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This page is all about the [[Electric Field]] due to a Point Charge.'''CLAIMED BY JENNIFER YU 09/06/19 (Fall 2019)'''
Claimed by Sam Bureau Spring 2024


This page is all about the [[Electric Field]] due to a Point Charge.




==The Main Idea==
 
==The Main Ideas ==
(Ch 13.1 in ''Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood'')
(Ch 13.1 in ''Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood'')


Line 16: Line 18:
''Like'' point charges ''attract'', ''opposite'' point charges ''repel''.
''Like'' point charges ''attract'', ''opposite'' point charges ''repel''.
ex.<table border>  <tr>
ex.<table border>  <tr>
     <th>Point Charges</th>
     <th> Point Charges </th>
     <th>Result</th>
     <th> Result </th>
<th>Diagram</th>
   </tr>
   </tr>
   <tr>
   <tr>
     <td> 1 proton, 1 electron</td>
     <td> 1 proton, 1 electron</td>
     <td> Attract </td>
     <td> Attract </td>
<td>[[File:Proton_electron_attraction.png]]</td>
   </tr>
   </tr>
   <tr>
   <tr>
     <td>2 protons </td>
     <td>2 protons </td>
     <td> Repel </td>
     <td> Repel </td>
<td>[[File:Proton_repulsion.png]]</td>
   </tr>
   </tr>
   <tr>
   <tr>
     <td>2 electrons </td>
     <td>2 electrons </td>
     <td> Repel </td>
     <td> Repel </td>
<td>[[File:Electron_repulsion.png]]</td>
   </tr>
   </tr>
</table border>
</table border>
   
   


===The Electric Field===
(Ch 13.3 in ''Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood'')


[[File:Phys 1.png|800px]]
In general, the electric field evaluates the affect of the source on the surrounding objects and area. The electric field created by a charge is present throughout space at all times, whether or not there is another charge around to feel its effects. Therefore, the concept of the electric field by a point charge describes the interactions that can happen at a distance, due to these affects caused by this point charge.  


The electric field is an inherent quality of a charged particle. It is defined as a vector field that associates each point in space with the electric force that an infinitesimal test charge would experience. As shown below, the electric field of a positive point charge points radially outward and that of a negative point charge points radially inward. The magnitude of the electric field decreases with increasing distance from the point charge. The source of the electric field in this article is the point charge.
Important to differentiate that Electric Force does not equal the Electric Field.


[[File:Point_charge.GIF|600px]]
Electric Field of a Charge Observed at a location: F = Eq
*F = Force on particle
*E = electric field at source location
*q = magnitude of the charge of particle (assume q= 1.6 x 10^-19 unless stated otherewise)
The magnitude of the electric field decreases with increasing distance from the point charge.


<table border>
  <tr>
    <td>The electric field of a positive point charge points radially outward</td>
    <td>The electric field of a negative point charge points radially inward</td>
  </tr>
  <tr>
    <td>[[File:Proton_electric_field.png]] </td>
    <td> [[File:Electron_electric_field.png]] </td>
  </tr>
</table border>


===A Mathematical Model===
===A Mathematical Model===


====Coulomb Force Law for Point Charges====
====Electric Field due to Point Charge====
(Ch 13.4 in ''Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood'')
 
The magnitude of the electric field decreases with increasing distance from the point charge. This is described by the equation below:


This law defines the electrical force of attraction or repulsion between two given point charges. The following formula describes the magnitude of this force:
Electric Field of a Point Charge (<math>\vec E</math>):


<math>\mid\vec F\mid=\frac{1}{4 \pi \epsilon_0 } \frac{\mid Q_1Q_2 \mid}{r^2}</math>
<math>\vec E=\frac{1}{4 \pi \epsilon_0 } \frac{q}{\mid\vec r\mid ^2} \hat r</math> (Newtons/Coulomb)


<math>Q_1, Q_2</math>= The charge of two particles of interest
*<math>\frac{1}{4 \pi \epsilon_0 } </math> is Coulomb's Constant and is approximately <math>8.987*10^{9}\frac{N m^2}{C^2} </math>
*'''''q''''' is the charge of the particle
*'''''r''''' is the magnitude of the distance between the observation location and the source location
*<math>\hat r </math> is the unit vector in the direction of the distance from the source location to the observation point.


r = The distance between the two particles


====Electric Field due to Point Charge====
The direction of the electric field at the observation location depends on the both the direction of <math>\hat r </math> and the sign of the source charge.
*If the source charge is positive, the field points away from the source charge, in the same direction as <math>\hat r </math>.
*If the source charge is negative, the field points toward the source charge, in the opposite direction as <math>\hat r </math>.


