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(→‎Curly Electric Field: Modified image since the old version was very vague as to why the induced field was flipping. This one is clear about the direction and increasing/decreasing.)
 
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Claimed by Amber Akbar to edit (Spring 2016)
Claimed by Ananya Ghose Fall 2021


==Faraday's Law of Induction==
Note to editors: need a computational model


Faraday's law focuses on how a time-varying magnetic field produces a "curly" non-Coulombic electric field, thereby inducing an emf.  
Faraday's Law
focuses on how a time-varying magnetic field produces a "curly" non-Coulomb electric field, thereby inducing an emf.  


'''Faraday's Law''' summarizes the ways voltage can be generated as a result of a time-varying magnetic flux.  
==Faraday's Law==
Faraday's law is one of four laws in Maxwell's equations. It tells us that in the presence of a time-varying magnetic field or current (which induces a time-varying magnetic field), there is an emf with a magnitude equal to the change in magnetic flux. It serves as a succinct summary of the ways a voltage (or emf) may be generated by a changing magnetic environment. The induced emf in a coil is equal to the negative of the rate of change of magnetic flux times the number of turns in the coil. It involves the interaction of charge with magnetic field.
 
Faraday's Law summarizes the ways voltage can be generated as a result of a time-varying magnetic flux. And it gives a way to connect the magnetic and electric fields in a quantifiable way (will elaborate later). Faraday's law is one of four laws in Maxwell's equations. It tells us that in the presence of a time-varying magnetic field or current (which induces a time-varying magnetic field), there is an emf with a magnitude equal to the change in magnetic flux. It serves as a succinct summary of the ways a voltage (or emf) may be generated by a changing magnetic environment. The induced emf in a coil is equal to the negative of the rate of change of magnetic flux times the number of turns in the coil. It involves the interaction of charge with the magnetic field.
 
==Curly Electric Field==
 
[[File:Newcurly.png]]


===Faraday's Law Experiment ===


[[File:experiment.png]]
===Mathematical Model===


Faraday showed that no current is registered in the galvanometer when bar magnet is
'''Faraday's Law'''
stationary with respect to the loop. However, a current is induced in the loop when a
relative motion exists between the bar magnet and the loop. In particular, the
galvanometer deflects in one direction as the magnet approaches the loop, and the
opposite direction as it moves away.
Faraday’s experiment demonstrates that an electric current is induced in the loop by
changing the magnetic field. The coil behaves as if it were connected to an emf source.
Experimentally it is found that the induced emf depends on the rate of change of
magnetic flux through the coil.


emf = <math>{\frac{-d{{Phi}}_{mag}}{dt}}</math>


===Mathematical Equation===
where emf = <math>\oint\vec{E}_{NC}\bullet d\vec{l}</math> and <math>{{Phi}}_{mag}\equiv\int\vec{B}\bullet\hat{n}dA</math>


'''Faraday's Law Equation'''
[[File:Law.png]]


In other words: The emf along a round-trip is equal to the rate of change of the magnetic flux on the area encircled by the path.  
In other words: The emf along a round-trip is equal to the rate of change of the magnetic flux on the area encircled by the path.  
Line 36: Line 31:




'''Formal Version of Faraday's Law'''
[[File:FormalLaw.png]]


==Problem Solving Tips==
'''Formal Version of Faraday's Law'''
To find the direction of the curly electric field, one must find the direction of <math> \frac{-dB}{dt} </math>. Do this using the change in magnetic field as the basis of finding the <math> \frac{-dB}{dt} </math>.
 
<math>\oint\vec{E}_{NC}\bullet d\vec{l} = {\frac{-d}{dt}}\int\vec{B}\bullet\hat{n}dA</math>    (sign given by right-hand rule)
 
===Fiding the direction of the induced conventional current===
To find the direction of the induced conventional current by the change in the magnetic flux one must find the direction of the Non-Coulomb electric filed generated by the change in flux as the conventional current is the direction of the Non-Coulomb electric field.
To find the direction of the the Non-Coulomb Electic field, one must find the direction of <math> \frac{-dB}{dt} </math>. Do this using the change in magnetic field as the basis of finding the <math> \frac{-dB}{dt} </math>.


