Impulse and Momentum - Revision history

Edwynbasa at 20:42, 27 April 2026

2026-04-27T20:42:30Z

Edwynbasa at 18:09, 27 April 2026

2026-04-27T18:09:23Z

← Older revision		Revision as of 14:09, 27 April 2026
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	<big><b>Edwyn Torres — Spring 2026</b></big>		<big><b>Edwyn Torres — Spring 2026</b></big>==Key Equations==

			<math>\vec{J} = \int \vec{F}_{net}dt</math>

			<math>\vec{J} = \vec{F}_{net,avg}\Delta t</math>

			<math>\Delta \vec{p} = \vec{J}</math>

			<math>\vec{p}_f = \vec{p}_i + \vec{F}_{net}\Delta t</math>

			<math>\vec{p} = m\vec{v}</math>

			Where:

			* <math>\vec{J}</math> = impulse
			* <math>\vec{F}_{net}</math> = net force
			* <math>\Delta t</math> = time interval
			* <math>\vec{p}</math> = momentum
			* <math>m</math> = mass
			* <math>\vec{v}</math> = velocity

Edwynbasa: Replaced content with "Edwyn Torres — Spring 2026"

2026-04-27T17:56:47Z

Replaced content with "<big><b>Edwyn Torres — Spring 2026</b></big>"

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YorickAndeweg: /* A Mathematical Model */

2019-08-03T19:05:50Z

A Mathematical Model

← Older revision		Revision as of 15:05, 3 August 2019
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	====Derivation====		====Derivation====

	The impulse-momentum theorem is a consequence of ~~the momentum principle~~ [[Newton's Second Law: the Momentum Principle\|the momentum principle]]. Below is its derivation:		The impulse-momentum theorem is a consequence of [[Newton's Second Law: the Momentum Principle\|the momentum principle]]. Below is its derivation:

	<math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math>		<math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math>

YorickAndeweg: /* Derivation */

2019-08-03T19:05:36Z

Derivation

← Older revision		Revision as of 15:05, 3 August 2019
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	====Derivation====		====Derivation====

	The impulse-momentum theorem is a consequence of the momentum principle ~~(see~~ [[Newton's Second Law: the Momentum Principle]]). Below is its derivation:		The impulse-momentum theorem is a consequence of the momentum principle [[Newton's Second Law: the Momentum Principle\|the momentum principle]]. Below is its derivation:

	<math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math>		<math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math>

YorickAndeweg: /* 6. (Difficult) */

2019-07-07T18:23:24Z

6. (Difficult)

← Older revision		Revision as of 14:23, 7 July 2019
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	What is the velocity of the particle at t=2?		What is the velocity of the particle at t=2?

			Solution:

	The net force acting on the particle can be found by adding the gravitational force and <math>\vec{F}</math>:		The net force acting on the particle can be found by adding the gravitational force and <math>\vec{F}</math>:

YorickAndeweg: /* 5. (Middling) */

2019-07-07T18:22:57Z

5. (Middling)

← Older revision		Revision as of 14:22, 7 July 2019
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	Here, we use kinematic equations to solve for average velocity!		Here, we use kinematic equations to solve for average velocity!

			[[File:Wiki_Image_1.png\|600px]]

	(b)		(b)
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	[[File:Wki Image 3.0.png\|600px]]		[[File:Wki Image 3.0.png\|600px]]

	~~[[File:Wiki_Image_1.png\|600px]]~~

	===6. (Difficult)===		===6. (Difficult)===

YorickAndeweg: /* 5. (Middling) */

2019-07-07T18:22:37Z

5. (Middling)

← Older revision		Revision as of 14:22, 7 July 2019
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	(b)		(b)

	[[File:Wiki_Image_2.0.png\|~~400px~~]]		[[File:Wiki_Image_2.0.png\|600px]]

	(c)		(c)

	[[File:Wki Image 3.0.png\|~~400px~~]]		[[File:Wki Image 3.0.png\|600px]]

	[[File:Wiki_Image_1.png\|~~400px~~]]		[[File:Wiki_Image_1.png\|600px]]

	===6. (Difficult)===		===6. (Difficult)===

YorickAndeweg: /* 5. (Middling) */

2019-07-07T18:21:50Z

5. (Middling)

← Older revision		Revision as of 14:21, 7 July 2019
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	(b)		(b)

	[[File:Wiki_Image_2.0.png]]		[[File:Wiki_Image_2.0.png\|400px]]

	(c)		(c)

	[[File:Wki Image 3.0.png]]		[[File:Wki Image 3.0.png\|400px]]

	[[File:Wiki_Image_1.png]]		[[File:Wiki_Image_1.png\|400px]]

	===6. (Difficult)===		===6. (Difficult)===

YorickAndeweg: /* Examples */

2019-07-07T18:21:24Z

Examples

← Older revision		Revision as of 14:21, 7 July 2019
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	A 2kg particle is travelling in the +y direction at 4m/s. After an impulse is applied to it, the particle is travelling in the +x direction at 3m/s. The impulse consisted of a force applied for .02s. What was the magnitude of the average force?		A 2kg particle is travelling in the +y direction at 4m/s. After an impulse is applied to it, the particle is travelling in the +x direction at 3m/s. The impulse consisted of a force applied for .02s. What was the magnitude of the average force?

			Solution:

	<math>\vec{J} = \Delta\vec{p} = \vec{p}_f - \vec{p}_i = <6, 0, 0> - <0, 8, 0> = <6, -8, 0>.</math> N*s		<math>\vec{J} = \Delta\vec{p} = \vec{p}_f - \vec{p}_i = <6, 0, 0> - <0, 8, 0> = <6, -8, 0>.</math> N*s
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	* If a rock's initial position just as it leaves your hand is <0,1.2,0>m, find the vector position of the ball after 0.25 seconds.		* If a rock's initial position just as it leaves your hand is <0,1.2,0>m, find the vector position of the ball after 0.25 seconds.

			Solution:

	* Initial Momentum?		* Initial Momentum?
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	(a) What is the average speed of the truck during the collision (that is, during the interval between first contact with the wall and coming to a stop)?		(a) What is the average speed of the truck during the collision (that is, during the interval between first contact with the wall and coming to a stop)?

	~~Here~~, ~~we use kinematic equations~~ to ~~solve for average velocity!~~		(b) About how long does the collision last? (That is, how long is the interval between first contact with the wall and coming to a stop?)

			(c) What is the magnitude of the average force exerted by the wall on the truck during the collision?

	~~[[File:Wiki_Image_1.png]]~~		(a)

			Here, we use kinematic equations to solve for average velocity!

	(b) ~~About how long does the collision last? (That is, how long is the interval between first contact with the wall and coming to a stop?)~~		(b)


	[[File:Wiki_Image_2.0.png]]		[[File:Wiki_Image_2.0.png]]

			(c)

			[[File:Wki Image 3.0.png]]

	~~(c) What is the magnitude of the average force exerted by the wall on the truck during the collision?~~		[[File:Wiki_Image_1.png]]

	[[File:~~Wki Image 3.0~~.png]]

	===6. (Difficult)===		===6. (Difficult)===