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This page is all about the [[Electric Field]] due to a Point Charge.'''CLAIMED BY Sindhu Kannappan 11-22-2018 (Fall 2018)'''
Claimed by Gabriel Cruz Fall 2025


This page is all about the [[Electric Field]] due to a Point Charge.




==The Main Idea==
A point charge refers to any particle that has a significantly small radius relative to the distance between it and any observation point of interest. This allows the generalization that all of the particle's charge and mass are localized at a specific point in space. The two known elementary charges are the proton and electron, both of which are modeled as point charges. A single proton holds a charge of +e (1.6e-19C), while an electron holds a charge of -e (-1.6e-19C). Like point charges, such as two positive or two negative charges, repel one another; opposite charges are attracted to one another. This pattern of attraction and repulsion is shown below.


[[File:Phys 1.png|800px]]
==The Main Ideas ==
(Ch 13.1 in ''Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood'')


Every charge creates its own electric field. As shown below, the electric field of a positive point charge points radially outward and that of a negative point charge points radially inward.  
'''Point Charge / Particle''' — an object whose radius is extremely small compared to the distances to other objects in the system. Because it is so small, all of its charge and mass can be treated as if they are concentrated at a single point.


[[File:Point_charge.GIF|600px]]
* Electrons and protons are always treated as point particles unless stated otherwise.
 
<u>Two types of point charges:</u> 
* **Protons ( +e )** → positive point charges, <math>q = +1.6\times10^{-19}\text{ C}</math> 
* **Electrons ( –e )** → negative point charges, <math>q = -1.6\times10^{-19}\text{ C}</math>
 
''Like'' point charges '''repel'''; ''opposite'' point charges '''attract'''.
 
<table border>
  <tr>
    <th>Point Charges</th>
    <th>Result</th>
    <th>Diagram</th>
  </tr>
  <tr>
    <td>1 proton, 1 electron</td>
    <td>Attract</td>
    <td>[[File:Proton_electron_attraction.png]]</td>
  </tr>
  <tr>
    <td>2 protons</td>
    <td>Repel</td>
    <td>[[File:Proton_repulsion.png]]</td>
  </tr>
  <tr>
    <td>2 electrons</td>
    <td>Repel</td>
    <td>[[File:Electron_repulsion.png]]</td>
  </tr>
</table border>
 
 
===The Electric Field===
(Ch 13.3 in ''Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood'')
 
The electric field describes how a source charge influences the space around it. This field exists everywhere, even if no other charges are present to experience a force. The electric field allows interactions to occur at a distance.
 
It is important to note that **electric field is not the same as electric force**.
 
Electric Force due to an Electric Field:
 
<math>\vec{F} = q\vec{E}</math>
 
* **F** = force on the particle 
* **E** = electric field at the observation location 
* **q** = charge of the particle (assume <math>1.6\times10^{-19}\text{ C}</math> unless stated otherwise)
 
The electric field becomes weaker as the distance from the point charge increases.
 
<table border>
  <tr>
    <td>The electric field of a positive point charge points radially outward.</td>
    <td>The electric field of a negative point charge points radially inward.</td>
  </tr>
  <tr>
    <td>[[File:Proton_electric_field.png]]</td>
    <td>[[File:Electron_electric_field.png]]</td>
  </tr>
</table border>


The field is calculated using Coulomb's Law. Indeed, the electric field is defined as a vector field that associates each point in space with the electric force that an infinitesimal test charge would experience. The source of the electric field in this article is the point charge.


===A Mathematical Model===
===A Mathematical Model===


====Coulomb Force Law for Point Charges====
====Electric Field Due to a Point Charge====
(Ch 13.4 in ''Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood'')
 
The magnitude of the electric field decreases with increasing distance from the point charge. This is described by:
 
<math>\vec{E} = \frac{1}{4\pi\epsilon_0}\frac{q}{|\vec{r}|^2}\hat{r}</math>  (Newtons/Coulomb)
 
* <math>\frac{1}{4\pi\epsilon_0}</math> is Coulomb’s constant, approximately <math>8.987\times10^{9}\frac{N\,m^2}{C^2}</math> 
* **q** = charge of the source particle 
* **r** = distance from source location to observation location 
* <math>\hat{r}</math> = unit vector pointing from the source to the observation point 


This law defines the electrical force of attraction or repulsion between two given point charges. The following formula describes the magnitude of this force:
'''Reminder:''' <math>\hat{r}</math> always points from the source charge to the observation location.