The easiest way to do this is to imagine the a vector for the initial magnetic field, and a vector for the final magnetic field. Then, draw the change in magnetic field vector, <math> \Delta \mathbf{B} </math>, and then the negative vector of that change in magnetic field gives <math> \frac{-dB}{dt} </math>:
As stated previously the negative sign in front of the change in magnetic flux in the Law is a representative of Lenz's law or in other words, it's there to remind us to apply Lenz's law. Lenz's law is basically there to make us abide by the law of conservation of energy. That said, thinking in terms of conservation of energy provides the simplest way to figure out the direction of the Non-Coulomb electric field.
The external magnetic field induces the Non-Coulomb electric field which drives the current which in turn creates a new magnetic field which we will call the induced magnetic field. This is the magnetic field whose direction we can deduce which in turn will help us find the direction of the current.
The easiest way to do this is to imagine a loop of wire with and an external magnetic field perpendicular to the surface of the plane of the loop. There is a change in magnetic flux generated by the change in the magnitude of the magnetic field. vector for the initial external magnetic field and a vector for the final magnetic field. Then, draw the change in magnetic field vector, <math> \Delta \mathbf{B} </math>, and then the negative vector of that change in magnetic field gives <math> \frac{-dB}{dt} </math>:


[[File:neg_change_B_dt.jpg]]
[[File:neg_change_B_dt.jpg]]
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Determine the sign of [[File:tips2.png]]
Determine the sign of [[File:tips2.png]]


3. The sign of the induced emf is the opposite of that of [[File:tips2.png]]. The direction of the  
3. The sign of the induced emf is the opposite of that of [[File:tips2.png]]. The direction of the
induced current can be found by using Lenz’s law or right hand rule (discussed previously).
induced current can be found by using Lenz’s law or right-hand rule (discussed previously).
 
==Computational Model==
The following simulations demonstrate Faraday's Law in action.
 


==More on Faraday's Law==
==More on Faraday's Law==
Line 79: Line 83:
Moving a magnet near a coil is not the only way to induce an emf in the coil. Another way to induce emf in a coil is to bring another coil with a steady current near the first coil, thereby changing the magnetic field (and flux) surrounding the first coil, inducing an emf and a current. Also, rotating a bar magnet (or coil) near a coil produces a time-varying magnetic field in the coil since rotating the magnet changes the magnetic field in the coil. The key to inducing the emf in the second coil is to change the magnetic field around it somehow, either by bringing an object that has its own magnetic field around that coil, or changing the current in that object, changing its magnetic field.
Moving a magnet near a coil is not the only way to induce an emf in the coil. Another way to induce emf in a coil is to bring another coil with a steady current near the first coil, thereby changing the magnetic field (and flux) surrounding the first coil, inducing an emf and a current. Also, rotating a bar magnet (or coil) near a coil produces a time-varying magnetic field in the coil since rotating the magnet changes the magnetic field in the coil. The key to inducing the emf in the second coil is to change the magnetic field around it somehow, either by bringing an object that has its own magnetic field around that coil, or changing the current in that object, changing its magnetic field.


Faraday's law can be used to calculate motional emf as well. A bar on two current-carrying rails connected by a resistor moves along the rails, using magnetic force to induce a current in the wire. There is a magnetic field going into the page. One way to calculate the motional emf is to use the [http://www.physicsbook.gatech.edu/Motional_Emf magnetic force], but an easier way is to use Faraday's law.  
Faraday's law can be used to calculate motional emf as well. A bar on two current-carrying rails connected by a resistor moves along the rails, using a magnetic force to induce a current in the wire. There is a magnetic field going into the page. One way to calculate the motional emf is to use the [http://www.physicsbook.gatech.edu/Motional_Emf magnetic force], but an easier way is to use Faraday's law.  


Faraday's law, using the change in magnetic flux, can be used to find the motional emf, where the changing factor in the magnetic flux is the area of the circuit as the bar moves, while magnetic field is kept constant.
Faraday's law, using the change in magnetic flux, can be used to find the motional emf, where the changing factor in the magnetic flux is the area of the circuit as the bar moves, while the magnetic field is kept constant.


[[File:motionalemf.jpg]]
[[File:motionalemf.jpg]]


==Conceptual Question ==
'''Falling Loop'''
A rectangular loop of wire with mass m, width w, vertical length l, and resistance R falls
out of a magnetic field under the influence of gravity. The magnetic field is uniform and out of the paper [[File:con3.png]] within the area shown and zero outside of that area. At the time shown in the sketch, the loop is exiting the magnetic field at speed [[File:con2.png]]
[[File:con1.png]]


1) What is the direction of the current flowing in the circuit at the time shown, clockwise
or counterclockwise? Why did you pick this direction?


