Interactions of Momentum and Energy Principles: Difference between revisions
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''Ef=Ei+W'' | ''Ef=Ei+W'' | ||
''Mc^c+KM+mc^2+Km+Uf=Mc^2+KM+mc^2+Km+Ui+W'' | ''Mc^c+KM+mc^2+Km+Uf=Mc^2+KM+mc^2+Km+Ui+W'' | ||
''Km+Uf=Km+Ui+0 | |||
== | ((1/2)mv^2)+(-GMm/r)=((1/2)mv^2)+(-GMm/r)'' | ||
= | ''GM((1/r)-(1/r))=(1/2)(v^2-v^2)'' | ||
''M=2e16 kg'' | |||
==Connectedness== | ==Connectedness== | ||
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#How is it connected to your major? | #How is it connected to your major? | ||
#Is there an interesting industrial application? | #Is there an interesting industrial application? | ||
==History== | ==History== | ||
Revision as of 22:08, 5 December 2015
Created by Anya Kohnke
The Main Idea
When looking at the Momentum and Energy Principles, it is easy to find connections in the ways they are used. Both make it possible to predict and explain a range of real-world phenomena. These principles are so useful because they apply in every situation no matter the circumstances. The two principles can be used in conjunction with each other and to solve for the same quantities based on what information is provided.
The Momentum Principle restates and extends Newton's first law of motion to say that the change in momentum of a system is equal to the net force acting on the system times the duration of the interaction.
The Energy Principle states that the energy inputs from the surroundings may be positive or negative, corresponding to flows of energy from surroundings to system or from system to surroundings.
Both principles are fundamental principles because: They apply to every possible system, no matter how large or small or fast the system is. They are true for any kind of interaction. They relate an effect to a cause.
A Mathematical Model
The Momentum Principle is modeled dP=Fnet*dt
The Energy Principle is modeled dE=Wsurr=Fnet*dx
Examples
A robot spacecraft lands on an asteroid, picks up a sample, and blasts off to return to Earth; its total mass is 1500 kg. When it is 200 km from the center of the asteroid, its speed is 5 m/s and the rockets are turned off. At the moment when it has coasted to a distance 500 km from the center of the asteroid, its speed has decreased to 4.1 m/s. Calculate the mass of the asteroid.
Initial state: Rockets off, 5 m/s, 200 km from center of asteroid. Asteroid at rest. Final state: Speed 4.1 m/s, 500 km for center of asteroid.
Ef=Ei+W Mc^c+KM+mc^2+Km+Uf=Mc^2+KM+mc^2+Km+Ui+W Km+Uf=Km+Ui+0 ((1/2)mv^2)+(-GMm/r)=((1/2)mv^2)+(-GMm/r) GM((1/r)-(1/r))=(1/2)(v^2-v^2) M=2e16 kg
Connectedness
- How is this topic connected to something that you are interested in?
- How is it connected to your major?
- Is there an interesting industrial application?
History
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.
See also
Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?
Further reading
Books, Articles or other print media on this topic
External links
References
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