<math>\mid\vec F\mid=\frac{1}{4 \pi \epsilon_0 } \frac{\mid Q_1Q_2 \mid}{r^2}</math>
The direction of the electric field depends on the sign of the source charge:


====Electric Field due to Point Charge====
* If the source charge is positive → field points away (same direction as <math>\hat{r}</math>) 
* If the source charge is negative → field points toward the charge (opposite <math>\hat{r}</math>)


The Electric Field of a Point Charge can be found by using the following formula:
<math>\vec E=\frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} \hat r</math>


Which is derived from [[Gauss's Law]], modelling the point charge as a sphere.
====Coulomb Force Law for Point Charges====
(Ch 13.2 in ''Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood'')


<math>{\epsilon_0} </math>  is a constant representing vacuum permittivity, the permittivity of free space, or the electric constant, and is approximately <math>8.854*10^{-12}\frac{C^2}{N m^2}</math>
<math>|\vec{F}| = \frac{1}{4\pi\epsilon_0}\frac{|Q_1 Q_2|}{r^2}</math>


<math>\frac{1}{4 \pi \epsilon_0 } </math> is known as Coulomb's Constant and is approximately <math>8.987*10^{9}\frac{N m^2}{C^2} </math>
Coulomb’s Law describes the magnitude of the electric force between two point charges.


'''''r''''' is the magnitude of the distance between the observation location and the source location
The full vector form is:
, '''''q''''' is the charge of the particle
and <math>\hat r </math> is the unit vector in the direction of the distance from the source location to the observation point.


The force on a given test charge is governed by <math> F = Eq </math> where '''''E''''' is the electric field and '''''q''''' is the charge of a test charge in Coulombs. This can be represented by Coulomb's Law:
<math>\vec{F} = \frac{1}{4\pi\epsilon_0}\frac{Q_1 Q_2}{r^2}\hat{r}</math>


<math> F = \frac{1}{4 \pi \epsilon_0 } \frac{q_1 q_2}{r^2} \hat r </math>
* <math>Q_1, Q_2</math> = the charges 
* **r** = the distance between the two charges 
* <math>\frac{1}{4\pi\epsilon_0}</math> = Coulomb’s constant 


By solving for the electric field in <math> F = Eq </math> modeled as Coulomb's Law, one obtains the equation for the electric field of the point charge:


<math> E = \frac{F}{q_2} = \frac{1}{4 \pi \epsilon_0 } \frac{q_1}{r^2} \hat r </math>
====Connection Between Electric Field and Force====


The force on a test charge is given by <math>F = Eq</math>.


Substituting Coulomb’s Law for **F**:


<math> E = \frac{F}{q_2} = \frac{1}{4\pi\epsilon_0}\frac{q_1}{r^2}\hat{r} </math>


The similarity of the Coulomb force law and electric field equation comes from the fact that the electric field is the force per unit test charge:


<math>\vec{E} = \frac{\vec{F}}{q_{test}}</math>
Direction rules:
* If the source charge is positive → force and field point away from the charge 
* If the source charge is negative → force and field point toward the charge 


===A Computational Model===


Below is a link to some code which can help visualize the Electric Field due to a proton.
====Electric Field Superposition (Point Charges)====


When multiple point charges are present, the **net electric field** is the vector sum of the electric field from each charge:


https://trinket.io/glowscript/725d552305
<math>\vec{E}_{net} = \sum \vec{E}_i</math>


Notice how the arrows grow by a factor of <math> \frac{1}{r^{2}} </math> as the observation location gets closer to the proton.
This is due to the principle of **superposition**: the total effect is the sum of individual effects.


==Examples==
Important reminders:


* A charge does not exert a force on itself 
* Source charges are assumed not to move (so <math>\vec{F}_{net} = 0</math>) 


===Simple===
[[File:IMG_1DCC0A11C7B8-1.jpeg]]
There is an electron at the origin. Calculate the electric field at (4,-3,1)m.  


'''Step 1:''' Find <math>\hat r</math>
===A Computational Model===


Find <math>\vec r_{obs} - \vec r_{electron}   ((4,-3,1) - (0,0,0) = <4,-3,1> </math>m
Below is a simulation showing the electric field at various observation locations around a proton. The arrows decrease in size according to <math>\frac{1}{r^{2}}</math>, showing how the electric field weakens with distance.


Calculate the magnitude of <math>\vec r</math>. (<math>\sqrt{4^2+(-3)^2+1^2}=\sqrt{26}</math>
[[File:First code.gif]]


From <math>\vec r</math>, find the unit vector <math>\hat{r}.</math> <math>  <\frac{4}{\sqrt{26}},\frac{-3}{\sqrt{26}},\frac{1}{\sqrt{26}}> </math>
Two adjacent point charges of opposite sign form an electric dipole. The electric field points toward the negative charge (blue) and away from the positive charge (red).