2) Using Faraday's law, find an expression for the magnitude of the emf in this circuit in
terms of the quantities given. What is the magnitude of the current flowing in the circuit
at the time shown?
3) Besides gravity, what other force acts on the loop in the ±k direction? Give its
magnitude and direction in terms of the quantities given.
4) Assume that the loop has reached a “terminal velocity” and is no longer accelerating.
What is the magnitude of that terminal velocity in terms of given quantities?
5) Show that at terminal velocity, the rate at which gravity is doing work on the loop is
equal to the rate at which energy is being dissipated in the loop through Joule heating.


==Examples==
==Examples==
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[[File:solenoid.ring.jpg|center|alt=Diagram for simple example]]
[[File:solenoid.ring.jpg|center|alt=Diagram for simple example]]


''Taken from the'' Matter & Interactions ''textbook, variation of P12 (4th ed)''.
''Adapted from the'' Matter & Interactions ''textbook, variation of P12 (4th ed)''.


The solenoid radius is 4 cm and the ring radius is 20 cm. B = 0.8 T inside the solenoid and approximately 0 outside the solenoid. What is the magnetic flux through the outer ring?
The solenoid radius is 4 cm and the ring radius is 20 cm. B = 0.8 T inside the solenoid and approximately 0 outside the solenoid. What is the magnetic flux through the outer ring?
Line 132: Line 114:
===Middle===
===Middle===


[[File:2coils.jpg|center|alt=Diagram for simple example]]
[[File:rectanglecoilsolenoid.jpg|center|alt=Diagram for simple example]]
''Adapted from the'' Matter & Interactions ''textbook, variation of P27 (4th ed)''.
 
A very long, tightly wound solenoid has a circular cross-section of radius 2 cm (only a portion of the very long solenoid is shown). The magnetic field outside the solenoid is negligible. Throughout the inside of the solenoid the magnetic field ''B'' is uniform, to the left as shown, but varying with time ''t: B'' = (.06+.02<math>t^2</math>)T. Surrounding the circular solenoid is a loop of 7 turns of wire in the shape of a rectangle 6 cm by 12 cm. The total resistance of the 7-turn loop is 0.2 ohms.
 
(a) At ''t'' = 2 s, what is the direction of the current in the 7-turn loop? Explain briefly.
 
(b) At ''t'' = 2 s, what is the magnitude of the current in the 7-turn loop? Explain briefly.
 
''Solution''
 
'''(a)''' The direction of the current in the loop is clockwise.
 
'''(b)'''
 
B(t) = (.06+.02<math>t^2</math>)
 
A = (π)(0.02 m)^2 = .00126 <math>m^2</math>
 
<math>|{&epsilon;}| = AN\frac{dB(t)}{dt}</math>


''Taken from the'' Matter & Interactions ''textbook, variation of P25 (4th ed)''.
<math>|{&epsilon;}|</math> = (.00126 <math>m^2</math>)(7)<math>\frac{d(.06+.02t^2)}{dt}</math> = (.00882)(.02)(2t) = .0003528t


Two coils are aligned with their axes along the z axis, as shown above. Coil 1 is connected to a power supply and has a current flowing clockwise through coil 1, as seen from the location of coil 2. Coil 2 is connected to a voltmeter that gives an emf reading. The distance between the centers of the two coils is x = .12 m. Coil 1 has turns N1 = 500 and radius R1 = 0.05 m. The current through coil 1 changes with time: at t = 0 s, the current through coil 1 is I(0) = 5 A. At t = 0.3 s, the current through coil 1 I(0.3) = 2 A. Coil 2 has turns N2 = 200 and radius R2 = 0.02 m.
'''At ''t'' = 2 s:'''


(a) What is the direction of <math> \frac{-dB}{dt}</math>?
<math>|{&epsilon;}|</math> = .0003528(2) = .0007056 V


(b) What is the direction of the electric field inside the wire of coil 2, at the bottom coil 2?
<math>i = \frac{{&epsilon;}}{R}</math>


(c) At t = 0 seconds, what is the magnetic flux through one turn of coil 2?
<math>i = \frac{{.0007056 V}}{0.2 ohms}</math> = '''.00353 A'''


(d) At t = 0.3 seconds, what is the magnetic flux through one turn of coil 2?
===Difficult===


(e) What is the emf in one turn of coil 2 during this time interval?


(f) The voltmeter is connected across all turns of coil 2, so what is the reading on the voltmeter over this time interval?
[[File:difficultfaraday.png]]


(g) During this time interval, what is the magnitude of the non-Coulombic electric field inside the wire of coil 2?


