Point Charge: Difference between revisions
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==Examples== | ==Examples== |
Revision as of 18:08, 24 October 2015
This page is all about the Electric Field due to a Point Charge.
Electric Field
A Work In Progress by Brandon Weiner: bweiner6
A Mathematical Model of Electric Field due to Point Charge
The Electric Field of a Point Charge can be found by the formula:
[math]\displaystyle{ \vec E=\frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} \hat r,\text{where } \frac{1}{4 \pi \epsilon_0 } \text{is approximately } 9*10^{9} \text{, q is the charge of the particle, r is the magnitude of the distance between the point charge and the observation point, and } }[/math] [math]\displaystyle{ \hat r \text { is the direction of the distance from the point charge to the observation point.} }[/math]
A Computational Model
How do we visualize or predict using this topic. Consider embedding some vpython code here Teach hands-on with GlowScript
<verbatim> <iframe src="https://trinket.io/embed/glowscript/cf036f65f7?start=result" width="100%" height="600" frameborder="0" marginwidth="0" marginheight="0" allowfullscreen></iframe> </verbatim>
Examples
Be sure to show all steps in your solution and include diagrams whenever possible
Simple
Problem 1: There is a proton at <1,2,3>. Calculate the electric field at <2,-1,3>.
Step 1: Find [math]\displaystyle{ \hat r }[/math]
Find [math]\displaystyle{ \vec r_{obs} - \vec r_{proton} (\lt 2,-1,3\gt - \lt 1,2,3\gt = \lt 1,-3,0\gt ) }[/math]
Calculate the magnitude of r. ([math]\displaystyle{ \sqrt{1^2+(-3)^2+0^2}=\sqrt{10} }[/math]
From r, find the unit vector [math]\displaystyle{ \hat{r}. }[/math] [math]\displaystyle{ \lt \frac{1}{\sqrt{10}},\frac{-3}{\sqrt{10}},\frac{0}{\sqrt{10}}\gt }[/math]
Step 2: Find the magnitude of the Electric Field
[math]\displaystyle{ E= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} = \frac{1}{4 \pi \epsilon_0 } \frac{1.6 * (10^{-19})}{10} }[/math]
Step 3: Multiply the magnitude by [math]\displaystyle{ \hat{r} }[/math] to find the Electric Field
Middling
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