Conductivity and Resistivity

'This page was constructed from an amalgamation of Conductivity and Resistivity, then edited by Elizabeth Pettit, Fall 2020'

Conductivity is the degree to which a specified material conducts electricity, calculated as the ratio of the current density in the material to the electric field that causes the flow of current. Resistivity is the reciprocal of conductivity, and so the two are interchangeable as long as one tracks the inversions (and, correspondingly, the units). Electrical conductivity tells us how well a material will allow electricity to travel through it, and is similar to thermal conductivity, which tells us the ease with which thermal energy (heat for most purposes) can move through the material.

Main Idea

A conductor is a material which gives very little resistance to the flow of an electric current. Correspondingly, an insulator is a material which is very resistant to the flow of electric current. Semiconductors are materials which display the properties of both conductors and insulators. The most common example of conductive materials are metals, while insulators include materials such as wood or plastics . Semiconductors are generally more rare, but are necessary for the construction of transistors, and as such are present in all computers, with the most common being doped silicon. In addition to these categories, there are superconductors, which have zero resistance under certain conditions (generally extremely low temperatures and/or extremely high pressures), and there also exist a host of other materials with odd behaviors.

The units for conductivity and resistivity are most naturally expressed in terms of the recognizable Ohm ([math]\displaystyle{ \Omega }[/math]). Resistivity has units of [math]\displaystyle{ \Omega \cdot m }[/math], so conductivity has units of [math]\displaystyle{ \frac{1}{\Omega \cdot m} }[/math]. Expressed in terms of SI base units, the unit of resistivity becomes [math]\displaystyle{ \frac{kg\cdot m^3}{s^3\cdot A^2} = \frac{kg\cdot m^3}{s\cdot C^2} }[/math].

Mathematical Method

First, we have the relation between conductivity and resistivity:

[math]\displaystyle{ \sigma = \frac{1}{\rho} }[/math]

By convention, we have [math]\displaystyle{ \sigma }[/math] as the conductivity, and [math]\displaystyle{ \rho }[/math] as the resistivity.

Resistivity geometry

Conductivity and Resistivity are properties of a material, dependent primarily on its chemical composition and structure, but also on its temperature and other environmental factors. As such, for our purposes it will always be either a know value, plugged into an equation, or an unknown value, derived from that equation. Our interest is therefore in those equations. The first is on the idealized relation between resistivity and resistance:

[math]\displaystyle{ R = \frac{\rho L}{A} }[/math]

In this, resistance is [math]\displaystyle{ R }[/math], the length of the wire is [math]\displaystyle{ L }[/math], [math]\displaystyle{ rho is equal to resistivity and \lt math\gt A }[/math] is its cross sectional area. This assumes that there is a clearly defined length (parallel to the direction of current flow) and cross sectional area (perpendicular to the direction of current flow). Naturally, this is exactly the scenario present in a standard wire. The next two relevant equations are two statements of the same fact, which we call Ohm's law. Precisely, it governs the relationship between the flow of charge and the electric field which produces that flow. The first form states this explicitly:

Through this equation, the "skin effect" is produced. The skin efect consists of an explantaion for the relationship between the current density and the radius of a wire. It explains that the thicker the wire (the bigger the radius), the larger the current density.

[math]\displaystyle{ \vec{J} = \sigma \vec{E} }[/math]

Here [math]\displaystyle{ \vec{J} }[/math] is the current density, and [math]\displaystyle{ \vec{E} }[/math] is the electric field as we've seen before. An aside on current density: it is the amount of charge which passes through a given cross sectional area in a given period of time, with SI units [math]\displaystyle{ \frac{A}{m^2} = \frac{C}{m^2 \cdot s} }[/math]. This means that it is a density with area in the denominator, which can be confusing. Given what one has learned so far, this is the operable definition of Ohm's Law. However, another version is more frequently used later on, and so will also be given here:

[math]\displaystyle{ V = I R }[/math]

where [math]\displaystyle{ V }[/math] is the electric potential, [math]\displaystyle{ I }[/math] is the current, and [math]\displaystyle{ R }[/math] is resistance as defined before.

Computational Method

This topic is largely conceptual and algebraic, so there is relatively little modelling to be done. However, this program is designed to create plots of the relationship between resistance, resistivity, length and cross sectional area. Furthermore, this external program provides a good visual demonstration of the relationship (but unfortunately the source code is not accessible).

Examples

Simple

An material has a resistivity of [math]\displaystyle{ 200 \; \Omega\cdot m }[/math]. What is its conductivity?

Solution

Since conductivity is the reciprocal of resistivity,

[math]\displaystyle{ \sigma = \frac{1}{\rho} = \frac{1}{200 \; \Omega \cdot m} = 0.005 \frac{1}{\Omega \cdot m} }[/math]

Middling

An electric potential of [math]\displaystyle{ 120 V }[/math] is applied to a circular wire of length [math]\displaystyle{ 2 \cdot 10^4 \; m }[/math] and radius [math]\displaystyle{ 0.001 m }[/math]. The current is equal to [math]\displaystyle{ 1.11 \; A }[/math]. Determine the resistivity, and match it to an elemental metal using an appropriate table (such as )

Solution

We have Ohm's Law

[math]\displaystyle{ V = I R }[/math]

and so plugging in our definition for resistance in terms of resistivity gives that

[math]\displaystyle{ V = \frac{I \rho L}{A} }[/math]

which we rearrange to get

[math]\displaystyle{ \rho = \frac{ V A}{I L} }[/math]

plugging all of the values in gives an answer of [math]\displaystyle{ \rho = 1.7 \cdot 10^{-8} \; \Omega \cdot m }[/math], which is the resistivity of copper.