'''Step 2:''' Find the magnitude of the Electric Field
[[File:Code_2.png]]


<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} = \frac{1}{4 \pi \epsilon_0 } \frac{-1.6 * 10^{-19}}{26} </math>
===A Computational Model 2 ===


'''Step 3:''' Multiply the magnitude of the Electric Field by <math>\hat{r}</math> to find the Electric Field
[https://trinket.io/glowscript/650fbf3a95c5 Click this link to see another computional model.]


<math>E = \frac{1}{4 \pi \epsilon_0 } \frac{-1.6 * 10^{-19}}{26}*<\frac{4}{\sqrt{26}},\frac{-3}{\sqrt{26}},\frac{1}{\sqrt{26}}> = <-4.34*10^{-11},3.26*10^{-11},-1.09*10^{-11}>  N/C    </math>
==Examples==


===Simple===
There is an electron at the origin. Calculate the electric field at <4, -3, 1> m.


[[File:Screenshot_2024-04-13_160839.png]]


===Middling===
===Middling===
A particle of unknown charge is located at (-0.21, 0.02, 0.11) m. Its electric field at point (-0.02, 0.31, 0.28) m is <math><0.124, 0.188, 0.109> </math> N/C. Find the magnitude and sign of the particle's charge.
A particle of unknown charge is located at <-0.21, 0.02, 0.11> m. Its electric field at point <-0.02, 0.31, 0.28> m is <math><0.124, 0.188, 0.109> </math> N/C. Find the magnitude and sign of the particle's charge.
 
Given both an observation location and a source location, one can find both r and <math>\hat{r}</math>  Given the value of the electric field, one can also find the magnitude of the electric field. Then, using the equation for the magnitude of electric field of a point charge,<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math>  one can find the magnitude and sign of the charge.  


'''Step 1:'''
Given both an observation location and a source location, one can find both r and <math>\hat{r}</math>  Given the value of the electric field, one can also find the magnitude of the electric field. Then, using the equation for the magnitude of electric field of a point charge, <math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math> one can find the magnitude and sign of the charge.  
Find <math>\vec r_{obs} - \vec r_{particle} </math>.


<math>\vec r = (-0.02,0.31,0.28) m - (-0.21,0.02,0.11) m = <0.19,0.29,0.17> m </math>
<table border>
  <tr>
    <td> <b>Step 1.</b> Find <math>\vec r_{obs} - \vec r_{particle} </math>:


<math>\vec r = <-0.02, 0.31, 0.28> m - <-0.21, 0.02, 0.11> m = <0.19,0.29,0.17> m </math>


To find <math>\vec r_{mag} </math>, find the magnitude of <math><0.19,0.29,0.17></math>  
To find <math>\vec r_{mag} </math>, find the magnitude of <math><0.19,0.29,0.17></math>  


<math>\sqrt{0.19^2+0.29^2+0.17^2}=\sqrt{0.1491}= 0.39</math>  
<math>\sqrt{0.19^2+0.29^2+0.17^2}=\sqrt{0.1491}= 0.39</math>  
</td></tr>


 
    <tr><td><b>Step 2:</b> Find the magnitude of the Electric Field:
'''Step 2:''' Find the magnitude of the Electric Field  


<math>E= <0.124, 0.188, 0.109> N/C</math>  
<math>E= <0.124, 0.188, 0.109> N/C</math>  


<math>E_{mag} = (\sqrt{0.124^2+0.188^2+0.109^2}=\sqrt{0.0626}=0.25</math>  
<math>E_{mag} = (\sqrt{0.124^2+0.188^2+0.109^2}=\sqrt{0.0626}=0.25</math>  </td></tr>


 
    <td>'''Step 3:''' Find '''''q''''' by rearranging the equation for <math>E_{mag}</math>
'''Step 3:''' Find '''''q''''' by rearranging the equation for <math>E_{mag}</math>


<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math>
<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math>
Line 113: Line 191:
By rearranging this equation we get
By rearranging this equation we get


<math> q= {4 pi * epsilon_0 } *{r^2}*E_{mag} </math>  
<math> q= {4 \pi * \epsilon_0 } *{r^2}*E_{mag} </math>  


<math> q= {1/(9*10^9)} *{0.39^2}*0.25 </math>  
<math> q= {1/(9*10^9)} *{0.39^2}*0.25 </math>  


<math> q= + 4.3*10^{-12} C </math>  
<math> q= + 4.3*10^{-12} C </math></td>
 


</table border>


===Difficult===
===Difficult===
The electric force on a -2mC particle at a location (3.98 , 3.98 , 3.98) m due to a particle at the origin is <math>< -5.5*10^{3} , -5.5*10^{3}, -5.5*10^{3}></math> N. What is the charge on the particle at the origin?
The electric force on a -2 mC particle at location (3.98, 3.98, 3.98) m due to a particle at the origin is
 
<math>\langle -5.5\times10^{3},\, -5.5\times10^{3},\, -5.5\times10^{3}\rangle</math> N.
Given the force and charge on the particle, one can calculate the surrounding electric field. With this variable found, this problem becomes much like the last one.
What is the charge on the particle at the origin?
 


