Energy Density: Difference between revisions

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:<math> Energy Density = \frac{\Delta U}{\Delta V} = \frac{\mathbf{E}^2 \varepsilon_0}{2} + \frac{\mathbf{B}^2}{\mu_0 2} </math>
:<math> Energy Density = \frac{\Delta U}{\Delta V} = \frac{\mathbf{E}^2 \varepsilon_0}{2} + \frac{\mathbf{B}^2}{\mu_0 2} </math>


 
Where all units have the same meanings as above. This equation demonstrates that where there are electric or magnetic fields, there is an associated Energy Density that scales with the magnitude of the field squared.
=Radiation=
=Radiation=



Revision as of 17:11, 5 December 2015

by jwilliams436

Energy Density is the idea that different objects and fields store varying amounts of energy throughout their area. Energy Density can relate to many different concepts, including fuel sources such as food or oil, however the more physics relevant element of energy density is how it relates to energy stored in Electric and Magnetic fields.

As it Relates to Electric and Magnetic Fields

Electric Field

A Moving Capcitor Plate Creating a more energy dense electric field
A Moving Capcitor Plate Creating a more energy dense electric field

The typical consideration of Energy as it relates to electric fields is the field's interaction with a particle. However, the Energy Density perspective is much more fundamental. It says that energy is physically stored in electric fields. To wrap your head around this idea, imagine a system of two oppositely charged capacitor plates in which you slowly pull one plate away from the other. In this scenario, the space where there is a sizable electric field increased, due to the energy expended by you. In this sense, energy is stored in the electric field.

Equation and Units

The equation for the Energy Density of an electric field is:

[math]\displaystyle{ Energy Density = \frac{\Delta U}{\Delta V} = \frac{\mathbf{E}^2 \varepsilon_0}{2} }[/math]


Where [math]\displaystyle{ \Delta U }[/math] is the Potential Energy, [math]\displaystyle{ \Delta V }[/math] represents the Volume, [math]\displaystyle{ \mathbf{E} }[/math] is the magnitude of the Electric Field, and [math]\displaystyle{ \varepsilon_0 }[/math] is the vacuum permittivity constant (8.85e-12).

As you can infer from the above equation, the Unit for Energy Density of an Electric Field is [math]\displaystyle{ \frac{J}{m^3} }[/math]. This comes from the fact that Energy is measured in Joules, and volume is measured in meters cubed.

Magnetic Field

In a similar manner that Energy can be stored in an electric field, there is also an energy density associated with a magnetic field. Typically, Magnetic Energy density is associated with solenoids and inductance. We won't go through the full derivation, however this concept can be visualized by imagining a circuit that includes an inducting solenoid. Because the circuit has a power going into an inductor, there is work being done. This work is translated into increasing the strong magnetic field inside of the solenoid, essentially converting energy in to a Magnetic field.

Equation and Units

The equation for the Energy Density of a Magnetic Field looks similar to the equation for the Energy Density of an Electric Field.

[math]\displaystyle{ Energy Density = \frac{\Delta U}{\Delta V} = \frac{\mathbf{B}^2}{\mu_0 2} }[/math]

Where [math]\displaystyle{ \Delta U }[/math] is the Potential Energy, [math]\displaystyle{ \Delta V }[/math] represents the Volume, [math]\displaystyle{ \mathbf{B} }[/math] is the magnitude of the Magnetic Field, and [math]\displaystyle{ \varepsilon_0 }[/math] is the magnetic permeability constant (1.25e-6).

Combination of Electric and Magnetic Energy Density

Typically, the Magnetic and Electric Energy Density Equations will be combined to form one equation that accounts for both fields.

[math]\displaystyle{ Energy Density = \frac{\Delta U}{\Delta V} = \frac{\mathbf{E}^2 \varepsilon_0}{2} + \frac{\mathbf{B}^2}{\mu_0 2} }[/math]

Where all units have the same meanings as above. This equation demonstrates that where there are electric or magnetic fields, there is an associated Energy Density that scales with the magnitude of the field squared.

Radiation

High Energy Density Physics

Sustainable Energy

There is currently a significant Global Discussion relating to the future of our energy sources. At this point, we have identified that fossil fuels such as oil or coal are not only limited, but also have an extreme negative impact on the environment. For this reason, there is an effort to find energy sources that not only are unlimited and renewable, but also provide the same amount of efficiency (Energy per volume or weight) as current fossil fuels. The problem is that fossil fuels far and away have the highest energy density of almost any current energy source. The table below shows a comparison of Energy Densities of several different popular fuel sources.

Fuel Source Energy Density (Wh/Kg) Energy Density (Wh/L)
Gasoline 9,000 13,500
Propane 6,600 13,900
Ethanol 6,100 7,850
Liquid Hydrogen 2,600 39,000
Lithium Ion Battery 250 350
Liquid Nitrogen 65 55
Compressed Air 17 34

As you can see, the three fossil fuels have much higher energy densities than the more sustainable options near the bottom. The only exception here is Pressurized Hydrogen, which is exceedingly explosive and dangerous.

For us to truly solve the issue of non-sustainable fuel, the scientists will need to find ways to increase the energy densities of non-fossil fuels before any widespread adoption of them can take place.


Path Independence

The potential difference between two locations does not depend on the path taken between the locations chosen.

A Mathematical Model

In order to find the potential difference between two locations, we use this formula [math]\displaystyle{ dV = -\left(E_x*dx + E_y*dy + E_z*dz\right) }[/math], where E is the electric field with components in the x, y, and z directions. Delta x, y, and z are the components of final location minus to the components of the initial location.

A Computational Model

How do we visualize or predict using this topic. Consider embedding some vpython code here Teach hands-on with GlowScript

Simple Example

In this example, the electric field is equal to [math]\displaystyle{ E = \left(E_x, 0, 0\right) }[/math]. The initial location is A and the final location is C. In order to find the potential difference between A and C, we use [math]\displaystyle{ dV = V_C - V_A }[/math].

Since there are no y and z components of the electric field, the potential difference is [math]\displaystyle{ dV = -\left(E_x*\left(x_1 - 0\right) + 0*\left(-y_1 - 0\right) + 0*0\right) = -E_x*x_1 }[/math]

Let's say there is a location B at [math]\displaystyle{ \left(x_1, 0, 0\right) }[/math]. Now in order to find the potential difference between A and C, we need to find the potential difference between A and B and then between B and C.

The potential difference between A and B is [math]\displaystyle{ dV = V_B - V_A = -\left(E_x*\left(x_1 - 0\right) + 0*0 + 0*0\right) = -E_x*x_1 }[/math].

The potential difference between B and C is [math]\displaystyle{ dV = V_C - V_B = -\left(E_x*0 + 0*\left(-y_1 - 0\right) + 0*0\right) = 0 }[/math].

Therefore, the potential difference A and C is [math]\displaystyle{ V_C - V_A = \left(V_C - V_B\right) + \left(V_B - V_A\right) = E_x*x_1 }[/math], which is the same answer that we got when we did not use location B.

As It Relates to Specific Energy

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