Collisions: Difference between revisions
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''The combined momentum of Rock 3' and the Chunk is <330, 360, 0>kg*m/s'' | ''The combined momentum of Rock 3' and the Chunk is <330, 360, 0>kg*m/s'' | ||
'''Later Rock 3' is observed moving with velocity ( | '''Later Rock 3' is observed moving with velocity (3,5,2), what is the velocity of the 15kg chunk?''' | ||
<code> | |||
Now we know the momentum of Rock 3' plus the chunk, AND we know the velocity and mass of Rock 3' | |||
pRock3Prime = m3f*vector(3,5,2) #calculate the momentum of Rock3' | |||
pChunk = pOfRock3PrimeAndChunk - pRock3Prime #calculate the momentum of the chunk | |||
chunk.v = pChunk/chunk.m #calculate the final velocity of the chunk | |||
</code> | |||
"The velocity of the chunk is <7, -1, -10>" | |||
Revision as of 18:18, 17 April 2016
SECOND EDIT BY SUNGJAE HYUN IN 2016-04-16 ADDITIONS MADE BY (currently in progress, adding computational model and difficult problem) Sam Webster 4-17-16
This topic covers Collisions, a comprehensive way to combine the Momentum and Energy Principles.
The Main Idea
Collisions are special types of contact interactions between objects. From a physics standpoint, collisions are a way to combine the Momentum and Energy Principles. In the case of collisions, if we choose a system of the two objects interacting, the change in momentum of the system and the change in energy of the system are both zero. With this in mind, calculations with collisions become very simple. We are able to choose a system of only the two objects (excluding external forces such as the Earth's gravity) because the collision takes place during such a short time that the external forces have a negligible effect. There are two types of collisions, Elastic Collisions and Inelastic Collisions.
A Mathematical Model
[math]\displaystyle{ {E}_{f} = {E}_{i} }[/math] where [math]\displaystyle{ {E}_{f} }[/math] is the total final energy of the system and [math]\displaystyle{ {E}_{i} }[/math] is the total initial energy of the system.
[math]\displaystyle{ {p}_{f} = {p}_{i} }[/math] where [math]\displaystyle{ {p}_{f} }[/math] is the total final momentum of the system and [math]\displaystyle{ {p}_{i} }[/math] is the total initial momentum of the system.
A Computational Model
The following situation was used for this model created using python:
Two objects are initially moving towards a third stationary object. Object 1 (in red) at position (-10,0,-2)m has a mass of 2kg and velocity (10,0,2)m/s. Object 2 (in blue) at position (0,6,3)m has a mass of 4kg and velocity (0,-6,3)m/s. Object 3 (in orange) at the origin has a mass of 5kg. The objects collide at the origin and after the collision it is observed that object 1 has embedded in object 3 (hence it is no longer visible in the model) and the combined object moves with velocity (5,-6,0)m/s (This is an example of a Maximally Inelastic Collision). The final velocity of object 2 is calculated and used in the rest of the simulation. (NOTE: the white sphere visible after the collision represents the origin to add dimension to the model and the delay during the collision is there to emphasis when and where the collision happens. Also use the link below the model for a more detailed explanation of the calculations and concepts.).
Check out the code used for the simulation at [1]. The code is commented pretty heavily (but it does assume some knowledge of python and python animations) in hopes that future students can modify some of the variables to experiment with creating different results.
Examples
Be sure to show all steps in your solution and include diagrams whenever possible
Simple
Example 1) A 0.5 kg soccer ball is moving with a speed of 5 m/s directly toward to 0.7 kg basket ball which is at rest. When two balls collide and stick together what will their final velocity be?
___
m1 = 0.5 kg, v1 init = 5 m/s, m2 = 0.7 kg, v2 init = 0 m/s
So m1 * v1 + m2 * + v2 = (m1 + m2) * vfinal
LHS = 0.5 * 5 + 0.7 * 0 = 2.5 kg*m/s RHS = (0.5 + 0.7) * vfinal = 1.2 * vfinal
LHS = RHS in inelastic collision
2.5 = 1.2 * vfinal
vfinal = 2.5 / 1.2 = 2.08333
Thus, the final velocity is 2.08 m/s. Since the two balls stick together, this is an example of a Maximally Inelastic Collision.
Middling
Example 2) A bullet of 50 caliber machine gun is 42 grams. It strikes a wooden target block of mass 10 kg stationed on a friction-less surface. The wooden block gains velocity of 1.8 m/s after being embedded with the bullet. What was the velocity of the bullet before it collided with the target?
m1 = 42/1000 = 0.042 kg, v1 init = ?, m2 = 10 kg, v2 init = 0, mfinal(m1+m2) = 0.042kg + 10kg, vfinal = 1.8 m/s
m1 * v1 init + m2 * v2 init = (m1 + m2) * vfinal
0.042 kg * v1 init = (0.042 + 10) * 1.8 m/s v1 init = 18.0756 / 0.042 = 430.37 m/s
Final Answer: The bullet's speed is 430.37 m/s.