Given the force and the charge of the particle experiencing the force, we can first compute the electric field at the observation location. Once the electric field is known, we can use the point-charge electric field model to solve for the unknown source charge.


<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r_{mag}^2} </math>
<table border>
  <tr>
    <td>
<b>Step 1.</b> Find the electric field using <math>\vec{F} = q\vec{E}</math>.


to find the rmag value. To find <math>\hat r</math> we can find the direction of the electric field as that is obviously going to be in the same direction as  <math>\hat r</math>. Then, once we find  <math>\hat r</math>, all that is left to do is multiply <math>\hat r</math> by rmag and that will give us the  <math> r</math> vector. We can then find the location of the particle as we know  <math>r=r_{observation}-r_{particle}</math>
<math>\vec{E} = \frac{\vec{F}}{q}</math>


'''Step 1''':
<math> = \frac{\langle -5.5\times10^{3}, -5.5\times10^{3}, -5.5\times10^{3}\rangle}{-2\times10^{-3}}</math>
Find the magnitude of the Electric field.


<math> F = Eq </math>  
<math> = \langle 2.75\times10^{6},\, 2.75\times10^{6},\, 2.75\times10^{6}\rangle</math> N/C
    </td>
  </tr>


<math> <5.5*10^{3}, -7.6*10^{3}, 0> = E * -2mC </math>  
  <tr>
    <td>
<b>Step 2.</b> Compute <math>\vec{r}</math> from the particle at the origin to the observation location.


<math> E = \frac{< -5.5*10^{3} , -5.5*10^{3}, -5.5*10^{3}>}{-2mC} = <2.75*10^{6} , 2.75*10^{6} , 2.75*10^{6}> </math> N/C
<math>\vec{r} = \langle 3.98,\,3.98,\,3.98\rangle\ \text{m}</math>


Magnitude:


<math>|\vec{r}| = \sqrt{3.98^2 + 3.98^2 + 3.98^2}</math> 
<math>= \sqrt{47.52} \approx 6.89\ \text{m}</math>


'''Step 2:''':
Unit vector:
Find <math>\vec r_{obs} - \vec r_{particle} </math>.


<math>\vec r = (3.98 , 3.98 , 3.98) m - (0 , 0 , 0) m = <3.98 , 3.98 , 3.98> m </math>
<math>\hat{r} = \frac{\vec{r}}{|\vec{r}|}</math>
    </td>
  </tr>


  <tr>
    <td>
<b>Step 3.</b> Solve for the unknown charge using the point-charge field equation:


To find <math>\vec r_{mag} </math>, find the magnitude of <math><3.98 , 3.98 , 3.98></math>  
<math>E_{mag}=\frac{1}{4\pi\epsilon_0}\frac{|q|}{r^2}</math>


<math>\sqrt{3.98^2+3.98^2+3.98^2}=\sqrt{47.52}= 6.9</math>
Rearranged:


<math>|q| = (4\pi\epsilon_0)\,(r^2)\,E_{mag}</math>


'''Step 3:''' Find the magnitude of the Electric Field
Using <math>E_{mag} = 2.75\times10^{6}</math> N/C and <math>r = 6.89</math> m:


<math>E= <2.75*10^{6} , 2.75*10^{6} , 2.75*10^{6}> </math> N/C
<math>|q| = (8.99\times10^{-12})(6.89^2)(2.75\times10^{6})</math>


<math>E_{mag} = (\sqrt{(2.75*10^{6})^2+2.75*10^{6})^2+2.75*10^{6})^2}=\sqrt{2.27*10^{13}}=4.76*10^{6}</math>
<math>|q| \approx 0.237\ \text{C}</math>
 
 
'''Step 4:''' Find '''''q''''' by rearranging the equation for <math>E_{mag}</math>
 
<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math>


By rearranging this equation we get
Sign of the charge: 
The force on the negative test charge is **toward** the origin → the source must be **positive**.


<math> q= {4 pi * epsilon_0 } *{r^2}*E_{mag} </math>  
<b>Final Answer:</b> 
<math>q_{\text{origin}} \approx +0.24\ \text{C}</math>
    </td>
  </tr>
</table border>


<math> q= {1/(9*10^9)} *{6.9^{2}}*4.76*10^{6} </math>
====Common Mistakes====
* **Using the wrong sign for q.*
  Remember: if the force on a negative charge points toward the origin, the source must be positive.


