Electric Dipole: Difference between revisions
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An '''Electric Dipole''' is a pair of equal and opposite [[Point Charge]]s separated by a small distance. | An '''Electric Dipole''' is a pair of equal and opposite [[Point Charge]]s separated by a small distance. | ||
claimed by [[User:Jmorton32|Jmorton32]] ([[User talk:Jmorton32|talk]]) 02:52, 19 October 2015 (EDT) | |||
==Mathematical Models== | ==Mathematical Models== |
Revision as of 01:52, 19 October 2015
An Electric Dipole is a pair of equal and opposite Point Charges separated by a small distance.
claimed by Jmorton32 (talk) 02:52, 19 October 2015 (EDT)
Mathematical Models
An Exact Model
Since an electric dipole is made up of 2 electric point charges, the electric field of the dipole can be calculated by summing the electric fields contributed by each point charge. In the example, the field at point P, [math]\displaystyle{ E_{P} }[/math] is equivalent to the sum of the electric field from the positive charge [math]\displaystyle{ q+ }[/math] and the negative charge [math]\displaystyle{ q- }[/math]. In other words, [math]\displaystyle{ E_{P} = E_{P_{q+}} + E_{P_{q-}} }[/math].
Substituting in the equation for the electric field from a point charge we get [math]\displaystyle{ \vec E_{P} = \frac{1}{4\pi\epsilon_{0}} \times \frac{q_{+}}{|r_{+}|^{2}} \times \hat r_{+} + \frac{1}{4\pi\epsilon_{0}} \times \frac{q_{-}}{|r_{-}|^{2}} \times \hat r_{-} }[/math].
A simple refactoring gives [math]\displaystyle{ \vec E_{P} = \frac{1}{4\pi\epsilon_{0}} \times (\frac{q_{+}}{|r_{+}|^{2}}\hat r_{+} + \frac{q_{-}}{|r_{-}|^{2}} \hat r_{-}) }[/math].
[math]\displaystyle{ |r_+| \text{and} |r_-| }[/math] can then be calculated as [math]\displaystyle{ |r_+| = \sqrt{(|r_x| + \frac{d}{2})^2 + |r_y|^2} }[/math], by decomposing [math]\displaystyle{ \vec r }[/math] into its components and factoring.
By a similar method, [math]\displaystyle{ |r_-| = \sqrt{(|r_x| - \frac{d}{2})^2 + |r_y|^2} }[/math].
By substituting [math]\displaystyle{ |\vec r| \cos(\theta) \text{ and } |\vec r| \sin(\theta) }[/math] for [math]\displaystyle{ |r_x| \text{ and } |r_y| }[/math] respectively, we get
[math]\displaystyle{ |r_+| = \sqrt{(|\vec r| \cos(\theta) + \frac{d}{2})^2 + (|\vec r| \sin(\theta))^2} }[/math] and [math]\displaystyle{ |r_-| = \sqrt{(|\vec r| \cos(\theta) - \frac{d}{2})^2 + (|\vec r| \sin(\theta))^2} }[/math]
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