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'''Claimed by Alex Oshin (Fall 2017)'''
==The Main Idea==
==The Main Idea==
[[Image:Pc1.png|right|thumb|A simple parallel circuit. R1 and R2 are in parallel because they lie on different branches of the circuit.|330px]]
Components of a circuit can be connected in two main ways, in series or in parallel. This page focuses on components connected in ''parallel'', which means that the components are connected such that the same voltage is applied to each component. A '''parallel circuit''' is a circuit that is connected entirely in parallel. Each component in a parallel circuit occupies its own ''branch'', or path in the circuit, and these branches are connected at locations called ''nodes''. Thus a charge passing through the circuit has multiple possible paths that it can take when it reaches a node. This property is the reason why adding an additional resistor in a parallel circuit results in a decreased total resistance of the circuit (since there is an additional path that the charges can follow). Likewise, if a path is removed, or if the circuit is broken in a single path, more charge is forced to flow through the remaining paths, and the total resistance increases.
===A Mathematical Model===
Ohm's Law is essential for understanding circuits, and in particular, the relationship between current, voltage, and resistance.
::<math>I=\frac{V}{R}</math>
The voltage is the same for all elements of a parallel circuit.
::<math>V_{total}=V_1=V_2=...=V_n</math>
The total resistance of a parallel circuit is the reciprocal of the sum of the reciprocals of the individual resistances.
::<math>\frac{1}{R_{total}}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_n}</math>
Applying Ohm's Law to these two equations, we can find an equation for the total current of a parallel circuit.
::<math>I_{total}=V(\frac{1}{R_{1}}+\frac{1}{R_{2}}+...+\frac{1}{R_{n}})</math>
And the current flowing through a component with resistance <math>R_{i}</math> will be:
::<math>I_{i}=\frac{V}{R_{i}}</math>
These results are consistent with Kirchhoff's circuit laws, and can be similarly derived.
===A Computational Model===


A schematic is the easiest way to visualize a parallel circuit, and circuits in general.


Parallel Circuit is a circuit that is connected in parallel. All components in parallel circuit are linked to the same set of electric points, and they can create several branches(individual paths) within a circuit. These individual paths provide multiple pathways to the charge, so whenever the charge encounters a branch it would travel to the lower potential. This means adding an additional resistor in a parallel circuit would result in a decreased resistance.
[[Image:pc3.png]]
In a parallel circuit, the potential difference is identical with each resistor positioned in different branches.
If a single circuit is opened(broke), no charge would flow to that path, but other paths will have charges going through them.


The circuit above contains a battery and three resistors. Notice R1, R2, and R3 occupy different branches of the circuit. They are connected by only two nodes, one at the top of the circuit and one at the bottom, even though it may seem like there are four nodes in the schematic.


In order to understand the parallel circuit, it's critical to know the main difference between series circuit and parallel circuits.
The following image shows a real-world example.
In a series circuit the current is identical through out the circuit, whereas parallel circuit has current, depending on the resistor running through the individual branch. On the other hand, in a series circuit the voltage differs,whereas in parallel circuit the voltage is same everywhere.


===A Mathematical Model===
[[File:paralleldiagram.jpeg]]


::<math>V=IR</math>
Each lightbulb acts like a resistor in the previous circuit schematic.
Using the basic Ohm's law we could determine the voltage, resistance, and current throughout the parallel resistor.


:::<math>\frac{1}{R}_{Total}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...\frac{1}{R_N}</math>
This [https://www.physicsclassroom.com/Physics-Interactives/Electric-Circuits/Circuit-Builder/Circuit-Builder-Interactive website] is a simple circuit builder that can be used to simulate circuits in parallel(or in series).


When calculating the total Reisistance in a parallel circuit, we need to know the basic principle:  
[[File:Parallel circuit2.png|500px]]


This [https://www.circuitlab.com/circuit/g2qzxs/resistors-in-series-and-parallel/ website] is a more complicated circuit builder that can also be used to model parallel or series circuits and test the differences in current, voltage, and resistance with with various setups.