''Solution:''
A square loop (dimensions L⇥L, total resistance R) is located halfway inside a region with uniform magnetic field B0. The magnitude of the magnetic field suddenly begins to increase linearly in time, eventually quadrupling in a time T.
 
'''(a) What current (magnitude and direction), if any, is induced in the loop at time T?
'''
 
<math> |emf| = \frac{-{&Phi;}_{B}}{&Delta;t} = \frac{A(B_f - B_i)}{T} = \frac{L^2(4B_o - B_o)}{T} = \frac{3B_oL^2}{T}</math>
 
emf = IR = <math>\frac{3B_oL^2}{TR}</math>
 
 
'''(b) What net force (magnitude and direction), if any, is induced on the loop at time T?
'''
 
<math> F_{top} </math> and <math> F_{bottom} </math> cancel out.
<math> F_{left} </math> = 0 because the left side is out of <math> \vec{B} </math> region.
 
<math> \vec{F}</math> = <math> \vec{F}_{right} </math> = I <math> \vec{L} \times \vec{B} = (ILB)[(\hat{y} \times - \hat{z} )] = \frac{3B_oL^2}{TR}(4B_o L)(- \hat{x}) = \frac{3{B_o}^2 L^3}{TR}(- \hat{x})</math>
 
 
'''(c) What net torque (magnitude and direction), if any, is induced on the loop at time T?
'''
 
<math> \vec{&tau;} = \vec{&mu;} \times \vec{B} = 0 </math> because <math>\vec{&mu;}</math> and <math>\vec{B}</math> are anti-parallel.


(a)Because current is decreasing with time, B1, the magnetic field in coil 1, is also decreasing. B1 points in the -z direction. The change in B therefore is +z, and <math> \frac{-dB}{dt}</math> points in the -z direction.
==Connectedness==


(b) Enc in coil 2 curls clockwise, when viewed from +z axis, so at the bottom of coil 2, Enc points in the -x direction.
Faraday's Law is one of Maxwell's equations which describe the essence of electric and magnetic fields. Maxwell's equations effectively summarize and connect all that we have learned throughout the course of Physics 2.


(c) All turns of coil 1 contribute to the magnetic field through coil 2.
As an electrical engineer, Faraday's Law is relevant to my major.


<math> \phi = BAcos(\theta)</math>


<math> = (\frac{\mu_0}{4\pi} \frac{2I_1A_1N_1}{(x^2 +R_1^2)^{3/2}}) A_2 </math>
== Faraday’s Law Applications ==
   
Physics 2 content has a lot of important concepts that we as engineers can use to make our jobs easier. Whether it be a direct application of a rule or some derivation of a rule. I know I personally struggle with a concept until I get a concrete real life application that I can see the material applied in. This section of the page will discuss how Faraday’s law is applied to concepts that you as students maybe more familiar with your day to day life.


<math> = \frac{\mu_0}{4\pi} \frac{2(5 A)\pi(0.05 m)^2 (500)}{((0.12 m)^2 +(0.05 m)^2)^{3/2}} * \pi(0.02 m)^2 </math>


<math> = 2.25 x 10^{-6} T*m^2 </math>
== Hydroelectric Generators ==
    Generators create energy by transforming mechanical motion into electrical energy, but hydroelectric generators use the power of falling water to turn a large turbine which is connected to a large magnet. Around this magnet is a large coil of tightly wound wire. The conceptual creation of electricity is the same as Faraday’s Law except alternating current is being produced, but the idea that a changing magnetic field in a coil of wire induces an electromotive force is still the same. The difference is the magnetic field changes sign and flips resulting in the same thing to occur in the induced EMF. Although the calculations here are slightly more difficult the concepts are the same.


(d) Since magnetic flux and I are proportional, and I decreases by a factor of (2/5), the magnetic flux also decreased by (2/5), so <math> \phi = 8.98 x 10^{-7} T*m^2 </math>.
== Transformers ==


(e) <math> |emf| = |\frac{d\phi}{dt}| = \frac{|8.98 x 10^{-7} T*m^2 - 2.25 x 10^{-6} T*m^2|}{0.3 s} </math>


<math> = 4.49 x 10^{-6} V </math>
Transformers use a similar concept for Faraday’s Law but it’s slightly different. The job of a transformer is to either step up or step down the voltage on the power line. Transformers have a constant magnetic field associated with it due to an iron core. The power supply voltage is adjusted by altering the number of turns of wire around the iron core which in turn alters the EMF of the electricity.  