<math> q= + 0.253 C </math>
* **Forgetting that E and F point the same direction only for positive test charges.** 
  Since the test charge is −2 mC, is opposite the force direction.


* **Mixing up <math>\vec{r}</math> and <math>|\vec{r}|</math>.** 
  One is a vector; the other is a scalar distance.


* **Failing to use the magnitude of E when solving for |q|.** 
  The field equation uses only magnitudes, not vector components.


* **Using an incorrect value of Coulomb’s constant.**


==Connectedness==
==Connectedness==
1.How is this topic connected to something that you are interested in?
''1. How is this topic connected to something that you are interested in?''


This topic is the most very basic aspect of physics relating to electricity and magnetism. As someone who is very interested in physics, this topic is important to understanding how more complex ideas that come in later on chapters work.
The topic is fascinating because electric fields not only exist within the human body but also in the realms of aerospace. It's captivating to think about the parallels between biological systems and aerospace systems, where electric field management is crucial for functions such as propulsion and navigation. Analyzing how bodies maintain and adapt their electric fields and applying this knowledge to aerospace engineering can lead to innovative approaches to energy management and system efficiency, particularly in the face of perturbations such as equipment failure or external environmental factors.


2.How is it connected to your major?
''2. How is it connected to your major?''


As a mechanical engineer, static charges don't relate to what I do all that much, but the vector algebra certainly does.
As an aerospace engineer, my interest lies in the application of principles from various sciences, including biochemistry, to improve and innovate within the field of aviation and space exploration. Understanding the role of electric fields in cellular behavior provides insights into potential analogs in aerospace technology. For instance, similar to how cells adjust their electric fields for optimal function, aerospace systems must regulate their onboard electric fields for navigation, communication, and operational efficiency. Such interdisciplinary knowledge can be the foundation for advancements in aerospace materials and systems that are responsive and adaptive to their environments.  


3.Is there an interesting industrial application?
''3. Is there an interesting industrial application?''
 
The electric field of a point particle and the [[Superposition Principle]] are integral in understanding the interactions of many charges in various situations, such as a charged sphere or rod. Understanding the way charges behave is important in working with electricity.


PEMF (Pulsed Electromagnetic Field) therapy's principle of restoring optimal voltage in damaged cells through electromagnetic fields has interesting parallels in aerospace engineering. For example, the management of electromagnetic fields is critical in spacecraft and aircraft to protect onboard electronics and enhance communication signals. The concept of PEMF can inspire the development of systems that can self-regulate and optimize electrical potential across different components of an aircraft or spacecraft, thereby enhancing performance and resilience. Such systems could prove vital in long-duration space missions, where human intervention is limited, and the machine's ability to self-heal and maintain operational integrity can be a game-changer.


==History==
==History==
Line 196: Line 295:
Charles de Coulomb was born in June 14, 1736 in central France. He spent much of his early life in the military and was placed in regions throughout the world. He only began to do scientific experiments out of curiously on his military expeditions. However, when controversy arrived with him and the French bureaucracy coupled with the French Revolution, Coulomb had to leave France and thus really began his scientific career.  
Charles de Coulomb was born in June 14, 1736 in central France. He spent much of his early life in the military and was placed in regions throughout the world. He only began to do scientific experiments out of curiously on his military expeditions. However, when controversy arrived with him and the French bureaucracy coupled with the French Revolution, Coulomb had to leave France and thus really began his scientific career.  


Between 1785 and 1791, de Coulomb wrote several key papers centered around multiple relations of electricity and magnetism. This helped him develop the principle known as Coulomb's Law, which confirmed that the force between two electrical charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. This is the same relationship that is seen in the electric field equation of a point charge.  
Between 1785 and 1791, de Coulomb wrote several key papers centered around multiple relations of electricity and magnetism. This helped him develop the principle known as Coulomb's Law, which confirmed that the force between two electrical charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. This is the same relationship that is seen in the electric field equation of a point charge.
 
[[File:Benjamin-Franklin-Portrait.png]]
''Benjamin Franklin''
 
Benjamin Franklin (1706–1790) made several foundational contributions to the early understanding of electric charge. Although he did not write mathematical laws like Coulomb, his ideas directly shaped the concepts used in point-charge physics.
 
Franklin introduced the naming system of positive and negative charge, which is still used today. He proposed that charge behaves like a conserved quantity that can move between objects—an essential idea behind treating charges as isolated point charges located at specific positions in space.


