Newton's Second Law: the Momentum Principle: Difference between revisions

Latest revision as of 18:50, 15 November 2024

Claimed by Arayna Saxena, Fall 2024

This page describes Newton's second law of motion, also known as the momentum principle, which relates net force to the change in Linear Momentum. This principle is used to predict the effects of forces on the motion of objects.

The Main Idea

Newton's second law of motion, also known as the momentum principle, explains how forces cause the momentum of a system to change over time. The principle states that [math]\displaystyle{ \vec{F}_{net} = \frac{d\vec{p}_{system}}{dt} }[/math] where [math]\displaystyle{ \vec{p} }[/math] is the Linear Momentum of a system, [math]\displaystyle{ \vec{F}_{net} }[/math] is the external Net Force acting on the system from its surroundings, and t is time. Often, the system in question consists of a single particle whose motion we want to predict, although the law is also true for systems of particles and non-particle distributions of mass, such as disks. Note that both force and momentum are vector quantities, and that the change in momentum as a result of a force will always be in the direction of that force.

Here are some simple situations to help you build an intuition for the momentum principle:

If a particle travels in a straight line at a constant speed, its momentum is constant, so there is no net force acting on the particle.
If a particle travels in a straight line while speeding up, its momentum is increasing, so there must be a net force acting in the same direction as the particle's momentum.
If a particle travels in a straight line while slowing down, its momentum is decreasing, so there must be a net force acting in the opposite direction as the particle's momentum.
If a particle travels along a curving path, its momentum changes direction, and a force not parallel to the object's momentum must be acting on it.

The momentum principle has no derivation, as it is considered the definition of force. The metric unit most commonly used for force is the Newton.

A Mathematical Model

The momentum principle states that [math]\displaystyle{ \vec{F}_{net} = \frac{d\vec{p}}{dt} }[/math]. Recall that [math]\displaystyle{ \vec{p} = m\vec{v} }[/math]. Therefore, by product rule, [math]\displaystyle{ \frac{d\vec{p}}{dt} = m\frac{d\vec{v}}{dt} + \vec{v}\frac{dm}{dt} }[/math]. Usually,the mass of the particle or system is constant over time, so the second term becomes 0, and the momentum principle becomes [math]\displaystyle{ \vec{F}_{net} = m\frac{d\vec{v}}{dt} }[/math], or [math]\displaystyle{ \vec{F}_{net} = m\vec{a} }[/math], which may be a more familiar form of Newton's second law. The form [math]\displaystyle{ \vec{F}_{net} = \frac{d\vec{p}}{dt} }[/math] is preferred for several reasons:

When a particle accumulates mass that was initially at rest, such as a snowball rolling downhill, the term [math]\displaystyle{ \vec{v}\frac{dm}{dt} }[/math] is not 0, and [math]\displaystyle{ \vec{F}_{net} = m\vec{a} }[/math] is no longer accurate, while [math]\displaystyle{ \vec{F}_{net} = \frac{d\vec{p}}{dt} }[/math] is;
As a particle approaches the speed of light, [math]\displaystyle{ \vec{F}_{net} = m\vec{a} }[/math] is no longer accurate, while [math]\displaystyle{ \vec{F}_{net} = \frac{d\vec{p}}{dt} }[/math] is, as long as Relativistic Momentum is used; and
[math]\displaystyle{ \vec{F}_{net} = \frac{d\vec{p}}{dt} }[/math] has a more direct rotational analogue- that is, it will be easier to accurately learn rotational physics if you learn linear physics using this form.

That said, the relation [math]\displaystyle{ \vec{F}_{net} = m\vec{a} }[/math] can often be of use when the particle is known to have a constant mass and travel at non-relativistic speeds, particularly in combination with kinematic equations that also use [math]\displaystyle{ \vec{a} }[/math].

The momentum principle is responsible for the relationship between Impulse and Momentum.