'''More resistor in parallel circuit, less resistance.'''
[[File:Parallel circuit1.png|400px]]
So, we need to find the sum of reciprocals of individual resistors to derive the total resistor.


==Examples==


===Simple===


:::<math>V_{Total}=V_1=V_2=V_3...=V_N</math>
'''Question'''


In a parallel circuit, potential difference through out the circuit is equal everywhere.
Calculate the total resistance of this parallel circuit.


[[Image:pc3.png]]


:::<math>I_{Total}=I_1+I_2+I_3+...I_N</math>


In a parallel circuit, the total amount of current outside the individual branch equals to the sum of individual branches in the circuit. Thus, the individual current in each branch depends on the resistor in the branch.
'''Solution'''


[[File:Current.gif]]
Start by applying the formula for the resistance of a parallel circuit.


:::<math>\frac{1}{R}_{total}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}</math>


:::<math>I_n=I_{Total}\frac{R_{Total}}{R_n}</math>


'''Current Divider Law'''
In this case, we simply need to substitute the values of <math>R_1</math>, <math>R_2</math>, and <math>R_3</math> into the formula, and solve for <math>R_{total}</math>.
Since the current running through each branch of the circuit is dependent on the impedance of that branch, the current divider law can be used to determine the magnitude the current through each individual branch.


So if we want to find out the current in R1
:::<math>\frac{1}{R}_{total}=\frac{1}{50&Omega;}+\frac{1}{70&Omega;}+\frac{1}{100&Omega;}</math>
:::<math>I_1=I_{Total}\frac{R_{Total}}{R_1}</math>


===A Computational Model===


[[File:ParallelCircuit.jpeg]]
:::<math>{R}_{total}=22.581&Omega;</math>
 
===Middling===


This is a simple way to represent a Parallel Circuit. The schematic version is very useful when we want to compute the values, and understand the concept. R represents a resistor and the battery represents the total emf in the circuit.
'''Question'''


'''Calculate the total current of the following circuit.'''


[[Image:pc4.png]]


[[File:paralleldiagram.jpeg]]


This diagram is the actual Parallel Circuit we could see in real life. The actual battery could represent the total emf in the previous schematic sketch, and the light bulb would act as a resistor from the previous parallel circuit.
'''Solution'''


==Examples==
Start by finding the total resistance of the circuit.


These are practical examples we could solve through the formula, and the concept we've learned through this Wiki Page.
:::<math>\frac{1}{R}_{total}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_4}</math>


===Simple===


'''Calculate the total resistance of this parallel circuit.'''
:::<math>\frac{1}{R}_{total}=\frac{1}{75&Omega;}+\frac{1}{150&Omega;}+\frac{1}{25&Omega;}+\frac{1}{100&Omega;}</math>




[[File:simplep.png]]
:::<math>{R}_{total}=14.286&Omega;</math>


===Solution===
From here, we can use Ohm's Law to find the total current <math>I_{total}</math>


:::<math>\frac{1}{R}_{Total}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3} </math>
:::<math>I=\frac{V}{R}</math>


Using this formula we could derive the total resistance of a parallel circuit.
Plugging in 90 for R1, 45 for 42, and 180 for R3, we get


:::<math>{R}_{Total}=25.7143 ohm</math>
:::<math>I_{total}=\frac{V}{R_{total}}</math>


===Middling===


'''Calculate the current running through R1.'''
:::<math>I_{total}=\frac{9V}{14.286&Omega;}</math>


'''Total current running through the circuit is 5 ampere. R1= 4 ohm, and R2= 6 ohm'''


[[File:middlep.gif]]
:::<math>I_{total}=0.63A</math>


===Solution===


This problem can be solved in one step by combining Ohm's Law with what we know about the resistance of a parallel circuit (see [[#A Mathematical Model|A Mathematical Model]] above)


:::<math>I_{total}=V(\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_4})</math>


In order to find out the current running through R1, we can use the current divider law.
First calculate the total resistance.