(f) <math> \Delta V = N |emf|_{1 turn} </math>


<math> = 200(4.49 x 10^{-6} V) = 8.98 x 10^{-4} V
Cartoon of Hydroelectric Plant
https://etrical.files.wordpress.com/2009/12/hydrohow.jpg
Turbine Picture
http://theprepperpodcast.com/wp-content/uploads/2016/02/108-All-About-Hydro-Power-Generators-1054x500.jpg 
Transformer Diagram https://en.wikipedia.org/wiki/Transformer#/media/File:Transformer3d_col3.svg


==History==
==History==


Michael Faraday was an English physicist working in the early 1800's. He worked with another scientist named Sir Humphrey Davy. Faraday's big discovery happened in 1831 when he found that when you change a magnetic field, you can create an electric current. He did a lot of other work with electricity such as making generators and experimenting with electrochemistry and electrolysis.  
In 1831, eletromagnetic induction was discovered by Michael Faraday.


Faraday's experiments started with magnetic fields that stayed the same. That setup did not induce current. It was only when he started to change the magnetic fields that the current and voltage were induced (created). He discovered that the changes in the magnetic field and the size of the field were related to the amount of current created. Scientists also use the term magnetic flux. Magnetic flux is a value that is the strength of the magnetic field multiplied by the surface area of the device.
===Faraday's Law Experiment ===


== See also ==
[[File:experiment.png]]


To fully understand this topic, you need to have an understanding on Maxwell's equations and Lenz's Law.  
Faraday showed that no current is registered in the galvanometer when bar magnet is
===Further reading===
stationary with respect to the loop. However, a current is induced in the loop when a
relative motion exists between the bar magnet and the loop. In particular, the
galvanometer deflects in one direction as the magnet approaches the loop, and the
opposite direction as it moves away.
Faraday’s experiment demonstrates that an electric current is induced in the loop by
changing the magnetic field. The coil behaves as if it were connected to an emf source.
Experimentally it is found that the induced emf depends on the rate of change of
magnetic flux through the coil.
 
Test it out yourself [https://phet.colorado.edu/en/simulation/faradays-law here]
 
 
==See also==
===Further Readings===
 
''Matter and Interactions, Volume II: Electric and Magnetic Interactions, 4th Edition''
 
''The Electric Life of Michael Faraday'' (2009) by Alan Hirshfield
 
''Electromagnetic Induction Phenomena'' (2012) by D. Schieber
 
===External Links===
 
https://www.youtube.com/watch?v=KGTZPTnZBFE


Maxwell, James Clerk (1881), A treatise on electricity and magnetism, Vol. II, Chapter III, §530, p. 178. Oxford, UK: Clarendon Press. ISBN 0-486-60637-6.
https://www.nde-ed.org/EducationResources/HighSchool/Electricity/electroinduction.htm


Kohlrausch, Friedrich (2005), The Fundamental Laws of Electrolytic Conduction: Memoirs by Faraday, Hittorf and F. Kohlrausch. ISBN: 9781297986291
http://www.famousscientists.org/michael-faraday/
===External links===


Faraday's Law Video Explanation: https://www.youtube.com/watch?v=fJjVxR2fynk
http://www.bbc.co.uk/history/historic_figures/faraday_michael.shtml


Faraday's Law Simulation: https://phet.colorado.edu/en/simulation/faradays-law
==References==
==References==


Encyclopedia.com: http://www.encyclopedia.com/topic/Faradays_law.aspx
''Matter and Interactions, 4th Edition''
 
Wikipedia (Electromagnetic Induction): http://en.wikipedia.org/wiki/Electromagnetic_induction


Encyclopædia Britannica (Faraday's Law of Induction): http://www.britannica.com/EBchecked/topic/201744/Faradays-law-of-induction
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/farlaw.html


Motional EMF picture: http://web.mit.edu/8.02t/www/materials/StudyGuide/guide10.pdf
https://files.t-square.gatech.edu/access/content/group/gtc-970b-7c13-52a7-9627-cdc3154438c6/Test%20Preparation/Old%20Test/2212_Test4_Key-1.pdf


[[Category: Maxwell's equations]]
https://en.wikipedia.org/wiki/Faraday%27s_law_of_induction

Latest revision as of 21:53, 11 November 2023

Claimed by Ananya Ghose Fall 2021

Note to editors: need a computational model

Faraday's Law 

focuses on how a time-varying magnetic field produces a "curly" non-Coulomb electric field, thereby inducing an emf.