The Electric Field of a Point Charge can be found by using the following formula:
====Coulomb Force Law for Point Charges====
(Ch 13.2 in ''Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood'')
<math>\vec E=\frac{1}{4 \pi \epsilon_0 } \frac{q}{\mid\vec r\mid ^2} \hat r</math>


Which is derived from [[Gauss's Law]], modeling the point charge as a sphere.
<math>\mid\vec F\mid=\frac{1}{4 \pi \epsilon_0 } \frac{\mid Q_1Q_2 \mid}{r^2}</math>


<math>{\epsilon_0} </math>  is a constant representing vacuum permittivity, the permittivity of free space, or the electric constant, and is approximately <math>8.854*10^{-12}\frac{C^2}{N m^2}</math>


<math>\frac{1}{4 \pi \epsilon_0 } </math> is known as Coulomb's Constant and is approximately <math>8.987*10^{9}\frac{N m^2}{C^2} </math>
Coulomb's law is one of the four fundamental physical interactions, and it describes the magnitude of the electric force between two point-charges.  


'''''r''''' is the magnitude of the distance between the observation location and the source location
*<math>Q_1, Q_2</math>= The charges of the two particles of interest
, '''''q''''' is the charge of the particle
*<math>\mid\vec F\mid=\frac{1}{4 \pi \epsilon_0 }</math> = constant,  
and <math>\hat r </math> is the unit vector in the direction of the distance from the source location to the observation point.
* <math>Q_1, Q_2</math> = the magnitudes of the point charges
*r = The distance between the two particles


====Connection Between Electric Field and Force====
====Connection Between Electric Field and Force====
The force on a source charge is determined by <math> F = Eq </math> where '''''E''''' is the electric field and '''''q''''' is the charge of a test charge in Coulombs.


The force on a given test charge is governed by <math> F = Eq </math> where '''''E''''' is the electric field and '''''q''''' is the charge of a test charge in Coulombs. This force is represented by Coulomb's Law which was described above.
By solving for the electric field in <math> F = Eq </math>, with F modeled by Coulomb's Law, you get the equation for the electric field of the point charge:
 
By solving for the electric field in <math> F = Eq </math>, with F modeled by Coulomb's Law, one obtains the equation for the electric field of the point charge:


<math> E = \frac{F}{q_2} = \frac{1}{4 \pi \epsilon_0 } \frac{q_1q_2}{r^2}\frac{1}{q_2}\hat r  = \frac{1}{4 \pi \epsilon_0 } \frac{q_1}{r^2} \hat r </math>
<math> E = \frac{F}{q_2} = \frac{1}{4 \pi \epsilon_0 } \frac{q_1q_2}{r^2}\frac{1}{q_2}\hat r  = \frac{1}{4 \pi \epsilon_0 } \frac{q_1}{r^2} \hat r </math>




===A Computational Model===
The direction of electric force also depends on the direction of the electric field too:


Below is a link to a code which can help visualize the Electric Field at various observation locations due to a proton. Notice how the arrows decrease in size by a factor of <math> \frac{1}{r^{2}} </math> as the observation location gets farther from the proton. The magnitude of the electric field decreases as the distance to the observation location increases.
*If the source charge is positive, the field points away from the source charge, in the same direction as the electric force.
*If the source charge is negative, the field points toward the source charge, in the opposite direction as the electric force.


====Electric Field Superposition (Point Charges)====


When there are multiple point charges present, the total net electric field <math> Enet </math>, is equal to the sum of the electric field of each independent point charge present.


<iframe src="https://trinket.io/embed/glowscript/725d552305?outputOnly=true" width="100%" height="356" frameborder="0" marginwidth="0" marginheight="0" allowfullscreen></iframe>
This is due to  concept of Superposition which is when the total effect is the sum of the effects of each part.


When it comes to the Electric Field Superposition of Point Charges, be sure to remember that:


https://trinket.io/glowscript/725d552305
*A charge cannot exert a force on itself
*Assume that the source charges do not move. (Therefore <math> Fnet = 0 </math>)


Two adjacent point charges of opposite sign exhibit an electric field pattern that is characteristic of a dipole. This interaction is displayed in the code below. Notice how the electric field points towards the negatively charged point charge (blue) and away from the positively charged point charge (red).


https://trinket.io/glowscript/f29782cb9d


==Examples==
[[File:IMG_1DCC0A11C7B8-1.jpeg]]


===Simple===
===A Computational Model===
There is an electron at the origin. Calculate the electric field at (4,-3,1)m.