Difficult

One cubic meter of a fictional material with resistivity [math]\displaystyle{ \rho = 10^{-5} \; \Omega \cdot m }[/math] is formed into a shape with uniform cross sectional area (such that volume is equal to the base times the height) for which the resistance to current run lengthwise is equal to [math]\displaystyle{ 10 \; \Omega }[/math]. Determine the dimensions (length and cross sectional area) of the shape, presuming that it follows Ohm's law and the equation for resistance given above.

Solution

As the clarification hints, it is necessary to use a little basic geometry to solve this problem, namely

[math]\displaystyle{ V = L \cdot A }[/math]

So we lay out the standard formula

[math]\displaystyle{ R = \frac{\rho L}{A} }[/math]

Then multiply both numerator and denominator by [math]\displaystyle{ L }[/math] to obtain

[math]\displaystyle{ R = \frac{\rho L^2}{A L} = \frac{\rho L^2}{V} }[/math]

From here it is simply rearrangement to find that

[math]\displaystyle{ L = \sqrt{\frac{R V}{\rho}} = \sqrt{\frac{(1 \;m^3)(10 \;\Omega)}{10^{-5} \; \Omega \cdot m }} = 10^2 \; m }[/math]

With the length determined, it is then straightforward to conclude that [math]\displaystyle{ A = 10^{-2} \; m^2 }[/math], and the cross-section can take any shape which has that enclosed area.

Connectedness

[A student should fill this out] Every time an electrical system has been created, an understanding of conductivity and resistivity had to be determined.

since conductivity and resistivity are related, it is reasonable to assume that wires or components with low electric resistivity make good conductors as they have a great ability to transmit electricity and heat and wires or components with high electric resistivity make bad conductors.

This is important in many real life applications, some of which include:

Home insulation: materials with high resistivity so the temperature of your house is maintained.

Cooking: Pots, pans, and other metallic objects are used to cook food. This is because the food is placed on the pan, which due to its low resistivity resulting from the metal's free electrons. As the resistivity is low, there is high conductivity and the heat from a stove would be able to easily reach the food on the pan without having to place the food directly onto the stove's surface.

Electronic Devices: Electronic devices rely on the transportation of currents to create electricity that powers the device. However, one problem with many electronic devices is they are prone to overheating. In order to regulate the temperature created by the constant usage of energy in the device, materials in the machine can be surrounded or replaced with highly resistive materials to slow the conductance of the current.

To measure conductivity, a sample of the material is placed in between two metallic electrodes, either made of copper or granite *******************

https://gpg.geosci.xyz/_images/electrode_conductivity_measurements1.png

Resistivity geometry

Resistivity geometry

History

The first scientist to contribute substantially to the study of conductivity and resistivity was Stephen Gray, who with his friend Ganvil Wheler noticed that electricity could be transmitted a distance, and that the effectiveness of this transmission varied between a wire of silk and wire of brass . A substantial amount of discovery then followed, including the famous contributions of Benjamin Franklin, but these developments are more relevant to other subjects. It was in the early 19th century that the equation for determining resistance from resistivity and geometry was determined by Antoine Becquerel (grandfather to Henri Becquerel, who was a pioneer in radioactivity alongside Marie Skłodowska Curie and Pierre Curie). Not long after, Georg Ohm proposed an incorrect theorem for the relation between current, potential and resistance, then soon amended it to the correct formula. The correction, philosophical differences, and confusion at the time about the definitions of resistance, current and potential led his work to be poorly received at first, but ultimately accepted and celebrated about 15 years after its release.

See Also

If you are interested in learning more about this topic or want further clarification about concepts, check out these resources!

Further reading

The textbook Matter and Interaction by Chabay and Sherwood has some discussion of conductivity and resistivity:

• Chapter 14 discusses conductors and insulators with some specifics about polarization and charge. Page 548 includes a specific definition for both.
• Page 771 talks about conductivity
• Page 773 talks about resistance in relation to conductivity and geometry
• Page 775 talks about semiconductors

The textbook Electricity and Magnetism by Purcell also covers conductivity and resistivity:

• Chapter 3.1 covers conductors and insulators
• Chapter 4.6 covers semiconductors

External links

• Table of electrical resistivity and conductivity values for different materials: https://www.thoughtco.com/table-of-electrical-resistivity-conductivity-608499
• Resistivity and conductivity explanation: http://hyperphysics.phy-astr.gsu.edu/hbase/electric/resis.html
• Khan Academy video on resistivity and conductivity https://www.khanacademy.org/science/ap-physics-1/ap-circuits-topic/current-ap/v/resistivity-and-conductivity