Note that according to the momentum principle, when the external force on a system is 0 (that is, the system is closed), the rate of change of its momentum is 0. This results in Conservation of Momentum in certain situations.

A Computational Model

The relationship between net force and change in momentum can be computationally modeled using the momentum update formula: [math]\displaystyle{ p_2=p_1+F_{net}*\Delta\text{t} }[/math]. This is a rewriting of Fnet= dp/dt, where mass is assumed to be constant. First, momentum is defined as the object’s mass times its velocity in the initial conditions of the simulations. For Iterative Prediction, a while loop for the duration of the movement first updates [math]\displaystyle{ F_{net} }[/math] by summing all possible net forces acting on the object during the simulation. Then the momentum principle is updated using the formula described previously. Finally, using the new momentum, the position is updated using the formula: [math]\displaystyle{ \overrightarrow{r}_2=\overrightarrow{r}_1+(\overrightarrow{p}/m)*\Delta\text{t} }[/math], where velocity can be substituted as [math]\displaystyle{ (\overrightarrow{p}/m) }[/math].

Such a simulation is shown below:

The vPython computational model calculates the changing position, velocity, and momentum vs. time graphs of a free-falling ball that is only subject to the force of gravity near the surface of the Earth.

https://www.glowscript.org/#/user/rgovind/folder/MyPrograms/program/Wiki

Examples

1. (Simple)

At t=0, a 4kg particle is released from rest and a constant 12N force begins acting on it. How far has the particle moved after 5 seconds?

For this problem, it is easier to use [math]\displaystyle{ \vec{F}_{net} = m\vec{a} }[/math] than [math]\displaystyle{ \vec{F}_{net} = \frac{d\vec{p}}{dt} }[/math] because it allows us to solve for [math]\displaystyle{ \vec{a} }[/math] which can then be used in a kinematic equation. We know this form of Newton's second law is accurate for this problem because the particle travels at non-relativistic speeds and is of constant mass.

[math]\displaystyle{ \vec{F}_{net} = m\vec{a} }[/math] can be rearranged into [math]\displaystyle{ \vec{a} = \frac{\vec{F}_{net}}{m} }[/math]

[math]\displaystyle{ a = \frac{12}{4} = 3 }[/math] (direction doesn't matter for this problem.)

[math]\displaystyle{ x_f = \frac{1}{2}at^2 + v_it + x_i = \frac{1}{2}(3)(5^2) = \frac{75}{2} }[/math] = 37.5 m.

2. (Middling)

A tennis ball of mass mB = 0.8kg and an initial velocity of ViB = <7,0,0> m/s. The tennis ball collides head-on with a lump of mashed potatoes with a mass mP = 3kg that was initially at rest. The tennis ball becomes embedded in the mush. Determine the velocity of the tennis ball and mashed potatoes after the collision, assuming that this collision is totally inelastic. Calculate how much energy is lost and determine the tennis ball and mashed potatoes individual velocities after the collision if the collision was elastic.

If this collision is inelastic, then we know that kinetic energy is not conserved. However, momentum is conserved for all types of collisions (elastic, inelastic, partially elastic) due to the momentum principle. To start, write out the momentum principle. Since the tennis ball and mashed potatoes are stuck together after the collision, the final momentum can be written with their combined mass:

File:Momentumconserved.jpg

alt text

File:Momentumconserved.jpg

File:MCP2.jpg

alt text

3. (Difficult)

A cylindrical rocket ship of mass [math]\displaystyle{ M }[/math] and speed [math]\displaystyle{ v }[/math] is cruising through outer space when it encounters a stationary dust cloud. The dust cloud has a number density of [math]\displaystyle{ N }[/math] particles per unit volume, and each dust particle has a mass of [math]\displaystyle{ m }[/math]. The rocket ship has a sticky surface on its front face that allows it to accumulate all of the dust that it hits, absorbing it into its mass. The radius of the rocket ship's circular face is [math]\displaystyle{ R }[/math]. What force does the rocket's thruster need to exert on it in order to preserve its speed as it moves through the dust cloud? (Assume that the consumption of fuel has a negligible impact on the mass of the rocket.)