'''Step 1:''' Find <math>\hat r</math>
Below is a link to a code which can help visualize the Electric Field at various observation locations due to a proton. Notice how the arrows decrease in size by a factor of <math> \frac{1}{r^{2}} </math> as the observation location gets farther from the proton. The magnitude of the electric field decreases as the distance to the observation location increases.


Find <math>\vec r_{obs} - \vec r_{electron}  ((4,-3,1) - (0,0,0) = <4,-3,1> </math>m


Calculate the magnitude of <math>\vec r</math>. (<math>\sqrt{4^2+(-3)^2+1^2}=\sqrt{26}</math>
[[File:First code.gif]]


From <math>\vec r</math>, find the unit vector <math>\hat{r}.</math> <math>  <\frac{4}{\sqrt{26}},\frac{-3}{\sqrt{26}},\frac{1}{\sqrt{26}}> </math>
Two adjacent point charges of opposite sign exhibit an electric field pattern that is characteristic of a dipole. This interaction is displayed in the code below. Notice how the electric field points towards the negatively charged point charge (blue) and away from the positively charged point charge (red).


'''Step 2:''' Find the magnitude of the Electric Field
[[File:Code_2.png]]


<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} = \frac{1}{4 \pi \epsilon_0 } \frac{-1.6 * 10^{-19}}{26} </math>
==Examples==


'''Step 3:''' Multiply the magnitude of the Electric Field by <math>\hat{r}</math> to find the Electric Field
===Simple===
There is an electron at the origin. Calculate the electric field at <4, -3, 1> m.


<math>E =  \frac{1}{4 \pi \epsilon_0 } \frac{-1.6 * 10^{-19}}{26}*<\frac{4}{\sqrt{26}},\frac{-3}{\sqrt{26}},\frac{1}{\sqrt{26}}> = <-4.34*10^{-11},3.26*10^{-11},-1.09*10^{-11}>  N/C    </math>
[[File:Screenshot_2024-04-13_160839.png]]


===Middling===
===Middling===
A particle of unknown charge is located at (-0.21, 0.02, 0.11) m. Its electric field at point (-0.02, 0.31, 0.28) m is <math><0.124, 0.188, 0.109> </math> N/C. Find the magnitude and sign of the particle's charge.
A particle of unknown charge is located at <-0.21, 0.02, 0.11> m. Its electric field at point <-0.02, 0.31, 0.28> m is <math><0.124, 0.188, 0.109> </math> N/C. Find the magnitude and sign of the particle's charge.


Given both an observation location and a source location, one can find both r and <math>\hat{r}</math>  Given the value of the electric field, one can also find the magnitude of the electric field. Then, using the equation for the magnitude of electric field of a point charge,<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math>  one can find the magnitude and sign of the charge.  
Given both an observation location and a source location, one can find both r and <math>\hat{r}</math>  Given the value of the electric field, one can also find the magnitude of the electric field. Then, using the equation for the magnitude of electric field of a point charge, <math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math>  one can find the magnitude and sign of the charge.  


'''Step 1:'''
<table border>
Find <math>\vec r_{obs} - \vec r_{particle} </math>.
  <tr>
 
    <td> <b>Step 1.</b> Find <math>\vec r_{obs} - \vec r_{particle} </math>:
<math>\vec r = (-0.02,0.31,0.28) m - (-0.21,0.02,0.11) m = <0.19,0.29,0.17> m </math>


<math>\vec r = <-0.02, 0.31, 0.28> m - <-0.21, 0.02, 0.11> m = <0.19,0.29,0.17> m </math>


To find <math>\vec r_{mag} </math>, find the magnitude of <math><0.19,0.29,0.17></math>  
To find <math>\vec r_{mag} </math>, find the magnitude of <math><0.19,0.29,0.17></math>  


<math>\sqrt{0.19^2+0.29^2+0.17^2}=\sqrt{0.1491}= 0.39</math>  
<math>\sqrt{0.19^2+0.29^2+0.17^2}=\sqrt{0.1491}= 0.39</math>  
</td></tr>