== See also ==
== See also ==
Line 215: Line 321:
===External links===
===External links===


Some more information : http://hyperphysics.phy-astr.gsu.edu/hbase/electric/epoint.html
Some more information:


http://www.physics.umd.edu/courses/Phys260/agashe/S10/notes/lecture18.pdf
*http://www.physics.umd.edu/courses/Phys260/agashe/S10/notes/lecture18.pdf
*https://www.reliantphysicaltherapy.com/services/pulsed-electromagnetic-field-pemf
*https://www.youtube.com/watch?v=HG9KxDZ-qwI&t=1s
*https://www.youtube.com/watch?v=8GJf-Fj-qoI&t=3s


==References==
==References==

Latest revision as of 22:59, 23 November 2025

Claimed by Gabriel Cruz Fall 2025

This page is all about the Electric Field due to a Point Charge.


The Main Ideas

(Ch 13.1 in Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood)

Point Charge / Particle — an object whose radius is extremely small compared to the distances to other objects in the system. Because it is so small, all of its charge and mass can be treated as if they are concentrated at a single point.

  • Electrons and protons are always treated as point particles unless stated otherwise.

Two types of point charges:

  • **Protons ( +e )** → positive point charges, [math]\displaystyle{ q = +1.6\times10^{-19}\text{ C} }[/math]
  • **Electrons ( –e )** → negative point charges, [math]\displaystyle{ q = -1.6\times10^{-19}\text{ C} }[/math]

Like point charges repel; opposite point charges attract.

Point Charges Result Diagram
1 proton, 1 electron Attract
2 protons Repel
2 electrons Repel


The Electric Field

(Ch 13.3 in Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood)

The electric field describes how a source charge influences the space around it. This field exists everywhere, even if no other charges are present to experience a force. The electric field allows interactions to occur at a distance.

It is important to note that **electric field is not the same as electric force**.

Electric Force due to an Electric Field:

[math]\displaystyle{ \vec{F} = q\vec{E} }[/math]

  • **F** = force on the particle
  • **E** = electric field at the observation location
  • **q** = charge of the particle (assume [math]\displaystyle{ 1.6\times10^{-19}\text{ C} }[/math] unless stated otherwise)

The electric field becomes weaker as the distance from the point charge increases.

The electric field of a positive point charge points radially outward. The electric field of a negative point charge points radially inward.


A Mathematical Model

Electric Field Due to a Point Charge

(Ch 13.4 in Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood)

The magnitude of the electric field decreases with increasing distance from the point charge. This is described by:

[math]\displaystyle{ \vec{E} = \frac{1}{4\pi\epsilon_0}\frac{q}{|\vec{r}|^2}\hat{r} }[/math] (Newtons/Coulomb)

  • [math]\displaystyle{ \frac{1}{4\pi\epsilon_0} }[/math] is Coulomb’s constant, approximately [math]\displaystyle{ 8.987\times10^{9}\frac{N\,m^2}{C^2} }[/math]
  • **q** = charge of the source particle
  • **r** = distance from source location to observation location
  • [math]\displaystyle{ \hat{r} }[/math] = unit vector pointing from the source to the observation point

Reminder: [math]\displaystyle{ \hat{r} }[/math] always points from the source charge to the observation location.

The direction of the electric field depends on the sign of the source charge:

  • If the source charge is positive → field points away (same direction as [math]\displaystyle{ \hat{r} }[/math])
  • If the source charge is negative → field points toward the charge (opposite [math]\displaystyle{ \hat{r} }[/math])


Coulomb Force Law for Point Charges

(Ch 13.2 in Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood)

[math]\displaystyle{ |\vec{F}| = \frac{1}{4\pi\epsilon_0}\frac{|Q_1 Q_2|}{r^2} }[/math]

Coulomb’s Law describes the magnitude of the electric force between two point charges.

The full vector form is:

[math]\displaystyle{ \vec{F} = \frac{1}{4\pi\epsilon_0}\frac{Q_1 Q_2}{r^2}\hat{r} }[/math]

  • [math]\displaystyle{ Q_1, Q_2 }[/math] = the charges
  • **r** = the distance between the two charges
  • [math]\displaystyle{ \frac{1}{4\pi\epsilon_0} }[/math] = Coulomb’s constant


Connection Between Electric Field and Force

The force on a test charge is given by [math]\displaystyle{ F = Eq }[/math].

Substituting Coulomb’s Law for **F**:

[math]\displaystyle{ E = \frac{F}{q_2} = \frac{1}{4\pi\epsilon_0}\frac{q_1}{r^2}\hat{r} }[/math]

The similarity of the Coulomb force law and electric field equation comes from the fact that the electric field is the force per unit test charge:

[math]\displaystyle{ \vec{E} = \frac{\vec{F}}{q_{test}} }[/math]

Direction rules:

  • If the source charge is positive → force and field point away from the charge
  • If the source charge is negative → force and field point toward the charge


Electric Field Superposition (Point Charges)

When multiple point charges are present, the **net electric field** is the vector sum of the electric field from each charge:

[math]\displaystyle{ \vec{E}_{net} = \sum \vec{E}_i }[/math]

This is due to the principle of **superposition**: the total effect is the sum of individual effects.