:::<math>\frac{1}{R}_{Total}=\frac{1}{R_1}+\frac{1}{R_2}</math>
:::<math>I_{total}=(9V)(\frac{1}{75&Omega;}+\frac{1}{150&Omega;}+\frac{1}{25&Omega;}+\frac{1}{100&Omega;})</math>


Rearranging this formula we get


:::<math>{R}_{Total}=\frac{R_1R_2}{R_1+R_2}=2.4 ohm</math>
:::<math>I_{total}=0.63A</math>


Now plug in all the value to the current divider law.


:::<math>I_1=I_{Total}\frac{R_{Total}}{R_1}=3A</math>


===Difficult===
===Difficult===
'''Calculate the current running through R2.'''


'''Question'''


[[File:difficultpp.png]]
'''Calculate the total current of the following circuit.'''


[[Image:pc5.png]]




===Solution===
'''Solution'''


First we have to find out the total resistance of this circuit. Since we have both series and parallel component in the circuit, we have to add all the components to find out the total resistance.
This problem relies on understanding both series and parallel circuits. See [[Series Circuits]] if any of the following assumptions are unclear.


:::<math>R_{Parallel}=\frac{R_2R_3}{R_2+R_3} </math>
This easiest way to solve this problem is to calculate the total resistance of the circuit, and then use Ohm's Law to calculate the total current. Since resistors in series can be simplified into a single resistor with resistance equal to the sum of all the resistors in series, we can simplify the circuit by combining R1 and R5, as well as R3 and R4.
:::<math>R_{Total}=R_1+R_{Parallel}+R_4=58.75 ohm </math>


Now using the Ohm's law we could determine the total current running through the circuit.
[[Image:pc6.png]]


::<math>V_{Total}=I_{Total}R_{Total}</math>
::<math>V_{Total}=10V</math>
::<math>I_{Total}=\frac{V_{Total}}{R_{Total}}</math>
::<math>I_{Total}=0.17A</math>


We can now use the current divider law to calculate the current running through R2.
Since R2 and R3+R4 are connected in parallel, we can use what we know about parallel circuits to further simplify the circuit.


:::<math>I_1=I_{Total}\frac{R_{Total}}{R_1}=3A</math>
:::<math>\frac{1}{R}_{total}=\frac{1}{R2}+\frac{1}{R3+R4}</math>
 
 
:::<math>R_{total}=35.714&Omega;</math>
 
 
[[Image:pc7.png]]
 
 
Finally, these two simplified resistors are connected in series, so we can find the total resistance.
 
:::<math>R_{total}=(R1+R5)+(R2+R3+R4)</math>
 
 
:::<math>R_{total}=160.714&Omega;</math>
 
 
Now we can use Ohm's Law to calculate the total current.
 
:::<math>I=\frac{V}{R}</math>
 
 
:::<math>I_{total}=\frac{V}{R_{total}}</math>
 
 
:::<math>I_{total}=\frac{9V}{160.714&Omega;}</math>
 
 
:::<math>I_{total}=0.056A</math>


==Connectedness==
==Connectedness==
#How is this topic connected to something that you are interested in?
 
#How is it connected to your major?
 
#Is there an interesting industrial application?
Circuits can be applied to many areas. However, it is rare that we can find a true parallel circuit in the real world. Many times, real world examples combine both series and parallel circuits. But with some generalizations, we can find examples of parallel circuits in our everyday lives. For example, your phone's battery supplies voltage to the various components and devices within your phone, such as the processor, memory, display, etc., and these are all connected in parallel. Electricity to houses is typically set up in parallel so that one appliance or light can be used without having to use all of them(which would be necessary in series to complete the circuit). On a larger scale, electric or power grids distribute electricity in parallel to the consumers that need it.


==History==
==History==


Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.
Electric circuits would not be possible without a constant source of current. Therefore, the battery was a necessary invention for the circuit to be developed. The invention of the battery is generally attributed to Alessandro Volta, who stacked pairs of zinc and copper soaked in brine, and realized that it produced current. The SI unit for electric potential, the ''volt'', is named after him in his honor.
 