 
    <tr><td><b>Step 2:</b> Find the magnitude of the Electric Field:
'''Step 2:''' Find the magnitude of the Electric Field  


<math>E= <0.124, 0.188, 0.109> N/C</math>  
<math>E= <0.124, 0.188, 0.109> N/C</math>  


<math>E_{mag} = (\sqrt{0.124^2+0.188^2+0.109^2}=\sqrt{0.0626}=0.25</math>  
<math>E_{mag} = (\sqrt{0.124^2+0.188^2+0.109^2}=\sqrt{0.0626}=0.25</math>  </td></tr>


 
    <td>'''Step 3:''' Find '''''q''''' by rearranging the equation for <math>E_{mag}</math>
'''Step 3:''' Find '''''q''''' by rearranging the equation for <math>E_{mag}</math>


<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math>
<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math>
Line 144: Line 172:
By rearranging this equation we get
By rearranging this equation we get


<math> q= {4 pi * epsilon_0 } *{r^2}*E_{mag} </math>  
<math> q= {4 \pi * \epsilon_0 } *{r^2}*E_{mag} </math>  


<math> q= {1/(9*10^9)} *{0.39^2}*0.25 </math>  
<math> q= {1/(9*10^9)} *{0.39^2}*0.25 </math>  


<math> q= + 4.3*10^{-12} C </math>  
<math> q= + 4.3*10^{-12} C </math></td>
 
</table border>


===Difficult===
===Difficult===
Line 154: Line 184:


Given the force and charge on the particle, one can calculate the surrounding electric field. With this variable found, this problem becomes much like the last one.
Given the force and charge on the particle, one can calculate the surrounding electric field. With this variable found, this problem becomes much like the last one.
<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r_{mag}^2} </math> to find the rmag value. To find <math>\hat r</math> we can find the direction of the electric field as that is obviously going to be in the same direction as  <math>\hat r</math>. Then, once we find  <math>\hat r</math>, all that is left to do is multiply <math>\hat r</math> by rmag and that will give us the  <math> r</math> vector. We can then find the location of the particle as we know  <math>r=r_{observation}-r_{particle}</math>


 
<table border>  
 
  <tr>
<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r_{mag}^2} </math>
    <td> <b>Step 1.</b> Find the magnitude of the Electric field:
 
to find the rmag value. To find <math>\hat r</math> we can find the direction of the electric field as that is obviously going to be in the same direction as  <math>\hat r</math>. Then, once we find  <math>\hat r</math>, all that is left to do is multiply <math>\hat r</math> by rmag and that will give us the  <math> r</math> vector. We can then find the location of the particle as we know  <math>r=r_{observation}-r_{particle}</math>
 
'''Step 1''':
Find the magnitude of the Electric field.
 
<math> F = Eq </math>  
<math> F = Eq </math>  
<math> = E * -2mC </math>


<math> <5.5*10^{3}, -7.6*10^{3}, 0> = E * -2mC </math>
<math> E = \frac{< -5.5e3 , -5.5e3, -5.5e3>}{-2mC}
 
<math> E = \frac{< -5.5*10^{3} , -5.5*10^{3}, -5.5*10^{3}>}{-2mC} = <2.75*10^{6} , 2.75*10^{6} , 2.75*10^{6}> </math> N/C
 




'''Step 2:''':
= <2.75e6 , 2.75e6, 2.75e6> </math> N/C
Find <math>\vec r_{obs} - \vec r_{particle} </math>.
</td></tr>


<math>\vec r = (3.98 , 3.98 , 3.98) m - (0 , 0 , 0) m = <3.98 , 3.98 , 3.98> m </math>
    <tr><td><b>Step 2:</b> Find <math>\vec r_{obs} - \vec r_{particle} </math>.


<math>\vec r = <3.98 , 3.98 , 3.98> m - <0 , 0 , 0> m = <3.98 , 3.98 , 3.98> m </math>


To find <math>\vec r_{mag} </math>, find the magnitude of <math><3.98 , 3.98 , 3.98></math>  
To find <math>\vec r_{mag} </math>, find the magnitude of <math><3.98 , 3.98 , 3.98></math>  


<math>\sqrt{3.98^2+3.98^2+3.98^2}=\sqrt{47.52}= 6.9</math>  
<math>\sqrt{3.98^2+3.98^2+3.98^2}=\sqrt{47.52}= 6.9</math>  
  </td></tr>