Important reminders:

  • A charge does not exert a force on itself
  • Source charges are assumed not to move (so [math]\displaystyle{ \vec{F}_{net} = 0 }[/math])

A Computational Model

Below is a simulation showing the electric field at various observation locations around a proton. The arrows decrease in size according to [math]\displaystyle{ \frac{1}{r^{2}} }[/math], showing how the electric field weakens with distance.

Two adjacent point charges of opposite sign form an electric dipole. The electric field points toward the negative charge (blue) and away from the positive charge (red).

A Computational Model 2

Click this link to see another computional model.

Examples

Simple

There is an electron at the origin. Calculate the electric field at <4, -3, 1> m.

Middling

A particle of unknown charge is located at <-0.21, 0.02, 0.11> m. Its electric field at point <-0.02, 0.31, 0.28> m is [math]\displaystyle{ \lt 0.124, 0.188, 0.109\gt }[/math] N/C. Find the magnitude and sign of the particle's charge.

Given both an observation location and a source location, one can find both r and [math]\displaystyle{ \hat{r} }[/math] Given the value of the electric field, one can also find the magnitude of the electric field. Then, using the equation for the magnitude of electric field of a point charge, [math]\displaystyle{ E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} }[/math] one can find the magnitude and sign of the charge.

Step 1. Find [math]\displaystyle{ \vec r_{obs} - \vec r_{particle} }[/math]:

[math]\displaystyle{ \vec r = \lt -0.02, 0.31, 0.28\gt m - \lt -0.21, 0.02, 0.11\gt m = \lt 0.19,0.29,0.17\gt m }[/math]

To find [math]\displaystyle{ \vec r_{mag} }[/math], find the magnitude of [math]\displaystyle{ \lt 0.19,0.29,0.17\gt }[/math]

[math]\displaystyle{ \sqrt{0.19^2+0.29^2+0.17^2}=\sqrt{0.1491}= 0.39 }[/math]

Step 2: Find the magnitude of the Electric Field:

[math]\displaystyle{ E= \lt 0.124, 0.188, 0.109\gt N/C }[/math]

[math]\displaystyle{ E_{mag} = (\sqrt{0.124^2+0.188^2+0.109^2}=\sqrt{0.0626}=0.25 }[/math]
Step 3: Find q by rearranging the equation for [math]\displaystyle{ E_{mag} }[/math]

[math]\displaystyle{ E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} }[/math]

By rearranging this equation we get

[math]\displaystyle{ q= {4 \pi * \epsilon_0 } *{r^2}*E_{mag} }[/math]

[math]\displaystyle{ q= {1/(9*10^9)} *{0.39^2}*0.25 }[/math]

[math]\displaystyle{ q= + 4.3*10^{-12} C }[/math]

Difficult

The electric force on a -2 mC particle at location (3.98, 3.98, 3.98) m due to a particle at the origin is [math]\displaystyle{ \langle -5.5\times10^{3},\, -5.5\times10^{3},\, -5.5\times10^{3}\rangle }[/math] N. What is the charge on the particle at the origin?

Given the force and the charge of the particle experiencing the force, we can first compute the electric field at the observation location. Once the electric field is known, we can use the point-charge electric field model to solve for the unknown source charge.

Step 1. Find the electric field using [math]\displaystyle{ \vec{F} = q\vec{E} }[/math].

[math]\displaystyle{ \vec{E} = \frac{\vec{F}}{q} }[/math]

[math]\displaystyle{ = \frac{\langle -5.5\times10^{3}, -5.5\times10^{3}, -5.5\times10^{3}\rangle}{-2\times10^{-3}} }[/math]

[math]\displaystyle{ = \langle 2.75\times10^{6},\, 2.75\times10^{6},\, 2.75\times10^{6}\rangle }[/math] N/C

Step 2. Compute [math]\displaystyle{ \vec{r} }[/math] from the particle at the origin to the observation location.