Faraday's Law

Faraday's Law summarizes the ways voltage can be generated as a result of a time-varying magnetic flux. And it gives a way to connect the magnetic and electric fields in a quantifiable way (will elaborate later). Faraday's law is one of four laws in Maxwell's equations. It tells us that in the presence of a time-varying magnetic field or current (which induces a time-varying magnetic field), there is an emf with a magnitude equal to the change in magnetic flux. It serves as a succinct summary of the ways a voltage (or emf) may be generated by a changing magnetic environment. The induced emf in a coil is equal to the negative of the rate of change of magnetic flux times the number of turns in the coil. It involves the interaction of charge with the magnetic field.

Curly Electric Field


Mathematical Model

Faraday's Law

emf = [math]\displaystyle{ {\frac{-d{{Phi}}_{mag}}{dt}} }[/math]

where emf = [math]\displaystyle{ \oint\vec{E}_{NC}\bullet d\vec{l} }[/math] and [math]\displaystyle{ {{Phi}}_{mag}\equiv\int\vec{B}\bullet\hat{n}dA }[/math]


In other words: The emf along a round-trip is equal to the rate of change of the magnetic flux on the area encircled by the path.

Direction: With the thumb of your right hand pointing in the direction of the -dB/dt, your fingers curl around in the direction of Enc.

The meaning of the minus sign: If the thumb of your right hand points in the direction of -dB/dt (that is, the opposite of the direction in which the magnetic field is increasing), your fingers curl around in the direction along which the path integral of electric field is positive. Similarly, the direction of the induced current can be explained using Lenz's Law. Lenz's law states that the induced current from the non-Coulombic electric field is induced in such a way that it produces a magnetic field that opposes the first magnetic field to keep the magnetic flux constant.


Formal Version of Faraday's Law

[math]\displaystyle{ \oint\vec{E}_{NC}\bullet d\vec{l} = {\frac{-d}{dt}}\int\vec{B}\bullet\hat{n}dA }[/math] (sign given by right-hand rule)

Fiding the direction of the induced conventional current

To find the direction of the induced conventional current by the change in the magnetic flux one must find the direction of the Non-Coulomb electric filed generated by the change in flux as the conventional current is the direction of the Non-Coulomb electric field. To find the direction of the the Non-Coulomb Electic field, one must find the direction of [math]\displaystyle{ \frac{-dB}{dt} }[/math]. Do this using the change in magnetic field as the basis of finding the [math]\displaystyle{ \frac{-dB}{dt} }[/math].

As stated previously the negative sign in front of the change in magnetic flux in the Law is a representative of Lenz's law or in other words, it's there to remind us to apply Lenz's law. Lenz's law is basically there to make us abide by the law of conservation of energy. That said, thinking in terms of conservation of energy provides the simplest way to figure out the direction of the Non-Coulomb electric field. The external magnetic field induces the Non-Coulomb electric field which drives the current which in turn creates a new magnetic field which we will call the induced magnetic field. This is the magnetic field whose direction we can deduce which in turn will help us find the direction of the current. The easiest way to do this is to imagine a loop of wire with and an external magnetic field perpendicular to the surface of the plane of the loop. There is a change in magnetic flux generated by the change in the magnitude of the magnetic field. vector for the initial external magnetic field and a vector for the final magnetic field. Then, draw the change in magnetic field vector, [math]\displaystyle{ \Delta \mathbf{B} }[/math], and then the negative vector of that change in magnetic field gives [math]\displaystyle{ \frac{-dB}{dt} }[/math]:

Pointing the thumb of your right hand in the direction of [math]\displaystyle{ \frac{-dB}{dt} }[/math] allows you to curl your fingers in the direction of [math]\displaystyle{ \mathbf{E_{NC}} }[/math].


In this chapter we have seen that a changing magnetic flux induces an emf:

according to Faraday’s law of induction. For a conductor which forms a closed loop, the emf sets up an induced current I =|ε|/R , where R is the resistance of the loop. To compute the induced current and its direction, we follow the procedure below:

1. For the closed loop of area on a plane, define an area vector A and let it point in the direction of your thumb, for the convenience of applying the right-hand rule later. Compute the magnetic flux through the loop using

Determine the sign of the magnetic flux

2. Evaluate the rate of change of magnetic flux . Keep in mind that the change could be caused by

Determine the sign of

3. The sign of the induced emf is the opposite of that of . The direction of the induced current can be found by using Lenz’s law or right-hand rule (discussed previously).

