Conservation of Charge: Difference between revisions
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A system contains two spheres of the same mass. Sphere 1 has a charge of -1C and Sphere 2 has a charge of + 5C. The two spheres are brought together, touch, and are separated again. What is the net charge on each of the two spheres? | |||
Solution: | |||
Since the two spheres have the same mass, the charge will distribute itself evenly between the two spheres. Add the two charges, then divide by 2. | |||
(-1+5)/2 = 3 C | |||
===Difficult=== | ===Difficult=== | ||
Revision as of 16:48, 5 December 2015
oduan3
Conservation of charge is the principle that the sum of the electrical charge of a closed system is constant.
The Main Idea
The idea that the net charge of a closed system is constant implies that: if a charge appears in a previously neutral system, an equal and opposite charge appears in another part of the system. Individual charges, however, can be created or destroyed.
A Mathematical Model
Given the intial and final times (Ti and Tf), the charge of a system can be described using the equation Q(Tf) = Q(Ti) + Qin - Qout
A Computational Model
How do we visualize or predict using this topic. Consider embedding some vpython code here Teach hands-on with GlowScript
Examples
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Simple
A system contains two spheres of the same mass. Sphere 1 has a charge of -1C and Sphere 2 has a charge of + 5C. The two spheres are brought together, touch, and are separated again. What is the net charge on each of the two spheres?
Solution:
Since the two spheres have the same mass, the charge will distribute itself evenly between the two spheres. Add the two charges, then divide by 2.
(-1+5)/2 = 3 C
Middling
A system contains two spheres of the same mass. Sphere 1 has a charge of -1C and Sphere 2 has a charge of + 5C. The two spheres are brought together, touch, and are separated again. What is the net charge on each of the two spheres?
Solution:
Since the two spheres have the same mass, the charge will distribute itself evenly between the two spheres. Add the two charges, then divide by 2.
(-1+5)/2 = 3 C
Difficult
Connectedness
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History
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See also
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Further reading
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