 
    <td> '''Step 3:''' Find '''''q''''' by rearranging the equation for <math>E_{mag}</math>
'''Step 3:''' Find the magnitude of the Electric Field
 
<math>E= <2.75*10^{6} , 2.75*10^{6} , 2.75*10^{6}> </math> N/C
 
<math>E_{mag} = (\sqrt{(2.75*10^{6})^2+2.75*10^{6})^2+2.75*10^{6})^2}=\sqrt{2.27*10^{13}}=4.76*10^{6}</math>
 
 
'''Step 4:''' Find '''''q''''' by rearranging the equation for <math>E_{mag}</math>


<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math>
<math> E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} </math>
Line 196: Line 213:
By rearranging this equation we get
By rearranging this equation we get


<math> q= {4 pi * epsilon_0 } *{r^2}*E_{mag} </math>  
<math> q= {4 pi * \epsilon_0 } *{r^2}*E_{mag} </math>  


<math> q= {1/(9*10^9)} *{6.9^{2}}*4.76*10^{6} </math>  
<math> q= {{1/(9e9)} *{6.9^{2}}*4.76e6} </math>  


<math> q= + 0.253 C </math>  
<math> q= + 0.253 C </math></td>


</table border>


==Connectedness==
==Connectedness==
1.How is this topic connected to something that you are interested in?
''1. How is this topic connected to something that you are interested in?''
 
The electric field of a single point charge is the most basic application of the fundamental property. It is the combined electric field that results from many point charges packed in the same region that causes atomic level changes such as polarization. I am interested in the topic of polarization because it is what directs the movement of current through conductors.


2.How is it connected to your major?
The topic is fascinating because electric fields not only exist within the human body but also in the realms of aerospace. It's captivating to think about the parallels between biological systems and aerospace systems, where electric field management is crucial for functions such as propulsion and navigation. Analyzing how bodies maintain and adapt their electric fields and applying this knowledge to aerospace engineering can lead to innovative approaches to energy management and system efficiency, particularly in the face of perturbations such as equipment failure or external environmental factors.


As a BME major, I learn to work with many types of electronics that involve circuits, capacitors, and resistors, to build medical devices. The movement of current through these electronics is dependent on the presence of an electric force (caused by the electric field) on a negatively charged point charge. Specifically, my BMED 2250 group is currently designing a device that includes a capacitive touch sensor. This sensor works due to the charge transfer between two charged plates of a capacitor. The charge transfer is driven by the attraction of oppositely charged point charges and their corresponding electric fields.
''2. How is it connected to your major?''


3.Is there an interesting industrial application?
As an aerospace engineer, my interest lies in the application of principles from various sciences, including biochemistry, to improve and innovate within the field of aviation and space exploration. Understanding the role of electric fields in cellular behavior provides insights into potential analogs in aerospace technology. For instance, similar to how cells adjust their electric fields for optimal function, aerospace systems must regulate their onboard electric fields for navigation, communication, and operational efficiency. Such interdisciplinary knowledge can be the foundation for advancements in aerospace materials and systems that are responsive and adaptive to their environments.


Electric fields are actually used in tissue engineering to determine the properties of cells and tissues. They are also used in electrokinetics to assemble artificial tissues from cells.  
''3. Is there an interesting industrial application?''


PEMF (Pulsed Electromagnetic Field) therapy's principle of restoring optimal voltage in damaged cells through electromagnetic fields has interesting parallels in aerospace engineering. For example, the management of electromagnetic fields is critical in spacecraft and aircraft to protect onboard electronics and enhance communication signals. The concept of PEMF can inspire the development of systems that can self-regulate and optimize electrical potential across different components of an aircraft or spacecraft, thereby enhancing performance and resilience. Such systems could prove vital in long-duration space missions, where human intervention is limited, and the machine's ability to self-heal and maintain operational integrity can be a game-changer.


==History==
==History==
Line 242: Line 260:
===External links===
===External links===


Some more information : http://hyperphysics.phy-astr.gsu.edu/hbase/electric/epoint.html
Some more information:


http://www.physics.umd.edu/courses/Phys260/agashe/S10/notes/lecture18.pdf
*http://www.physics.umd.edu/courses/Phys260/agashe/S10/notes/lecture18.pdf
*https://www.reliantphysicaltherapy.com/services/pulsed-electromagnetic-field-pemf
*https://www.youtube.com/watch?v=HG9KxDZ-qwI&t=1s
*https://www.youtube.com/watch?v=8GJf-Fj-qoI&t=3s


==References==
==References==

Latest revision as of 15:46, 13 April 2024

Claimed by Sam Bureau Spring 2024

This page is all about the Electric Field due to a Point Charge.