Computational Model

The following simulations demonstrate Faraday's Law in action.


More on Faraday's Law

Moving a magnet near a coil is not the only way to induce an emf in the coil. Another way to induce emf in a coil is to bring another coil with a steady current near the first coil, thereby changing the magnetic field (and flux) surrounding the first coil, inducing an emf and a current. Also, rotating a bar magnet (or coil) near a coil produces a time-varying magnetic field in the coil since rotating the magnet changes the magnetic field in the coil. The key to inducing the emf in the second coil is to change the magnetic field around it somehow, either by bringing an object that has its own magnetic field around that coil, or changing the current in that object, changing its magnetic field.

Faraday's law can be used to calculate motional emf as well. A bar on two current-carrying rails connected by a resistor moves along the rails, using a magnetic force to induce a current in the wire. There is a magnetic field going into the page. One way to calculate the motional emf is to use the magnetic force, but an easier way is to use Faraday's law.

Faraday's law, using the change in magnetic flux, can be used to find the motional emf, where the changing factor in the magnetic flux is the area of the circuit as the bar moves, while the magnetic field is kept constant.



Examples

Simple

Diagram for simple example

Adapted from the Matter & Interactions textbook, variation of P12 (4th ed).

The solenoid radius is 4 cm and the ring radius is 20 cm. B = 0.8 T inside the solenoid and approximately 0 outside the solenoid. What is the magnetic flux through the outer ring?

Solution:

Because the magnetic field outside the solenoid is 0, there is no flux between the ring and solenoid. So the flux in the ring is due to the area of the solenoid, so we use the area of the solenoid to find the flux through the outer ring rather than the area of the ring itself:

[math]\displaystyle{ \phi = BAcos(\theta) }[/math]

[math]\displaystyle{ = (0.8 T)(\pi)(0.04 m)^2cos(0) }[/math]

[math]\displaystyle{ = 4.02 x 10^{-3} T*m^2 }[/math]

Middle

Diagram for simple example

Adapted from the Matter & Interactions textbook, variation of P27 (4th ed).

A very long, tightly wound solenoid has a circular cross-section of radius 2 cm (only a portion of the very long solenoid is shown). The magnetic field outside the solenoid is negligible. Throughout the inside of the solenoid the magnetic field B is uniform, to the left as shown, but varying with time t: B = (.06+.02[math]\displaystyle{ t^2 }[/math])T. Surrounding the circular solenoid is a loop of 7 turns of wire in the shape of a rectangle 6 cm by 12 cm. The total resistance of the 7-turn loop is 0.2 ohms.

(a) At t = 2 s, what is the direction of the current in the 7-turn loop? Explain briefly.

(b) At t = 2 s, what is the magnitude of the current in the 7-turn loop? Explain briefly.

Solution

(a) The direction of the current in the loop is clockwise.

(b)

B(t) = (.06+.02[math]\displaystyle{ t^2 }[/math])

A = (π)(0.02 m)^2 = .00126 [math]\displaystyle{ m^2 }[/math]

[math]\displaystyle{ |{&epsilon;}| = AN\frac{dB(t)}{dt} }[/math]

[math]\displaystyle{ |{&epsilon;}| }[/math] = (.00126 [math]\displaystyle{ m^2 }[/math])(7)[math]\displaystyle{ \frac{d(.06+.02t^2)}{dt} }[/math] = (.00882)(.02)(2t) = .0003528t

At t = 2 s:

[math]\displaystyle{ |{&epsilon;}| }[/math] = .0003528(2) = .0007056 V

[math]\displaystyle{ i = \frac{{&epsilon;}}{R} }[/math]

[math]\displaystyle{ i = \frac{{.0007056 V}}{0.2 ohms} }[/math] = .00353 A

Difficult


A square loop (dimensions L⇥L, total resistance R) is located halfway inside a region with uniform magnetic field B0. The magnitude of the magnetic field suddenly begins to increase linearly in time, eventually quadrupling in a time T.

(a) What current (magnitude and direction), if any, is induced in the loop at time T?

[math]\displaystyle{ |emf| = \frac{-{&Phi;}_{B}}{&Delta;t} = \frac{A(B_f - B_i)}{T} = \frac{L^2(4B_o - B_o)}{T} = \frac{3B_oL^2}{T} }[/math]

emf = IR = [math]\displaystyle{ \frac{3B_oL^2}{TR} }[/math]


(b) What net force (magnitude and direction), if any, is induced on the loop at time T?