Advanced Note: in order to use [math]\displaystyle{ \frac{dm}{dt} }[/math] for the accumulation of mass, the accumulated mass (i.e. the dust) must initially be at rest, like in the above problem. Otherwise, one must treat the accumulation of dust particles as a series of collisions, or change one's frame of reference so that the accumulated mass is initially at rest.

4. (Difficult)

A particle of mass [math]\displaystyle{ m }[/math] and speed [math]\displaystyle{ v }[/math] moves in a circular path. Its angular frequency is [math]\displaystyle{ \Omega }[/math]. (Angular frequency is the rate at which the angle of the particle's position is changing in radians per unit time.) Using the momentum principle, show that

a) a nonzero net force is acting on the particle,

b) the magnitude of the force is given by [math]\displaystyle{ f = mv\Omega }[/math], and

c) the direction of the force is inwards towards the center of the circle.

a) The particle's momentum vector is changing over time; its magnitude is constant (mv), but its direction changes as its position along the circular path changes. It is always tangential to the circular path. Since [math]\displaystyle{ \vec{p} }[/math] changes over time, a nonzero net force must be acting on the particle. In fact, the only way a particle of constant mass can have a net force of 0 acting on it is if it is travelling along a straight line at a constant speed, or if it is at rest.

b)

c) As one can see from the diagram above, [math]\displaystyle{ d\vec{p} }[/math] is pointing towards the center of the circle. If the particle is exactly at the top of the circle, its momentum is to the right (or left if the particle is travelling counterclockwise), and as [math]\displaystyle{ d\theta }[/math] approaches 0, [math]\displaystyle{ d\vec{p} }[/math] approaches a downward direction, which is towards the center of the circle.

For more information, see Centripetal Force and Curving Motion. Our answer agrees with the formulas given on that page.

Connectedness

Newton's second law is applicable to any situation where a force is applied and a system's momentum changes. There are nearly limitless examples of such situations, as well as nearly limitless applications. A few can be found below.

Scenario: bungee jump

When a bungee jumper falls and their cord is pulled taut, the cord applies a force in the direction opposite to the jumper's direction of travel. When this force is greater in magnitude than the gravity force, the net force is upward, which cuses causes the jumper's momentum, which is initially downward, to change over time in the upward direction. Eventually, the jumper is pulled back to a high altitude, the cord becomes slack, and gravity is once again the dominant force. The net force is downward once more, and the jumper's momentum changes over time in the downward direction.

Application: automobile industry

Cars frequently undergo all sorts of acceleration; they speed up, turn, and slow down. Forces are responsible for all of those accelerations, and these forces ultimately come from the tires' contact with the road. This force is, in fact, a form of Static Friction. The magnitude of this static friction force can only be up to a certain quantity known as the maximum static friction force. This maximum is determined by the shape and materials of the tires, as well as the weight of the car. Automobile manufacturers must always be aware of this maximum friction force when designing their car, as it places a limit on the ability of the car to accelerate, turn, and brake without slipping.

History

In his 1687 work Principia Mathematica, Isaac Newton (1643-1727) published his three laws of motion. Although his first and third laws were inspired by other scientists' work, his second law was entirely original. Below was the law as it appeared in his book:

Original Latin:

“Lex II: Mutationem motus proportionalem esse vi motrici impressae, et fieri secundum lineam rectam qua vis illa imprimitur.”

This was translated closely in Motte's 1729:

“Law II: The alteration of motion is ever proportional to the motive force impress'd; and is made in the direction of the right line in which that force is impress'd.”

In other words, the rate of change of momentum of a body is proportional to the force impressed on the body, and happens in the direction of that force.