The Main Ideas

(Ch 13.1 in Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood)

Point Charge/Particle - an object with a radius that is very small compared to the distance between it and any other objects of interest in the system. Since it is very small, the object can be treated as if all of its charge and mass are concentrated at a single "point".

  • Electrons and Protons are always considered to be point particles unless stated otherwise

2 types of point charges:

  • Protons (e) --> positive point charges, ( q = 1.6e-19 Coulombs)
  • Electrons (-e) --> negative point charges, (q = -1.6e-19 Coulombs)


Like point charges attract, opposite point charges repel.

ex.

Point Charges Result Diagram
1 proton, 1 electron Attract
2 protons Repel
2 electrons Repel


The Electric Field

(Ch 13.3 in Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood)

In general, the electric field evaluates the affect of the source on the surrounding objects and area. The electric field created by a charge is present throughout space at all times, whether or not there is another charge around to feel its effects. Therefore, the concept of the electric field by a point charge describes the interactions that can happen at a distance, due to these affects caused by this point charge.

Important to differentiate that Electric Force does not equal the Electric Field.

Electric Field of a Charge Observed at a location: F = Eq

  • F = Force on particle
  • E = electric field at source location
  • q = magnitude of the charge of particle (assume q= 1.6 x 10^-19 unless stated otherewise)

The magnitude of the electric field decreases with increasing distance from the point charge.

The electric field of a positive point charge points radially outward The electric field of a negative point charge points radially inward

A Mathematical Model

Electric Field due to Point Charge

(Ch 13.4 in Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood)

The magnitude of the electric field decreases with increasing distance from the point charge. This is described by the equation below:

Electric Field of a Point Charge ([math]\displaystyle{ \vec E }[/math]):

[math]\displaystyle{ \vec E=\frac{1}{4 \pi \epsilon_0 } \frac{q}{\mid\vec r\mid ^2} \hat r }[/math] (Newtons/Coulomb)

  • [math]\displaystyle{ \frac{1}{4 \pi \epsilon_0 } }[/math] is Coulomb's Constant and is approximately [math]\displaystyle{ 8.987*10^{9}\frac{N m^2}{C^2} }[/math]
  • q is the charge of the particle
  • r is the magnitude of the distance between the observation location and the source location
  • [math]\displaystyle{ \hat r }[/math] is the unit vector in the direction of the distance from the source location to the observation point.


The direction of the electric field at the observation location depends on the both the direction of [math]\displaystyle{ \hat r }[/math] and the sign of the source charge.

  • If the source charge is positive, the field points away from the source charge, in the same direction as [math]\displaystyle{ \hat r }[/math].
  • If the source charge is negative, the field points toward the source charge, in the opposite direction as [math]\displaystyle{ \hat r }[/math].

Coulomb Force Law for Point Charges

(Ch 13.2 in Matter & Interactions Vol. 2: Modern Mechanics, 4th Edition by R. Chabay & B. Sherwood)

[math]\displaystyle{ \mid\vec F\mid=\frac{1}{4 \pi \epsilon_0 } \frac{\mid Q_1Q_2 \mid}{r^2} }[/math]


Coulomb's law is one of the four fundamental physical interactions, and it describes the magnitude of the electric force between two point-charges.

  • [math]\displaystyle{ Q_1, Q_2 }[/math]= The charges of the two particles of interest
  • [math]\displaystyle{ \mid\vec F\mid=\frac{1}{4 \pi \epsilon_0 } }[/math] = constant,
  • [math]\displaystyle{ Q_1, Q_2 }[/math] = the magnitudes of the point charges
  • r = The distance between the two particles

Connection Between Electric Field and Force

The force on a source charge is determined by [math]\displaystyle{ F = Eq }[/math] where E is the electric field and q is the charge of a test charge in Coulombs.

By solving for the electric field in [math]\displaystyle{ F = Eq }[/math], with F modeled by Coulomb's Law, you get the equation for the electric field of the point charge:

[math]\displaystyle{ E = \frac{F}{q_2} = \frac{1}{4 \pi \epsilon_0 } \frac{q_1q_2}{r^2}\frac{1}{q_2}\hat r = \frac{1}{4 \pi \epsilon_0 } \frac{q_1}{r^2} \hat r }[/math]


The direction of electric force also depends on the direction of the electric field too:

  • If the source charge is positive, the field points away from the source charge, in the same direction as the electric force.
  • If the source charge is negative, the field points toward the source charge, in the opposite direction as the electric force.