[math]\displaystyle{ \vec{r} = \langle 3.98,\,3.98,\,3.98\rangle\ \text{m} }[/math]

Magnitude:

[math]\displaystyle{ |\vec{r}| = \sqrt{3.98^2 + 3.98^2 + 3.98^2} }[/math] [math]\displaystyle{ = \sqrt{47.52} \approx 6.89\ \text{m} }[/math]

Unit vector:

[math]\displaystyle{ \hat{r} = \frac{\vec{r}}{|\vec{r}|} }[/math]

Step 3. Solve for the unknown charge using the point-charge field equation:

[math]\displaystyle{ E_{mag}=\frac{1}{4\pi\epsilon_0}\frac{|q|}{r^2} }[/math]

Rearranged:

[math]\displaystyle{ |q| = (4\pi\epsilon_0)\,(r^2)\,E_{mag} }[/math]

Using [math]\displaystyle{ E_{mag} = 2.75\times10^{6} }[/math] N/C and [math]\displaystyle{ r = 6.89 }[/math] m:

[math]\displaystyle{ |q| = (8.99\times10^{-12})(6.89^2)(2.75\times10^{6}) }[/math]

[math]\displaystyle{ |q| \approx 0.237\ \text{C} }[/math]

Sign of the charge: The force on the negative test charge is **toward** the origin → the source must be **positive**.

Final Answer: [math]\displaystyle{ q_{\text{origin}} \approx +0.24\ \text{C} }[/math]

Common Mistakes

  • **Using the wrong sign for q.**
 Remember: if the force on a negative charge points toward the origin, the source must be positive.
  • **Forgetting that E and F point the same direction only for positive test charges.**
 Since the test charge is −2 mC, is opposite the force direction.
  • **Mixing up [math]\displaystyle{ \vec{r} }[/math] and [math]\displaystyle{ |\vec{r}| }[/math].**
 One is a vector; the other is a scalar distance.
  • **Failing to use the magnitude of E when solving for |q|.**
 The field equation uses only magnitudes, not vector components.
  • **Using an incorrect value of Coulomb’s constant.**

Connectedness

1. How is this topic connected to something that you are interested in?

The topic is fascinating because electric fields not only exist within the human body but also in the realms of aerospace. It's captivating to think about the parallels between biological systems and aerospace systems, where electric field management is crucial for functions such as propulsion and navigation. Analyzing how bodies maintain and adapt their electric fields and applying this knowledge to aerospace engineering can lead to innovative approaches to energy management and system efficiency, particularly in the face of perturbations such as equipment failure or external environmental factors.

2. How is it connected to your major?

As an aerospace engineer, my interest lies in the application of principles from various sciences, including biochemistry, to improve and innovate within the field of aviation and space exploration. Understanding the role of electric fields in cellular behavior provides insights into potential analogs in aerospace technology. For instance, similar to how cells adjust their electric fields for optimal function, aerospace systems must regulate their onboard electric fields for navigation, communication, and operational efficiency. Such interdisciplinary knowledge can be the foundation for advancements in aerospace materials and systems that are responsive and adaptive to their environments.

3. Is there an interesting industrial application?

PEMF (Pulsed Electromagnetic Field) therapy's principle of restoring optimal voltage in damaged cells through electromagnetic fields has interesting parallels in aerospace engineering. For example, the management of electromagnetic fields is critical in spacecraft and aircraft to protect onboard electronics and enhance communication signals. The concept of PEMF can inspire the development of systems that can self-regulate and optimize electrical potential across different components of an aircraft or spacecraft, thereby enhancing performance and resilience. Such systems could prove vital in long-duration space missions, where human intervention is limited, and the machine's ability to self-heal and maintain operational integrity can be a game-changer.

History

Charles de Coulomb

Charles de Coulomb was born in June 14, 1736 in central France. He spent much of his early life in the military and was placed in regions throughout the world. He only began to do scientific experiments out of curiously on his military expeditions. However, when controversy arrived with him and the French bureaucracy coupled with the French Revolution, Coulomb had to leave France and thus really began his scientific career.

Between 1785 and 1791, de Coulomb wrote several key papers centered around multiple relations of electricity and magnetism. This helped him develop the principle known as Coulomb's Law, which confirmed that the force between two electrical charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. This is the same relationship that is seen in the electric field equation of a point charge.

Benjamin Franklin

Benjamin Franklin (1706–1790) made several foundational contributions to the early understanding of electric charge. Although he did not write mathematical laws like Coulomb, his ideas directly shaped the concepts used in point-charge physics.

Franklin introduced the naming system of positive and negative charge, which is still used today. He proposed that charge behaves like a conserved quantity that can move between objects—an essential idea behind treating charges as isolated point charges located at specific positions in space.

See also

Electric Field
Electric Force
Superposition Principle
Electric Dipole

Further reading

Principles of Electrodynamics by Melvin Schwartz ISBN: 9780486134673

Electricity and Magnetism: Edition 3 , Edward M. Purcell David J. Morin

External links

Some more information:

References

Chabay. (2000-2018). Matter & Interactions (4th ed.). John Wiley & Sons.

PY106 Notes. (n.d.). Retrieved November 27, 2016, from http://physics.bu.edu/~duffy/py106.html

Retrieved November 28, 2016, from http://www.biography.com/people/charles-de-coulomb-9259075#controversy-and-absolution