Collisions: Difference between revisions
Richardtz12 (talk | contribs) |
Richardtz12 (talk | contribs) |
||
Line 139: | Line 139: | ||
== See also == | == See also == | ||
[[Maximally Inelastic Collision]] , [[Inelastic Collisions]] , [Elastic Collisions] | |||
===Further reading=== | ===Further reading=== |
Revision as of 16:36, 17 April 2016
SECOND EDIT BY SUNGJAE HYUN IN 2016-04-16 ADDITIONS MADE BY (currently in progress, adding computational model and difficult problem) Sam Webster 4-17-16
This topic covers Collisions, a comprehensive way to combine the Momentum and Energy Principles.
The Main Idea
Collisions are special types of contact interactions between objects. From a physics standpoint, collisions are a way to combine the Momentum and Energy Principles. In the case of collisions, if we choose a system of the two objects interacting, the change in momentum of the system and the change in energy of the system are both zero. With this in mind, calculations with collisions become very simple. We are able to choose a system of only the two objects (excluding external forces such as the Earth's gravity) because the collision takes place during such a short time that the external forces have a negligible effect. There are two types of collisions, Elastic Collisions and Inelastic Collisions.
A Mathematical Model
[math]\displaystyle{ {E}_{f} = {E}_{i} }[/math] where [math]\displaystyle{ {E}_{f} }[/math] is the total final energy of the system and [math]\displaystyle{ {E}_{i} }[/math] is the total initial energy of the system.
[math]\displaystyle{ {p}_{f} = {p}_{i} }[/math] where [math]\displaystyle{ {p}_{f} }[/math] is the total final momentum of the system and [math]\displaystyle{ {p}_{i} }[/math] is the total initial momentum of the system.
A Computational Model
The following situation was used for this model created using python:
Two objects are initially moving towards a third stationary object. Object 1 (in red) at position (-10,0,-2)m has a mass of 2kg and velocity (10,0,2)m/s. Object 2 (in blue) at position (0,6,3)m has a mass of 4kg and velocity (0,-6,3)m/s. Object 3 (in orange) at the origin has a mass of 5kg. The objects collide at the origin and after the collision it is observed that object 1 has embedded in object 3 (hence it is no longer visible in the model) and the combined object moves with velocity (5,-6,0)m/s (This is an example of a Maximally Inelastic Collision). The final velocity of object 2 is calculated and used in the rest of the simulation. (NOTE: the white sphere visible after the collision represents the origin to add dimension to the model and the delay during the collision is there to emphasis when and where the collision happens. Also use the link below the model for a more detailed explanation of the calculations and concepts.).
Check out the code used for the simulation at [1]. The code is commented pretty heavily (but it does assume some knowledge of python and python animations) in hopes that future students can modify some of the variables to experiment with creating different results.
Examples
Be sure to show all steps in your solution and include diagrams whenever possible
Simple
Example 1) A 0.5 kg soccer ball is moving with a speed of 5 m/s directly toward to 0.7 kg basket ball which is at rest. When two balls collide and stick together what will their final velocity be?
___
m1 = 0.5 kg, v1 init = 5 m/s, m2 = 0.7 kg, v2 init = 0 m/s
So m1 * v1 + m2 * + v2 = (m1 + m2) * vfinal
LHS = 0.5 * 5 + 0.7 * 0 = 2.5 kg*m/s RHS = (0.5 + 0.7) * vfinal = 1.2 * vfinal
LHS = RHS in inelastic collision
2.5 = 1.2 * vfinal
vfinal = 2.5 / 1.2 = 2.08333
Thus, the final velocity is 2.08 m/s. Since the two balls stick together, this is an example of a Maximally Inelastic Collision.