This law was the first time force had ever been defined, and it is a definition that is still used today. As a result of Newton's contribution to the science of forces, the unit of force most commonly still used today is named after him.

@@ Line 1: / Line 1: @@
-This page describes Newton's second law, also known as the momentum principle, which relates net force to the change in [[linear momentum]]. This principle is used to predict the effects of forces on the motion of objects.
+'''Claimed by Arayna Saxena, Fall 2024'''
+This page describes Newton's second law of motion, also known as the momentum principle, which relates net force to the change in [[Linear Momentum]]. This principle is used to predict the effects of forces on the motion of objects.
 ==The Main Idea==
-Newton's second law, also known as the momentum principle, states that <math>\vec{F}_{net} = \frac{d\vec{p}_{system}}{dt}</math> where <math>\vec{p}</math> is the [[linear momentum]] of the system and <math>\vec{F}_{net}</math> is the net external force acting on the system from its surroundings. Often, the system in question consists of a single particle whose motion we want to predict. Note that both force and momentum are vector quantities, and that the change in momentum as a result of a force will always be in the direction of that force.
+Newton's second law of motion, also known as the momentum principle, explains how forces cause the momentum of a system to change over time. The principle states that <math>\vec{F}_{net} = \frac{d\vec{p}_{system}}{dt}</math> where <math>\vec{p}</math> is the [[Linear Momentum]] of a system, <math>\vec{F}_{net}</math> is the external [[Net Force]] acting on the system from its surroundings, and t is time. Often, the system in question consists of a single particle whose motion we want to predict, although the law is also true for systems of particles and non-particle distributions of mass, such as disks. Note that both force and momentum are vector quantities, and that the change in momentum as a result of a force will always be in the direction of that force.
-The momentum principle has no derivation, as it is considered the definition of force.
+Here are some simple situations to help you build an intuition for the momentum principle:
+<ol>
+<li>If a particle travels in a straight line at a constant speed, its momentum is constant, so there is no net force acting on the particle.
+<li>If a particle travels in a straight line while speeding up, its momentum is increasing, so there must be a net force acting in the same direction as the particle's momentum.
+<li>If a particle travels in a straight line while slowing down, its momentum is decreasing, so there must be a net force acting in the opposite direction as the particle's momentum.
+<li>If a particle travels along a curving path, its momentum changes direction, and a force not parallel to the object's momentum must be acting on it.
+</ol>
+The momentum principle has no derivation, as it is considered the definition of force. The metric unit most commonly used for force is the Newton.
 ===A Mathematical Model===
-The momentum principle states that <math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math>. Recall that <math>\vec{p} = m\vec{v}</math>. Therefore, by product rule, <math>\frac{d\vec{p}}{dt} = m\frac{d\vec{v}}{dt} + \vec{v}\frac{dm}{dt}</math>. Under the assumption that mass is constant, the second term becomes 0, and the momentum principle becomes <math>\vec{F}_{net} = m\frac{d\vec{v}}{dt}</math>, or <math>\vec{F}_{net} = m\vec{a}</math>, which may be a more familiar form of Newton's second law. The form <math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math> is preferred for several reasons:
+The momentum principle states that <math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math>. Recall that <math>\vec{p} = m\vec{v}</math>. Therefore, by product rule, <math>\frac{d\vec{p}}{dt} = m\frac{d\vec{v}}{dt} + \vec{v}\frac{dm}{dt}</math>. Usually,the mass of the particle or system is constant over time, so the second term becomes 0, and the momentum principle becomes <math>\vec{F}_{net} = m\frac{d\vec{v}}{dt}</math>, or <math>\vec{F}_{net} = m\vec{a}</math>, which may be a more familiar form of Newton's second law. The form <math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math> is preferred for several reasons:
 <ol>
 <li>When a particle accumulates mass that was initially at rest, such as a snowball rolling downhill, the term <math>\vec{v}\frac{dm}{dt}</math> is not 0, and <math>\vec{F}_{net} = m\vec{a}</math> is no longer accurate, while <math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math> is;</li>
-<li>As a particle approaches the speed of light, <math>\vec{F}_{net} = m\vec{a}</math> is no longer accurate, while <math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math> is, as long as [[relativistic momentum]] is used; and</li>
+<li>As a particle approaches the speed of light, <math>\vec{F}_{net} = m\vec{a}</math> is no longer accurate, while <math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math> is, as long as [[Relativistic Momentum]] is used; and</li>
-<li><math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math> has a more direct rotational analogue (that is, it will be easier to accurately learn rotational physics if you learn linear physics using this form.)</li>
+<li><math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math> has a more direct rotational analogue- that is, it will be easier to accurately learn rotational physics if you learn linear physics using this form.</li>
 </ol>
-The momentum principle is responsible for the relationship between [[impulse and momentum]].
+That said, the relation <math>\vec{F}_{net} = m\vec{a}</math> can often be of use when the particle is known to have a constant mass and travel at non-relativistic speeds, particularly in combination with [[Kinematics|kinematic equations]] that also use <math>\vec{a}</math>.
+The momentum principle is responsible for the relationship between [[Impulse and Momentum]].
+Note that according to the momentum principle, when the external force on a system is 0 (that is, the system is closed), the rate of change of its momentum is 0. This results in [[Conservation of Momentum]] in certain situations.
 ===A Computational Model===
-asdfasd
+The relationship between net force and change in momentum can be computationally modeled using the momentum update formula: <math>p_2=p_1+F_{net}*\Delta\text{t}</math>. This is a rewriting of Fnet= dp/dt, where mass is assumed to be constant. First, momentum is defined as the object’s mass times its velocity in the initial conditions of the simulations. For [[Iterative Prediction]], a while loop for the duration of the movement first updates <math>F_{net}</math> by summing all possible net forces acting on the object during the simulation. Then the momentum principle is updated using the formula described previously. Finally, using the new momentum, the position is updated using the formula: <math>\overrightarrow{r}_2=\overrightarrow{r}_1+(\overrightarrow{p}/m)*\Delta\text{t}</math>, where velocity can be substituted as <math>(\overrightarrow{p}/m)</math>.
+[[File:UpdateLoopforMomentumPrinciple.png]]
+Such a simulation is shown below:
+The vPython computational model calculates the changing position, velocity, and momentum vs. time graphs of a free-falling ball that is only subject to the force of gravity near the surface of the Earth.
+https://www.glowscript.org/#/user/rgovind/folder/MyPrograms/program/Wiki
 ==Examples==
-===Simple===
+===1. (Simple)===
+At t=0, a 4kg particle is released from rest and a constant 12N force begins acting on it. How far has the particle moved after 5 seconds?
+For this problem, it is easier to use <math>\vec{F}_{net} = m\vec{a}</math> than <math>\vec{F}_{net} = \frac{d\vec{p}}{dt}</math> because it allows us to solve for <math>\vec{a}</math> which can then be used in a kinematic equation. We know this form of Newton's second law is accurate for this problem because the particle travels at non-relativistic speeds and is of constant mass.
+<math>\vec{F}_{net} = m\vec{a}</math> can be rearranged into <math>\vec{a} = \frac{\vec{F}_{net}}{m}</math>
+<math> a = \frac{12}{4} = 3 </math> (direction doesn't matter for this problem.)
+<math> x_f = \frac{1}{2}at^2 + v_it + x_i = \frac{1}{2}(3)(5^2) = \frac{75}{2}</math> = 37.5 m.
+===2. (Middling)===
