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- ...power. '''(a)''' If you follow a diet of 2000 food calories per day (2000 kC), what is your average rate of energy consumption in watts (power input)? ( ...th>power = \frac{W}{\Delta t} = \frac{2000 kC}{day} \cdot \frac{4200 J}{1 kC} \cdot \frac{1 day}{24 h} \cdot \frac{1 h}{3600 s} = 97.2 watts </math> ...3 KB (521 words) - 10:52, 2 December 2015
- C(with dielectric) = kC ...4 KB (593 words) - 00:55, 6 December 2015
- ...power. '''(a)''' If you follow a diet of 2000 food calories per day (2000 kC), what is your average rate of energy consumption in watts (power input)? ( ...th>power = \frac{W}{\Delta t} = \frac{2000 kC}{day} \cdot \frac{4200 J}{1 kC} \cdot \frac{1 day}{24 h} \cdot \frac{1 h}{3600 s} = 97.2 J/s </math> ...10 KB (1,766 words) - 21:03, 18 April 2018
- ...and two Super Bowls in the two years given that he’s been gone. Winning in KC goes beyond the greatest player in the sport—although obtaining Patrick M ...6 KB (957 words) - 22:37, 29 March 2024