Momentum with respect to external Forces: Difference between revisions

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Claimed by vkt3
Claimed by vkt3
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Short Description of Topic


==The Main Idea==
==The Main Idea==
Line 19: Line 15:


==Examples==
==Examples==
Standing on Earth, you throw a small rock with a mass of 0.5 kg into the air. At the instant it leaves your hand, the rock's velocity is <math> \vec{0.1,4.0,0.3} {m/s}<\math> Ignore air resistance.
Standing on Earth, you throw a small rock with a mass of 0.5 kg into the air. At the instant it leaves your hand, the rock's velocity is v=<0.1,4.0,0.3> m/s Ignore air resistance.


a. Initial Momentum?
a. Initial Momentum?
<math>m=0.5, \vec{v}={0.1,4,0.3}, \vec{p}={0.05,2,0.15} {kgm/s} <\math>
m=0.5, v=<0.1,4,0.3> p=<0.05,2,0.15> kgm/s


==Connectedness==
b.Rock's momentum after 0.25 seconds?
#How is this topic connected to something that you are interested in?
pf=pi+Fnet(deltat)
#How is it connected to your major?
#Is there an interesting industrial application?


==History==
pf=<0.05,2,0.15>+<0,(-9.8)(0.5),0>(0.25)=<0.05,2,0.15>+<0,-1.225,0>=pf
pf=<0.05,0.775,0.15> kgm/s


Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.
c.Calculate the average velocity of the rock from just after it leaves your hand to 0.25 seconds later.
p=mv, v=p/m


== See also ==
vf=(pf/m)=(1/0.5)<0.05,0.775,0.15>=vf
vf=<0.1,1.55,0.3>m/s
vavg=(vi+vf)/2 = (0.5)*[<0.1,4,0.3> + <0.1,1.55,0.3>]= (0.5)<0.2,5.55,0.6>=
vavg=<0.1,2.775,0.3>m/s


Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?
d. If a rock's initial position just as it leaves your hand is <0,1.2,0>m, find the vector position of the ball after 0.25 seconds.


===Further reading===
ri=<0,1.2,0>m
rf=ri+vavg(deltat)= <0,1.2,0>+<0.1,2.775,0.3>(0.25)=
<0,1.2,0>+<0.025,0.694,0.075>=
rf=<0.025,1.894,0.075>


Books, Articles or other print media on this topic
==Connectedness==
This topic is the basis behind calculating most forms of linear movement with simple forces. While a simple formula, this equation is a powerful tool as that it can include any number of forces acting on a system, and show the change in momentum of an object.


===External links===
This equation can be used to calculate the simple movements of objects in the vacuum of space with respect to the magnitude of forces acting upon the system.
[http://www.scientificamerican.com/article/bring-science-home-reaction-time/]


==History==


==References==
The Momentum Principle was born from Newton's First Law which states that an object at rest will remain at rest, and an object in motion will remain in motion unless acted upon by an external force.


This section contains the the references you used while writing this page


[[Category:Which Category did you place this in?]]
[[Category:Momentum Principle]]

Revision as of 21:30, 6 December 2015

Claimed by vkt3

The Main Idea

Momentum in an open system, is fundamentally different from that within a closed system. No longer do individual elements of a system's momentum equal to each other symettrically to add up to 0, however, they will have to even out to the magnitude of the added Force.


A Mathematical Model

They equation expressing this idea is [math]\displaystyle{ {\frac{d\vec{p}}{dt}}_{system} = \vec{F}_{net} }[/math] where p is the momentum of the system and F is the net force from the surroundings.

A Computational Model

How do we visualize or predict using this topic. Consider embedding some vpython code here Teach hands-on with GlowScript

Examples

Standing on Earth, you throw a small rock with a mass of 0.5 kg into the air. At the instant it leaves your hand, the rock's velocity is v=<0.1,4.0,0.3> m/s Ignore air resistance.

a. Initial Momentum? m=0.5, v=<0.1,4,0.3> p=<0.05,2,0.15> kgm/s

b.Rock's momentum after 0.25 seconds? pf=pi+Fnet(deltat)

pf=<0.05,2,0.15>+<0,(-9.8)(0.5),0>(0.25)=<0.05,2,0.15>+<0,-1.225,0>=pf pf=<0.05,0.775,0.15> kgm/s

c.Calculate the average velocity of the rock from just after it leaves your hand to 0.25 seconds later. p=mv, v=p/m

vf=(pf/m)=(1/0.5)<0.05,0.775,0.15>=vf vf=<0.1,1.55,0.3>m/s vavg=(vi+vf)/2 = (0.5)*[<0.1,4,0.3> + <0.1,1.55,0.3>]= (0.5)<0.2,5.55,0.6>= vavg=<0.1,2.775,0.3>m/s

d. If a rock's initial position just as it leaves your hand is <0,1.2,0>m, find the vector position of the ball after 0.25 seconds.

ri=<0,1.2,0>m rf=ri+vavg(deltat)= <0,1.2,0>+<0.1,2.775,0.3>(0.25)= <0,1.2,0>+<0.025,0.694,0.075>= rf=<0.025,1.894,0.075>

Connectedness

This topic is the basis behind calculating most forms of linear movement with simple forces. While a simple formula, this equation is a powerful tool as that it can include any number of forces acting on a system, and show the change in momentum of an object.

This equation can be used to calculate the simple movements of objects in the vacuum of space with respect to the magnitude of forces acting upon the system.

History

The Momentum Principle was born from Newton's First Law which states that an object at rest will remain at rest, and an object in motion will remain in motion unless acted upon by an external force.