Middling
Example 2) A bullet of 50 caliber machine gun is 42 grams. It strikes a wooden target block of mass 10 kg stationed on a friction-less surface. The wooden block gains velocity of 1.8 m/s after being embedded with the bullet. What was the velocity of the bullet before it collided with the target?
m1 = 42/1000 = 0.042 kg, v1 init = ?, m2 = 10 kg, v2 init = 0, mfinal(m1+m2) = 0.042kg + 10kg, vfinal = 1.8 m/s
m1 * v1 init + m2 * v2 init = (m1 + m2) * vfinal
0.042 kg * v1 init = (0.042 + 10) * 1.8 m/s v1 init = 18.0756 / 0.042 = 430.37 m/s
Final Answer: The bullet's speed is 430.37 m/s.
Difficult
Example 3) Two rocks in space are approaching a third stationary rock. Rock 1 has mass 30kg moves with velocity (13,-10,-2)m/s. Rock 2 has mass 60kg and moves with velocity (-3,23,3)m/s. Rock 3 has mass 35kg and is stationary. The rocks collide at rock 3's location. After the collision it is observed that Rock 1 has embedded into Rock 3, but a chunk of mass 15kg has broken off of the combined rock, Rock 3'. It is also noticed that Rock 2 is now moving with velocity (-2,12,2)m/s. (NOTE: due to the difficulty and use of three dimensions it is suggested to use a computer to solve this problem. Therefore the sample solution will involve code, but conceptually everything remains the same.)
First determine the momentum of Rock 3' plus the momentum of the 15kg chunk.
Solution to Question 1
#KNOWNS
m1i = 30 #initial mass object 1 in kg
v1i = vector(13,-10,-2) #initial velocity object1 in m/s
m2i = 60 #initial mass object 2 in kg
v2i = vector(-3,23,3) #vinitial elocity object 2 in m/s
m3i = 35 #initial mass object 3 in kg
v3i = vector(0,0,0) #initial velocity object 3 in m/s
- OBJECTS (Spheres representing the point particle col
o1 = sphere(pos = vector(-13,10,2), radius = .5, color = color.red) #object 1
o1.v = v1i
o1.m = m1i
o1.p = o1.v*o1.m
o2 = sphere(pos = vector(3,-23,-3), radius = 1, color = color.blue) #object 2
o2.v = v2i
o2.m = m2i
o2.p = o2.v*o2.m
o3 = sphere(pos = vector(0,0,0), radius = .55, color = color.orange) #object 3
o3.v = v3i
o3.m = m3i
o3.p = o3.m*o3.v
Later Rock 3' is observed moving with velocity (x,y,z), what is the velocity of the 15kg chunk?
With the information you know, determine the combined change in internal energy for all of the rocks.
Connectedness
Collisions are interesting phenomenons that are applicable to everyday situations. Some examples are when a bat collides with a baseball in your neighbor's backyard, two cars crashing in the highway in front of you, and two linebackers running into each-other at your local College's spring football game. Depending on the type of collision, you can predict if there will be a change in internal energy (thermal energy, chemical energy etc.). Another very interesting application of collisions is in the field of astronomy. The universe is ever-changing and we never know what might come our way. A large meteor could be flying at the Earth with a very high speed and we could use our knowledge of collisions to find out how the Earth will move after the collision, what the temperature change of the area would be, and how the rest of the Earth would be effected by the collision. By using our collision skills, we could evacuate anyone who is prone to harm during the collision.
Knowledge of collisions is also a must for many engineering majors. Industrial engineers must take in collisions when they are trying to optimize complex systems. For instance, an Industrial engineer must make sure that the bridge he or she builds can withstand the forces the cars can exert on it. Architects and Civil engineers must design houses in a certain way so that slight collisions with other objects won't completely knock the house down. And of course, Mechanical engineers and Aerospace engineers must take into account collisions when designing and maintaining mechanical systems.
History
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.
See also
Maximally Inelastic Collision , Inelastic Collisions , [Elastic Collisions]
Further reading
Books, Articles or other print media on this topic
External links
Internet resources on this topic
References
This section contains the the references you used while writing this page