Electric Field Superposition (Point Charges)

When there are multiple point charges present, the total net electric field [math]\displaystyle{ Enet }[/math], is equal to the sum of the electric field of each independent point charge present.

This is due to concept of Superposition which is when the total effect is the sum of the effects of each part.

When it comes to the Electric Field Superposition of Point Charges, be sure to remember that:

  • A charge cannot exert a force on itself
  • Assume that the source charges do not move. (Therefore [math]\displaystyle{ Fnet = 0 }[/math])


A Computational Model

Below is a link to a code which can help visualize the Electric Field at various observation locations due to a proton. Notice how the arrows decrease in size by a factor of [math]\displaystyle{ \frac{1}{r^{2}} }[/math] as the observation location gets farther from the proton. The magnitude of the electric field decreases as the distance to the observation location increases.


Two adjacent point charges of opposite sign exhibit an electric field pattern that is characteristic of a dipole. This interaction is displayed in the code below. Notice how the electric field points towards the negatively charged point charge (blue) and away from the positively charged point charge (red).

Examples

Simple

There is an electron at the origin. Calculate the electric field at <4, -3, 1> m.

Middling

A particle of unknown charge is located at <-0.21, 0.02, 0.11> m. Its electric field at point <-0.02, 0.31, 0.28> m is [math]\displaystyle{ \lt 0.124, 0.188, 0.109\gt }[/math] N/C. Find the magnitude and sign of the particle's charge.

Given both an observation location and a source location, one can find both r and [math]\displaystyle{ \hat{r} }[/math] Given the value of the electric field, one can also find the magnitude of the electric field. Then, using the equation for the magnitude of electric field of a point charge, [math]\displaystyle{ E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} }[/math] one can find the magnitude and sign of the charge.

Step 1. Find [math]\displaystyle{ \vec r_{obs} - \vec r_{particle} }[/math]:

[math]\displaystyle{ \vec r = \lt -0.02, 0.31, 0.28\gt m - \lt -0.21, 0.02, 0.11\gt m = \lt 0.19,0.29,0.17\gt m }[/math]

To find [math]\displaystyle{ \vec r_{mag} }[/math], find the magnitude of [math]\displaystyle{ \lt 0.19,0.29,0.17\gt }[/math]

[math]\displaystyle{ \sqrt{0.19^2+0.29^2+0.17^2}=\sqrt{0.1491}= 0.39 }[/math]

Step 2: Find the magnitude of the Electric Field:

[math]\displaystyle{ E= \lt 0.124, 0.188, 0.109\gt N/C }[/math]

[math]\displaystyle{ E_{mag} = (\sqrt{0.124^2+0.188^2+0.109^2}=\sqrt{0.0626}=0.25 }[/math]
Step 3: Find q by rearranging the equation for [math]\displaystyle{ E_{mag} }[/math]

[math]\displaystyle{ E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} }[/math]

By rearranging this equation we get

[math]\displaystyle{ q= {4 \pi * \epsilon_0 } *{r^2}*E_{mag} }[/math]

[math]\displaystyle{ q= {1/(9*10^9)} *{0.39^2}*0.25 }[/math]

[math]\displaystyle{ q= + 4.3*10^{-12} C }[/math]

Difficult

The electric force on a -2mC particle at a location (3.98 , 3.98 , 3.98) m due to a particle at the origin is [math]\displaystyle{ \lt -5.5*10^{3} , -5.5*10^{3}, -5.5*10^{3}\gt }[/math] N. What is the charge on the particle at the origin?

Given the force and charge on the particle, one can calculate the surrounding electric field. With this variable found, this problem becomes much like the last one. [math]\displaystyle{ E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r_{mag}^2} }[/math] to find the rmag value. To find [math]\displaystyle{ \hat r }[/math] we can find the direction of the electric field as that is obviously going to be in the same direction as [math]\displaystyle{ \hat r }[/math]. Then, once we find [math]\displaystyle{ \hat r }[/math], all that is left to do is multiply [math]\displaystyle{ \hat r }[/math] by rmag and that will give us the [math]\displaystyle{ r }[/math] vector. We can then find the location of the particle as we know [math]\displaystyle{ r=r_{observation}-r_{particle} }[/math]

Step 1. Find the magnitude of the Electric field:

[math]\displaystyle{ F = Eq }[/math] [math]\displaystyle{ = E * -2mC }[/math]

[math]\displaystyle{ E = \frac{\lt -5.5e3 , -5.5e3, -5.5e3\gt }{-2mC} = \lt 2.75e6 , 2.75e6, 2.75e6\gt }[/math] N/C

Step 2: Find [math]\displaystyle{ \vec r_{obs} - \vec r_{particle} }[/math].