These, and all later batteries, produce ''direct current'', or DC for short, which supplies a constant current in one direction. Circuits created using these batteries are very similar to the circuits discussed on this page. In fact, these circuits formed the basis for Thomas Edison's invention of the incandescent light bulb, and later his attempt at distributing electricity across a power grid.
 
However, DC has an inherent disadvantage in that there is a large power loss over long distances due the resistance of the wires used to transport the electricity. As such, Edison's rival and contemporary Nikola Tesla used ''alternating current'', or AC, to efficiently distribute electricity over long distances. AC periodically changes direction, and this property allows it to travel long distances with little power loss, and it also generates relatively little heat during the process (another problem of DC). Using electric devices known as transformers, it is possible to change voltage levels in an AC circuit, and this forms the foundation for the electricity that is sent to your home. You will learn later about how a transformer works when you study magnetic induction.
 
After the invention of lighting, and power grids that could effectively distribute electricity, the further development of home appliances and other electric devices meant that the influence of electric circuits would continue to spread. Nowadays, it is hard to imagine how different our lives would be if we did not have electricity.


== See also ==
== See also ==


Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?
See [[Series Circuit]] for more information about simple circuits.
 
See [[RC]] to learn about how a capacitor interacts with a circuit.
 
See these topics to deepen your understanding of circuits and electricity.
:[[Ohm's Law]]
:[[Current]]
:[[Node Rule]]
:[[Loop Rule]]
:[[Power in a circuit]]


===Further reading===
===Further reading===
Introduction to Electric Circuits 9th edition James A. Svoboda Richard C. Dorf


Books, Articles or other print media on this topic
Basic Electric Circuit Theory Issaak D. Mayegoyz W.Lawson
 
Matter & Interactions Vol. II: Electric and Magnetic Interactions, 4th Edition R. Chabay B Sherwood


===External links===
===External links===


Internet resources on this topic
The following are some sites that further expand upon both series and parallel circuits.
 
*[http://www.physicsclassroom.com/class/circuits/Lesson-4/Parallel-Circuits Parallel Circuits]
*[http://www.regentsprep.org/regents/physics/phys03/bparcir/ Basics]
*[http://science.howstuffworks.com/environmental/energy/circuit3.htm History of Circuit]
*[http://www.allaboutcircuits.com/textbook/direct-current/chpt-5/what-are-series-and-parallel-circuits/ All about parallel and series circuit]
*[https://learn.sparkfun.com/tutorials/series-and-parallel-circuits Series and Parallel Circuits]
*[https://www.swtc.edu/Ag_Power/electrical/lecture/parallel_circuits.htm Parallel Circuits]
*[http://science.howstuffworks.com/environmental/energy/circuit.htm How Circuits Work]


==References==
==References==


This section contains the the references you used while writing this page
*[https://learn.sparkfun.com/tutorials/series-and-parallel-circuits Series and Parallel Circuits]
*[https://www.swtc.edu/Ag_Power/electrical/lecture/parallel_circuits.htm Parallel Circuits]
*[http://science.howstuffworks.com/environmental/energy/circuit.htm How Circuits Work]
*[https://www.physicsclassroom.com/Physics-Interactives/Electric-Circuits/Circuit-Builder/Circuit-Builder-Interactive Physics Classroom]
*[https://www.circuitlab.com/circuit/g2qzxs/resistors-in-series-and-parallel/ Circuit Lab]


[[Category:Which Category did you place this in?]]
[[Category:Simple Circuits]]

Latest revision as of 17:26, 7 November 2019

Claimed by Alex Oshin (Fall 2017)

The Main Idea

A simple parallel circuit. R1 and R2 are in parallel because they lie on different branches of the circuit.

Components of a circuit can be connected in two main ways, in series or in parallel. This page focuses on components connected in parallel, which means that the components are connected such that the same voltage is applied to each component. A parallel circuit is a circuit that is connected entirely in parallel. Each component in a parallel circuit occupies its own branch, or path in the circuit, and these branches are connected at locations called nodes. Thus a charge passing through the circuit has multiple possible paths that it can take when it reaches a node. This property is the reason why adding an additional resistor in a parallel circuit results in a decreased total resistance of the circuit (since there is an additional path that the charges can follow). Likewise, if a path is removed, or if the circuit is broken in a single path, more charge is forced to flow through the remaining paths, and the total resistance increases.