+A tennis ball of mass mB = 0.8kg and an initial velocity of ViB = <7,0,0> m/s. The tennis ball collides head-on with a lump of mashed potatoes with a mass mP = 3kg that was initially at rest. The tennis ball becomes embedded in the mush. Determine the velocity of the tennis ball and mashed potatoes after the collision, assuming that this collision is totally inelastic. Calculate how much energy is lost and determine the tennis ball and mashed potatoes individual velocities after the collision if the collision was elastic.
+If this collision is inelastic, then we know that kinetic energy is not conserved. However, momentum is conserved for all types of collisions (elastic, inelastic, partially elastic) due to the momentum principle.
+To start, write out the momentum principle. Since the tennis ball and mashed potatoes are stuck together after the collision, the final momentum can be written with their combined mass:
+[[File:momentumconserved.jpg|200px|thumb|left|alt text]]
+[[File:momentumconserved.jpg]]
+[[File:MCP2.jpg|200px|thumb|left|alt text]]
+===3. (Difficult)===
+A cylindrical rocket ship of mass <math>M</math> and speed <math>v</math> is cruising through outer space when it encounters a stationary dust cloud. The dust cloud has a number density of <math>N</math> particles per unit volume, and each dust particle has a mass of <math>m</math>. The rocket ship has a sticky surface on its front face that allows it to accumulate all of the dust that it hits, absorbing it into its mass. The radius of the rocket ship's circular face is <math>R</math>. What force does the rocket's thruster need to exert on it in order to preserve its speed as it moves through the dust cloud? (Assume that the consumption of fuel has a negligible impact on the mass of the rocket.)
+[[File:Rocketdustcloudpart1.jpg]]
+[[File:Rocketdustcloudpart2.jpg]]
+Advanced Note: in order to use <math>\frac{dm}{dt}</math> for the accumulation of mass, the accumulated mass (i.e. the dust) must initially be at rest, like in the above problem. Otherwise, one must treat the accumulation of dust particles as a series of collisions, or change one's frame of reference so that the accumulated mass is initially at rest.
+===4. (Difficult)===
+A particle of mass <math>m</math> and speed <math>v</math> moves in a circular path. Its angular frequency is <math>\Omega</math>. (Angular frequency is the rate at which the angle of the particle's position is changing in radians per unit time.) Using the momentum principle, show that
+a) a nonzero net force is acting on the particle,
+b) the magnitude of the force is given by <math>f = mv\Omega</math>, and
+c) the direction of the force is inwards towards the center of the circle.
-===Middling===
-===Difficult===
+a) The particle's momentum vector is changing over time; its magnitude is constant (mv), but its direction changes as its position along the circular path changes. It is always tangential to the circular path. Since <math>\vec{p}</math> changes over time, a nonzero net force must be acting on the particle. In fact, the only way a particle of constant mass can have a net force of 0 acting on it is if it is travelling along a straight line at a constant speed, or if it is at rest.
+b)
+[[File:derivationofcentripetalforce.jpg]]
+c) As one can see from the diagram above, <math>d\vec{p}</math> is pointing towards the center of the circle. If the particle is exactly at the top of the circle, its momentum is to the right (or left if the particle is travelling counterclockwise), and as <math>d\theta</math> approaches 0, <math>d\vec{p}</math> approaches a downward direction, which is towards the center of the circle.
+For more information, see [[Centripetal Force and Curving Motion]]. Our answer agrees with the formulas given on that page.
 ==Connectedness==
-#How is this topic connected to something that you are interested in?
-#How is it connected to your major?
+Newton's second law is applicable to any situation where a force is applied and a system's momentum changes. There are nearly limitless examples of such situations, as well as nearly limitless applications. A few can be found below.
-#Is there an interesting industrial application?
+===Scenario: bungee jump===
