3-Dimensional Position and Motion: Difference between revisions

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===External links===
===External links===
[http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html]
[http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html]
A Mathematical Model
To program the position in VPython for an object, obj, write obj.pos=(xp,yp,zp). Here xp, yp, and zp are the x, y, and z coordinates, respectively, of the object. Velocity and acceleration are programmed similarly with obj.velocity=(xv,yv,zv) and obj.acceleration=(xa,ya,za). The x, y, and z velocity and acceleration values are xv, yv, and zv and xa, ya, and za respectively.

Revision as of 23:46, 5 December 2015

In order to be able to calculate the effect of forces on an object, you need to first be able to describe its position and motion in three dimensional space. For locating entities, we have position vectors. The change in position over time creates the velocity vector, which describes motion in space. From here, we can apply three dimensional forces.

The Main Idea

Objects, exist, move and accelerate in three dimensions, so we have to describe them in three dimensions as well.


A Mathematical Model

What are the mathematical equations that allow us to model this topic. For example [math]\displaystyle{ \lt {\frac{d\vec{x}}{dt}},{\frac{d\vec{y}}{dt}},{\frac{d\vec{z}}{dt}}\gt }[/math] is the velocity and [math]\displaystyle{ {\frac{d\vec{(velocity)}}{dt}} }[/math] is the acceleration.

A Computational Model

To program the position in VPython for an object, obj, write obj.pos=(xp,yp,zp). Here xp, yp, and zp are the x, y, and z coordinates, respectively, of the object. Velocity and acceleration are programmed similarly with obj.velocity=(xv,yv,zv) and obj.acceleration=(xa,ya,za). The x, y, and z velocity and acceleration values are xv, yv, and zv and xa, ya, and za respectively.

Examples

Here are a few examples

Simple

obj. is at position (0,0,0) meters, moving at a velocity of (-1, 4, 9) meters per second for n seconds. What is obj.'s position now? (0-n,0+4n,0+9n)=(-n,4n,9n)

Middling

obj. is at position (2,5,8) meters. Acceleration is (2, 9, 0) meters per second squared for 5 seconds. new position= (2,5,8)+(2,9,0)*1/2*5^2= (2,5,8)+(25,112.5,0)=(27,117.5,8)

Difficult

obj. starts at position [math]\displaystyle{ (1,2,1) }[/math] meters with initial velocity [math]\displaystyle{ (1,5,2) }[/math] and an acceleration of [math]\displaystyle{ (-1,4,-2) }[/math]. After four seconds, what is the position? [math]\displaystyle{ position= (initial position) + (initial velocity)*(time) + (acceleration)*1/2(time)^2 }[/math]. [math]\displaystyle{ (1,2,1) + 4*(1,5,2) + 4^2/2*(-1,4,-2)= (1,2,1)+(4,20,8)+(-8,32,-16)=(1+4-8,2+20+32,1+8-16)=(-3,54,-7) }[/math]

Connectedness

  1. How is this topic connected to something that you are interested in?

Everything we do involves three dimensional position and motion. Any force acting upon an object is doing so in three dimensions. If I throw a football, the force I use to throw it is in three dimensions, as is its position and velocity.

  1. How is it connected to your major?

I am a mechanical engineering major. As mentioned before, whenever an object is acted upon by a force, this happens in three dimensions.

  1. Is there an interesting industrial application?

Yes! Every force is in three dimensions, as is every object and its movement.

See also

External links

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