Maximally Inelastic Collision: Difference between revisions

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:: <math> {ΔE_k} + {ΔU} = 0 </math> which we can break into the initial and final components to get: <math> {ΔU} = -({K_{final}} - ({K_{initial,1}} + {K_{initial,2}})) </math>
:: <math> {ΔE_k} + {ΔU} = 0 </math> which we can break into the initial and final components to get: <math> {ΔU} = -({K_{final}} - ({K_{initial,1}} + {K_{initial,2}})) </math>
Kinetic Energy for objects that have a velocity smaller than the speed of light is defined as <math> \frac{1}{2}{mv^2} </math>, so putting in the values for mass and velocity we get that:
Kinetic Energy for objects that have a velocity smaller than the speed of light is defined as <math> \frac{1}{2}{mv^2} </math>, so putting in the values for mass and velocity we get that:
:: <math> {ΔU} = \frac{1}{2}{(m_1 v_1 +m_2 v_2)^2}{m_1+m_2} - (\frac{1}{2}{m_1 (v_1)^2} + \frac{1}{2}{m_2 (v_2)^2} </math>
:: <math> {ΔU} = \frac{1}{2}{(m_1 v_1 +m_2 v_2)^2}{m_1+m_2} - (\frac{1}{2}{m_1 (v_1)^2} + \frac{1}{2}{m_2 (v_2)^2}) </math>


===A Computational Model===
===A Computational Model===

Revision as of 13:25, 24 November 2015

This topic covers Maximally Inelastic Collisions. claimed by apatel404

The Main Idea

A collision is a brief interaction between large forces. This could include two objects or several depending on the situation and how they collide is important. Collisions can be either inelastic,elastic, or maximally inelastic which is a subset of inelastic. Inelastic collisions occur when the object's kinetic energies are not conserved in the final and initial state. In maximally inelastic collisions, the objects in the system collide and stick together to form one object which has a new velocity and the mass of the object is the total mass of all the objects that have now combined into one.

A Mathematical Model

Maximally Inelastic Collisions can be based off the fundamental principle of momentum:

[math]\displaystyle{ {\frac{d\vec{p}}{dt}}_{system} = \vec{F}_{net}{Δt} }[/math]

where p is the momentum of the system, F is the net force from the surroundings, Δt is the change in time for the process.

Using the principle of momentum, one can derive the final velocity of the object where the two initial objects have combined to become one since the interaction between the objects is brief so, [math]\displaystyle{ {Δt} ≈ {0} }[/math]. So rewriting the equation with the concept that the change in time is 0 yields:

[math]\displaystyle{ {ΔP_{system}} = {0} }[/math] where we can break the change in momentum of the system to it's initial and final components to get: [math]\displaystyle{ {P_{final}} = {P_{initial}} }[/math].

Now if we plug in the mass and velocity of object 1 and the mass and velocity of object 2 we see that: [math]\displaystyle{ m_1 v_1 + m_2 v_2 = \left( m_1 + m_2 \right) v \, }[/math] where v is the final velocity, which becomes

[math]\displaystyle{ v=\frac{m_1 v_1 + m_2 v_2}{m_1 + m_2} }[/math]

Now if we apply the concept of conservation of energy:

[math]\displaystyle{ {E} = {Q} + {W} }[/math] where E is the total energy, Q is the heat given off, and W is the work done.

If we input the various types of energy in for the total energy such as kinetic, potential, and internal we get

[math]\displaystyle{ {ΔE_k}+{ΔE_p}+{ΔU}= {Q} + {W} }[/math] where ΔE_k is the change in kinetic energy,ΔE_p is the change in potential energy, and ΔU is the change in internal energy.

Based on the concept that the two objects have initial velocities and are going to combine into one, we can assume that the work done is negligible, the process is adiabatic,and the change in potential energy is negligible. The equation is simplified to:

[math]\displaystyle{ {ΔE_k} + {ΔU} = 0 }[/math] which we can break into the initial and final components to get: [math]\displaystyle{ {ΔU} = -({K_{final}} - ({K_{initial,1}} + {K_{initial,2}})) }[/math]

Kinetic Energy for objects that have a velocity smaller than the speed of light is defined as [math]\displaystyle{ \frac{1}{2}{mv^2} }[/math], so putting in the values for mass and velocity we get that:

[math]\displaystyle{ {ΔU} = \frac{1}{2}{(m_1 v_1 +m_2 v_2)^2}{m_1+m_2} - (\frac{1}{2}{m_1 (v_1)^2} + \frac{1}{2}{m_2 (v_2)^2}) }[/math]

A Computational Model

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