[math]\displaystyle{ \vec r = \lt 3.98 , 3.98 , 3.98\gt m - \lt 0 , 0 , 0\gt m = \lt 3.98 , 3.98 , 3.98\gt m }[/math]

To find [math]\displaystyle{ \vec r_{mag} }[/math], find the magnitude of [math]\displaystyle{ \lt 3.98 , 3.98 , 3.98\gt }[/math]

[math]\displaystyle{ \sqrt{3.98^2+3.98^2+3.98^2}=\sqrt{47.52}= 6.9 }[/math]

Step 3: Find q by rearranging the equation for [math]\displaystyle{ E_{mag} }[/math]

[math]\displaystyle{ E_{mag}= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} }[/math]

By rearranging this equation we get

[math]\displaystyle{ q= {4 pi * \epsilon_0 } *{r^2}*E_{mag} }[/math]

[math]\displaystyle{ q= {{1/(9e9)} *{6.9^{2}}*4.76e6} }[/math]

[math]\displaystyle{ q= + 0.253 C }[/math]

Connectedness

1. How is this topic connected to something that you are interested in?

The topic is fascinating because electric fields not only exist within the human body but also in the realms of aerospace. It's captivating to think about the parallels between biological systems and aerospace systems, where electric field management is crucial for functions such as propulsion and navigation. Analyzing how bodies maintain and adapt their electric fields and applying this knowledge to aerospace engineering can lead to innovative approaches to energy management and system efficiency, particularly in the face of perturbations such as equipment failure or external environmental factors.

2. How is it connected to your major?

As an aerospace engineer, my interest lies in the application of principles from various sciences, including biochemistry, to improve and innovate within the field of aviation and space exploration. Understanding the role of electric fields in cellular behavior provides insights into potential analogs in aerospace technology. For instance, similar to how cells adjust their electric fields for optimal function, aerospace systems must regulate their onboard electric fields for navigation, communication, and operational efficiency. Such interdisciplinary knowledge can be the foundation for advancements in aerospace materials and systems that are responsive and adaptive to their environments.

3. Is there an interesting industrial application?

PEMF (Pulsed Electromagnetic Field) therapy's principle of restoring optimal voltage in damaged cells through electromagnetic fields has interesting parallels in aerospace engineering. For example, the management of electromagnetic fields is critical in spacecraft and aircraft to protect onboard electronics and enhance communication signals. The concept of PEMF can inspire the development of systems that can self-regulate and optimize electrical potential across different components of an aircraft or spacecraft, thereby enhancing performance and resilience. Such systems could prove vital in long-duration space missions, where human intervention is limited, and the machine's ability to self-heal and maintain operational integrity can be a game-changer.

History

Charles de Coulomb

Charles de Coulomb was born in June 14, 1736 in central France. He spent much of his early life in the military and was placed in regions throughout the world. He only began to do scientific experiments out of curiously on his military expeditions. However, when controversy arrived with him and the French bureaucracy coupled with the French Revolution, Coulomb had to leave France and thus really began his scientific career.

Between 1785 and 1791, de Coulomb wrote several key papers centered around multiple relations of electricity and magnetism. This helped him develop the principle known as Coulomb's Law, which confirmed that the force between two electrical charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. This is the same relationship that is seen in the electric field equation of a point charge.

See also

Electric Field
Electric Force
Superposition Principle
Electric Dipole

Further reading

Principles of Electrodynamics by Melvin Schwartz ISBN: 9780486134673

Electricity and Magnetism: Edition 3 , Edward M. Purcell David J. Morin

External links

Some more information:

References

Chabay. (2000-2018). Matter & Interactions (4th ed.). John Wiley & Sons.

PY106 Notes. (n.d.). Retrieved November 27, 2016, from http://physics.bu.edu/~duffy/py106.html

Retrieved November 28, 2016, from http://www.biography.com/people/charles-de-coulomb-9259075#controversy-and-absolution

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