Magnetic Force: Difference between revisions
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===A Mathematical Model=== | ===A Mathematical Model=== | ||
The force that a particle | The force (that a particle will experience), where the charge is given by ''q'', velocity <math>{\vec{v}}</math>, that is in the presence of a magnetic field <math>{\vec{B}}</math>, is given by the following: | ||
<math>{\vec{F} = q\vec{v}\times\vec{B}}</math> | <math>{\vec{F} = q\vec{v}\times\vec{B}}</math> | ||
Therefore, for a particle | |||
===A Computational Model=== | ===A Computational Model=== | ||
Revision as of 00:19, 3 December 2015
Authored by TheAstroChemist (This page was claimed first by TheAstroChemist - check the page history)
The Main Idea
We know so far that an electric field will act on a charged particle in a specific manner. In effect, a charged particle in the vicinity of any electric field will undergo a force based upon the magnitude and sign of the charged particle. This electric field is generated regardless of whether the charge is stationary or moving.
In the case of a moving charged particle, it is also known to generate a magnetic field. Whenever any charge maintains some velocity, it will necessarily produce a magnetic field. This applies whether you're dealing with a single point charge or a charge distribution such as a uniformly charged rod or disk.
Now, you might reasonably guess that because an electric field brings about a force on a charged particle, then so too a magnetic field should bring about a force on a particle. However, in order for a magnetic field to implement this force, the particle of interest must be moving. These two forces (electric and magnetic) can be combined to be known as the Lorentz Force, but that will be covered in further detail later. For now, we shall only focus on the specifics of the magnetic force and ignore the effects of an electric field on our system of interest.
A Mathematical Model
The force (that a particle will experience), where the charge is given by q, velocity [math]\displaystyle{ {\vec{v}} }[/math], that is in the presence of a magnetic field [math]\displaystyle{ {\vec{B}} }[/math], is given by the following:
[math]\displaystyle{ {\vec{F} = q\vec{v}\times\vec{B}} }[/math]
Therefore, for a particle
A Computational Model
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