Energy and Momentum Analysis in Radiation: Difference between revisions

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Now if we assume that the speed of this charged particle is very small compared to the speed of light then we can see that the radiative energy is directly proportional to the square of the electric field of the radiation.
Also by the conservation of energy principle we know that the since the charged particle has gained energy, the radiation should have lost an equal amount of energy and therefore, the electric field E should be smaller after the pulse has accelerated the charged particle.


===A Computational Model===
===Energy Density===


How do we visualize or predict using this topic. Consider embedding some vpython code here [https://trinket.io/glowscript/31d0f9ad9e Teach hands-on with GlowScript]
 
 
'''ENERGY DENSITY IN ELECTRIC AND MAGNETIC FIELDS'''
 
<math>
\frac{Energy}{Volume} = \frac{1}{2} \epsilon_0 E^2 + \frac{1}{2} \frac{1}{\mu_0} B^2
 
</math>
 
 
 
'''ENERGY DENSITY IN ELECTROMAGNETIC RADIATION'''
 
<math>
\frac{Energy}{Volume} = \frac{1}{2} \epsilon_0 E^2 + \frac{1}{2} \frac{1}{\mu_0} (\frac{E}{c})^2 = \frac{1}{2} \epsilon_0 E^2(1 + \frac{1}{\mu_0 \epsilon_0 c^2}) = \epsilon_0 E^2
 
</math>


==Examples==
==Examples==

Revision as of 23:36, 25 November 2015

Electromagnetic Radiations in the Classical Model

Electromagnetic radiation can essentially be described as stream of photons. These photons are defined as chargeless and massless, however they have both energy and surprisingly, given their lack of mass, momentum, which can be calculated from their wave properties.

Waves were poorly understood until the 1900s, when Max Planck and Albert Einstein developed modern corrections to classical theory.

Planck theorized that "black bodies" or thermal radiators and other forms of electromagnetic radiation existed not as a continuous spectrum but rather in discrete or "quantized" form. This implied that there were only certain energy values that an electromagnetic wave could have.

In the classical model that we study now it is mentioned that electromagnetic radiation carries both momentum and energy, and can impart both energy and momentum to matter. We shall discuss these ideas in more detail.

Energy in Electromagnetic Radiation

Let's start by understanding how a pulse of electromagnetic radiation would interact with ordinary matter. To see this effect, we shall look at a single charged particle interacting with the electromagnetic radiation which is composed of perpendicular electric and magnetic fields and see what happens when the pulse of radiation goes by.

Until the pulse reaches the charged particle nothing happens. Now let's assume that the electromagnetic radiation has a width of "w" so the pulse would last for a short time (w/c) where c is the speed of light. Now upon the arrival of the pulse, the charged particle (assuming it is positive) experiences a force (F = qE, where E is the magnitude of the electric field in the electromagnetic radiation) in the direction of the electric field that comprises the radiation and this brief impulse i.e. the product of force and time duration gives the charged particle a momentum. According to the Newton's Second Law of Motion:

[math]\displaystyle{ \Delta p = p - 0 = F \Delta t = (qE)*(w/c) }[/math]

Now this interaction is over so quickly that the charged particle hardly has the time to move a significant distance in the direction of the field. However, if attach the charged particle to a spring then it will oscillate to and fro in the direction of applied force. Since the kinetic energy of the charged particle has to come from somewhere, we conclude that it was imparted to the charged particle by the radiation which means that the there must be some energy carried by the electromagnetic radiation which was transferred.

Since the momentum is proportional to the magnitude of the electric field E in the pulse, we have the following:

[math]\displaystyle{ \Delta K = K - 0 \approx \frac{p^2}{2m} = (qE \frac{w}{c})^2(\frac{1}{2m}) }[/math]

Now if we assume that the speed of this charged particle is very small compared to the speed of light then we can see that the radiative energy is directly proportional to the square of the electric field of the radiation. Also by the conservation of energy principle we know that the since the charged particle has gained energy, the radiation should have lost an equal amount of energy and therefore, the electric field E should be smaller after the pulse has accelerated the charged particle.

Energy Density

ENERGY DENSITY IN ELECTRIC AND MAGNETIC FIELDS

[math]\displaystyle{ \frac{Energy}{Volume} = \frac{1}{2} \epsilon_0 E^2 + \frac{1}{2} \frac{1}{\mu_0} B^2 }[/math]


ENERGY DENSITY IN ELECTROMAGNETIC RADIATION

[math]\displaystyle{ \frac{Energy}{Volume} = \frac{1}{2} \epsilon_0 E^2 + \frac{1}{2} \frac{1}{\mu_0} (\frac{E}{c})^2 = \frac{1}{2} \epsilon_0 E^2(1 + \frac{1}{\mu_0 \epsilon_0 c^2}) = \epsilon_0 E^2 }[/math]

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