+When a bungee jumper falls and their cord is pulled taut, the cord applies a force in the direction opposite to the jumper's direction of travel. When this force is greater in magnitude than the gravity force, the net force is upward, which cuses causes the jumper's momentum, which is initially downward, to change over time in the upward direction. Eventually, the jumper is pulled back to a high altitude, the cord becomes slack, and gravity is once again the dominant force. The net force is downward once more, and the jumper's momentum changes over time in the downward direction.
+===Application: automobile industry===
+Cars frequently undergo all sorts of acceleration; they speed up, turn, and slow down. Forces are responsible for all of those accelerations, and these forces ultimately come from the tires' contact with the road. This force is, in fact, a form of [[Static Friction]]. The magnitude of this static friction force can only be up to a certain quantity known as the maximum static friction force. This maximum is determined by the shape and materials of the tires, as well as the weight of the car. Automobile manufacturers must always be aware of this maximum friction force when designing their car, as it places a limit on the ability of the car to accelerate, turn, and brake without slipping.
 ==History==
-Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.
+In his 1687 work <i>Principia Mathematica</i>, Isaac Newton (1643-1727) published his three laws of motion. Although his first and third laws were inspired by other scientists' work, his second law was entirely original. Below was the law as it appeared in his book:
+Original Latin:
+“Lex II: Mutationem motus proportionalem esse vi motrici impressae, et fieri secundum lineam rectam qua vis illa imprimitur.”
+This was translated closely in Motte's 1729:
+“Law II: The alteration of motion is ever proportional to the motive force impress'd; and is made in the direction of the right line in which that force is impress'd.”
+In other words, the rate of change of momentum of a body is proportional to the force impressed on the body, and happens in the direction of that force.
+This law was the first time force had ever been defined, and it is a definition that is still used today. As a result of Newton's contribution to the science of forces, the unit of force most commonly still used today is named after him.
 == See also ==
-Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?
+*[[Linear Momentum]]
+*[[Impulse and Momentum]]
+*[[Conservation of Momentum]]
+*[[Net Force]]
+*[[Mass]]
+*[[Acceleration]]
 ===Further reading===
-Books, Articles or other print media on this topic
+RANKINE, William John Macquorn, and Edward Fisher BAMBER. A Mechanical Text Book. 1873. Print.
 ===External links===
-Internet resources on this topic
+<ol>
+<li>nhttp://homepages.engineering.auckland.ac.nz/~pkel015/SolidMechanicsBooks/Part_III/Chapter_3_Stress_Mass_Momentum/Stress_Balance_Principles_02_The_Momentum_Principles.pdf</li>
+<li>http://acme.highpoint.edu/~atitus/phy221/lecture-notes/2-2-momentum-principle.pdf</li>
+<li>https://www.khanacademy.org/science/physics/forces-newtons-laws/newtons-laws-of-motion/v/newton-s-second-law-of-motion</li>
+<li>https://www.khanacademy.org/science/physics/forces-newtons-laws/newtons-laws-of-motion/v/more-on-newtons-second-law</li>
+<li>https://science.howstuffworks.com/innovation/scientific-experiments/newton-law-of-motion3.htm</li>
+<li>https://www.livescience.com/46560-newton-second-law.html</li>
+</ol>
 ==References==
-This section contains the the references you used while writing this page
+*William, Harris. "How Newton's Laws of Motion Work" 29 July 2008. HowStuffWorks.com. <https://science.howstuffworks.com/innovation/scientific-experiments/newton-law-of-motion.htm> 11 April, 2018.
+*Sherwood, Bruce A. "2.1 The Momentum Principle." Matter & Interactions. By Ruth W. Chabay. 4th ed. Vol. 1. N.p.: John Wiley & Sons, 2015. 45-50. Print. Modern Mechanics. 8 April, 2018.
+*http://www.physicsclassroom.com/class/newtlaws/Lesson-3/Newton-s-Second-Law
+*Dugas, René (1988). A history of mechanics. Translated into English by J.R. Maddox (Dover ed.). New York: Dover Publications.
+*Jennings, John (1721). Miscellanea in Usum Juventutis Academicae. Northampton: R. Aikes & G. Dicey.
-[[Category:Which Category did you place this in?]]
+[[Category: Momentum]]