A Mathematical Model

Ohm's Law is essential for understanding circuits, and in particular, the relationship between current, voltage, and resistance.

[math]\displaystyle{ I=\frac{V}{R} }[/math]

The voltage is the same for all elements of a parallel circuit.

[math]\displaystyle{ V_{total}=V_1=V_2=...=V_n }[/math]

The total resistance of a parallel circuit is the reciprocal of the sum of the reciprocals of the individual resistances.

[math]\displaystyle{ \frac{1}{R_{total}}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_n} }[/math]

Applying Ohm's Law to these two equations, we can find an equation for the total current of a parallel circuit.

[math]\displaystyle{ I_{total}=V(\frac{1}{R_{1}}+\frac{1}{R_{2}}+...+\frac{1}{R_{n}}) }[/math]

And the current flowing through a component with resistance [math]\displaystyle{ R_{i} }[/math] will be:

[math]\displaystyle{ I_{i}=\frac{V}{R_{i}} }[/math]

These results are consistent with Kirchhoff's circuit laws, and can be similarly derived.

A Computational Model

A schematic is the easiest way to visualize a parallel circuit, and circuits in general.

The circuit above contains a battery and three resistors. Notice R1, R2, and R3 occupy different branches of the circuit. They are connected by only two nodes, one at the top of the circuit and one at the bottom, even though it may seem like there are four nodes in the schematic.

The following image shows a real-world example.

Each lightbulb acts like a resistor in the previous circuit schematic.

This website is a simple circuit builder that can be used to simulate circuits in parallel(or in series).

This website is a more complicated circuit builder that can also be used to model parallel or series circuits and test the differences in current, voltage, and resistance with with various setups.

Examples

Simple

Question

Calculate the total resistance of this parallel circuit.


Solution

Start by applying the formula for the resistance of a parallel circuit.

[math]\displaystyle{ \frac{1}{R}_{total}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3} }[/math]


In this case, we simply need to substitute the values of [math]\displaystyle{ R_1 }[/math], [math]\displaystyle{ R_2 }[/math], and [math]\displaystyle{ R_3 }[/math] into the formula, and solve for [math]\displaystyle{ R_{total} }[/math].

[math]\displaystyle{ \frac{1}{R}_{total}=\frac{1}{50&Omega;}+\frac{1}{70&Omega;}+\frac{1}{100&Omega;} }[/math]


[math]\displaystyle{ {R}_{total}=22.581&Omega; }[/math]

Middling

Question

Calculate the total current of the following circuit.


Solution

Start by finding the total resistance of the circuit.

[math]\displaystyle{ \frac{1}{R}_{total}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_4} }[/math]


[math]\displaystyle{ \frac{1}{R}_{total}=\frac{1}{75&Omega;}+\frac{1}{150&Omega;}+\frac{1}{25&Omega;}+\frac{1}{100&Omega;} }[/math]


[math]\displaystyle{ {R}_{total}=14.286&Omega; }[/math]

From here, we can use Ohm's Law to find the total current [math]\displaystyle{ I_{total} }[/math]

[math]\displaystyle{ I=\frac{V}{R} }[/math]


[math]\displaystyle{ I_{total}=\frac{V}{R_{total}} }[/math]


[math]\displaystyle{ I_{total}=\frac{9V}{14.286&Omega;} }[/math]


[math]\displaystyle{ I_{total}=0.63A }[/math]


This problem can be solved in one step by combining Ohm's Law with what we know about the resistance of a parallel circuit (see A Mathematical Model above)

[math]\displaystyle{ I_{total}=V(\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_4}) }[/math]


[math]\displaystyle{ I_{total}=(9V)(\frac{1}{75&Omega;}+\frac{1}{150&Omega;}+\frac{1}{25&Omega;}+\frac{1}{100&Omega;}) }[/math]


[math]\displaystyle{ I_{total}=0.63A }[/math]


Difficult

Question

Calculate the total current of the following circuit.