Difficult
Example 3) Two rocks in space are approaching a third stationary rock. Rock 1 has mass 30kg moves with velocity (13,-10,-2)m/s. Rock 2 has mass 60kg and moves with velocity (-3,23,3)m/s. Rock 3 has mass 35kg and is stationary. The rocks collide at rock 3's location. After the collision it is observed that Rock 1 has embedded into Rock 3, but a chunk of mass 15kg has broken off of the combined rock, Rock 3'. It is also noticed that Rock 2 is now moving with velocity (-2,12,2)m/s. (NOTE: due to the difficulty and use of three dimensions it is suggested to use a computer to solve this problem. Therefore the sample solution will involve code, but conceptually everything remains the same. Additionally some code is omitted for the sake of saving space, but the important calculations are included. See the entire code at . . . )
First determine the momentum of Rock 3' plus the momentum of the 15kg chunk.
Having defined the rocks as o1, o2, and o3 respectively, and defined there initial masses and velocities to calculate their individual momenta
calculated the total momentum of the system by adding
totalP = o1.p+o2.p+o3.p #total momentum of the system
Next update the o1, o2 and o3 objects with the information observed after the collosions
mChunk = 15 # in kg
m1f = 0 #final mass object 1 in kg
m2f = 60 #final mass object 2 in kg
v2f = vector(-2,12,2) #final elocity object 2 in m/s
m3f = o1.m + o2.m - mChunk #final mass object 3 in kg
create a new sphere object with mass 15kg (code omitted)
calculate the final momentum of rock 2
o2.p = o2.v*o2.m
finally determine the combined momentum of rock 3' and the chunk using the momentum principle
pOfRock3PrimeAndChunk = totalP - o2.p #for now we are only calculating the combined momentum of rock 3' and the chunk
The combined momentum of Rock 3' and the Chunk is <330, 360, 0>kg*m/s
Later Rock 3' is observed moving with velocity (3,5,2), what is the velocity of the 15kg chunk?
Now we know the momentum of Rock 3' plus the chunk, AND we know the velocity and mass of Rock 3'
pRock3Prime = m3f*vector(3,5,2) #calculate the momentum of Rock3'
pChunk = pOfRock3PrimeAndChunk - pRock3Prime #calculate the momentum of the chunk
chunk.v = pChunk/chunk.m #calculate the final velocity of the chunk
"The velocity of the chunk is <7, -1, -10>"
With the information you know, determine the combined change in internal energy for all of the rocks.
Connectedness
Collisions are interesting phenomenons that are applicable to everyday situations. Some examples are when a bat collides with a baseball in your neighbor's backyard, two cars crashing in the highway in front of you, and two linebackers running into each-other at your local College's spring football game. Depending on the type of collision, you can predict if there will be a change in internal energy (thermal energy, chemical energy etc.). Another very interesting application of collisions is in the field of astronomy. The universe is ever-changing and we never know what might come our way. A large meteor could be flying at the Earth with a very high speed and we could use our knowledge of collisions to find out how the Earth will move after the collision, what the temperature change of the area would be, and how the rest of the Earth would be effected by the collision. By using our collision skills, we could evacuate anyone who is prone to harm during the collision.
Knowledge of collisions is also a must for many engineering majors. Industrial engineers must take in collisions when they are trying to optimize complex systems. For instance, an Industrial engineer must make sure that the bridge he or she builds can withstand the forces the cars can exert on it. Architects and Civil engineers must design houses in a certain way so that slight collisions with other objects won't completely knock the house down. And of course, Mechanical engineers and Aerospace engineers must take into account collisions when designing and maintaining mechanical systems.
History
In Rutherford's Gold Foil Experiment in 1899, Rutherford found out that the plum pudding model of the atom was inaccurate through atomic collisions.
See also
Maximally Inelastic Collision , Inelastic Collisions , Elastic Collisions, Momentum Principle, Net Force.
Further reading
Chabay, Ruth W., and Bruce A. Sherwood. Matter and Interactions. 4th ed. Vol. 1. Hoboken, NJ: Wiley, 2015. Print. Matter and Interactions.
External links
"The Collision Theory - Boundless Open Textbook." Boundless. N.p., n.d. Web. 17 Apr. 2016.
References
Chabay, Ruth W., and Bruce A. Sherwood. Matter and Interactions. 4th ed. Vol. 1. Hoboken, NJ: Wiley, 2015. Print. Matter and Interactions.