[math]\displaystyle{ F_{top} }[/math] and [math]\displaystyle{ F_{bottom} }[/math] cancel out. [math]\displaystyle{ F_{left} }[/math] = 0 because the left side is out of [math]\displaystyle{ \vec{B} }[/math] region.

[math]\displaystyle{ \vec{F} }[/math] = [math]\displaystyle{ \vec{F}_{right} }[/math] = I [math]\displaystyle{ \vec{L} \times \vec{B} = (ILB)[(\hat{y} \times - \hat{z} )] = \frac{3B_oL^2}{TR}(4B_o L)(- \hat{x}) = \frac{3{B_o}^2 L^3}{TR}(- \hat{x}) }[/math]


(c) What net torque (magnitude and direction), if any, is induced on the loop at time T?

[math]\displaystyle{ \vec{&tau;} = \vec{&mu;} \times \vec{B} = 0 }[/math] because [math]\displaystyle{ \vec{&mu;} }[/math] and [math]\displaystyle{ \vec{B} }[/math] are anti-parallel.

Connectedness

Faraday's Law is one of Maxwell's equations which describe the essence of electric and magnetic fields. Maxwell's equations effectively summarize and connect all that we have learned throughout the course of Physics 2.

As an electrical engineer, Faraday's Law is relevant to my major.


Faraday’s Law Applications

Physics 2 content has a lot of important concepts that we as engineers can use to make our jobs easier. Whether it be a direct application of a rule or some derivation of a rule. I know I personally struggle with a concept until I get a concrete real life application that I can see the material applied in. This section of the page will discuss how Faraday’s law is applied to concepts that you as students maybe more familiar with your day to day life.


Hydroelectric Generators

    Generators create energy by transforming mechanical motion into electrical energy, but hydroelectric generators use the power of falling water to turn a large turbine which is connected to a large magnet. Around this magnet is a large coil of tightly wound wire. The conceptual creation of electricity is the same as Faraday’s Law except alternating current is being produced, but the idea that a changing magnetic field in a coil of wire induces an electromotive force is still the same. The difference is the magnetic field changes sign and flips resulting in the same thing to occur in the induced EMF. Although the calculations here are slightly more difficult the concepts are the same.

Transformers

Transformers use a similar concept for Faraday’s Law but it’s slightly different. The job of a transformer is to either step up or step down the voltage on the power line. Transformers have a constant magnetic field associated with it due to an iron core. The power supply voltage is adjusted by altering the number of turns of wire around the iron core which in turn alters the EMF of the electricity.


Cartoon of Hydroelectric Plant https://etrical.files.wordpress.com/2009/12/hydrohow.jpg Turbine Picture http://theprepperpodcast.com/wp-content/uploads/2016/02/108-All-About-Hydro-Power-Generators-1054x500.jpg Transformer Diagram https://en.wikipedia.org/wiki/Transformer#/media/File:Transformer3d_col3.svg

History

In 1831, eletromagnetic induction was discovered by Michael Faraday.

Faraday's Law Experiment

Faraday showed that no current is registered in the galvanometer when bar magnet is stationary with respect to the loop. However, a current is induced in the loop when a relative motion exists between the bar magnet and the loop. In particular, the galvanometer deflects in one direction as the magnet approaches the loop, and the opposite direction as it moves away.

Faraday’s experiment demonstrates that an electric current is induced in the loop by changing the magnetic field. The coil behaves as if it were connected to an emf source. Experimentally it is found that the induced emf depends on the rate of change of magnetic flux through the coil.

Test it out yourself here


See also

Further Readings

Matter and Interactions, Volume II: Electric and Magnetic Interactions, 4th Edition

The Electric Life of Michael Faraday (2009) by Alan Hirshfield

Electromagnetic Induction Phenomena (2012) by D. Schieber

External Links

https://www.youtube.com/watch?v=KGTZPTnZBFE

https://www.nde-ed.org/EducationResources/HighSchool/Electricity/electroinduction.htm

http://www.famousscientists.org/michael-faraday/

http://www.bbc.co.uk/history/historic_figures/faraday_michael.shtml

References

Matter and Interactions, 4th Edition

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/farlaw.html

https://files.t-square.gatech.edu/access/content/group/gtc-970b-7c13-52a7-9627-cdc3154438c6/Test%20Preparation/Old%20Test/2212_Test4_Key-1.pdf

https://en.wikipedia.org/wiki/Faraday%27s_law_of_induction

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