Solution

This problem relies on understanding both series and parallel circuits. See Series Circuits if any of the following assumptions are unclear.

This easiest way to solve this problem is to calculate the total resistance of the circuit, and then use Ohm's Law to calculate the total current. Since resistors in series can be simplified into a single resistor with resistance equal to the sum of all the resistors in series, we can simplify the circuit by combining R1 and R5, as well as R3 and R4.


Since R2 and R3+R4 are connected in parallel, we can use what we know about parallel circuits to further simplify the circuit.

[math]\displaystyle{ \frac{1}{R}_{total}=\frac{1}{R2}+\frac{1}{R3+R4} }[/math]


[math]\displaystyle{ R_{total}=35.714&Omega; }[/math]



Finally, these two simplified resistors are connected in series, so we can find the total resistance.

[math]\displaystyle{ R_{total}=(R1+R5)+(R2+R3+R4) }[/math]


[math]\displaystyle{ R_{total}=160.714&Omega; }[/math]


Now we can use Ohm's Law to calculate the total current.

[math]\displaystyle{ I=\frac{V}{R} }[/math]


[math]\displaystyle{ I_{total}=\frac{V}{R_{total}} }[/math]


[math]\displaystyle{ I_{total}=\frac{9V}{160.714&Omega;} }[/math]


[math]\displaystyle{ I_{total}=0.056A }[/math]

Connectedness

Circuits can be applied to many areas. However, it is rare that we can find a true parallel circuit in the real world. Many times, real world examples combine both series and parallel circuits. But with some generalizations, we can find examples of parallel circuits in our everyday lives. For example, your phone's battery supplies voltage to the various components and devices within your phone, such as the processor, memory, display, etc., and these are all connected in parallel. Electricity to houses is typically set up in parallel so that one appliance or light can be used without having to use all of them(which would be necessary in series to complete the circuit). On a larger scale, electric or power grids distribute electricity in parallel to the consumers that need it.

History

Electric circuits would not be possible without a constant source of current. Therefore, the battery was a necessary invention for the circuit to be developed. The invention of the battery is generally attributed to Alessandro Volta, who stacked pairs of zinc and copper soaked in brine, and realized that it produced current. The SI unit for electric potential, the volt, is named after him in his honor.

These, and all later batteries, produce direct current, or DC for short, which supplies a constant current in one direction. Circuits created using these batteries are very similar to the circuits discussed on this page. In fact, these circuits formed the basis for Thomas Edison's invention of the incandescent light bulb, and later his attempt at distributing electricity across a power grid.

However, DC has an inherent disadvantage in that there is a large power loss over long distances due the resistance of the wires used to transport the electricity. As such, Edison's rival and contemporary Nikola Tesla used alternating current, or AC, to efficiently distribute electricity over long distances. AC periodically changes direction, and this property allows it to travel long distances with little power loss, and it also generates relatively little heat during the process (another problem of DC). Using electric devices known as transformers, it is possible to change voltage levels in an AC circuit, and this forms the foundation for the electricity that is sent to your home. You will learn later about how a transformer works when you study magnetic induction.

After the invention of lighting, and power grids that could effectively distribute electricity, the further development of home appliances and other electric devices meant that the influence of electric circuits would continue to spread. Nowadays, it is hard to imagine how different our lives would be if we did not have electricity.

See also

See Series Circuit for more information about simple circuits.

See RC to learn about how a capacitor interacts with a circuit.

See these topics to deepen your understanding of circuits and electricity.

Ohm's Law
Current
Node Rule
Loop Rule
Power in a circuit

Further reading

Introduction to Electric Circuits 9th edition James A. Svoboda Richard C. Dorf

Basic Electric Circuit Theory Issaak D. Mayegoyz W.Lawson

Matter & Interactions Vol. II: Electric and Magnetic Interactions, 4th Edition R. Chabay B Sherwood

External links

The following are some sites that further expand upon both series and parallel circuits.

References