Steady State: Difference between revisions

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<br><math>\bar{v}= \frac{20.0A}{(8.342\times10^{28}/m^3) (1.60\times10^{-19}C)(3.310\times10^{-6}m^2)}</math>
<br><math>\bar{v}= \frac{20.0A}{(8.342\times10^{28}/m^3) (1.60\times10^{-19}C)(3.310\times10^{-6}m^2)}</math>
<br><math>\bar{v}= 4.53\times 10^{–4}m/s </math>
<br><math>\bar{v}= 4.53\times 10^{–4}m/s </math>
Voila!


===Difficult===
===Difficult===

Revision as of 14:18, 17 November 2016

Claimed by Amira Abadir (Fall 2016) claimed by Nyemkuna Fortingo (Spring 2016) claimed by Shirin Kale (Fall 2015)

Steady State is the term used to describe an assembled circuit in which the current and net electric field are constant and stay approximately constant for a very long time. Circuits with uniform thickness and composition can be described as steady state if charged particles move with constant current in each section of a wire in the circuit. Circuits in the steady state do not change current as a function of time.

The Main Idea

After a circuit has been assembled, it can be described as steady state if it meets the following requirements:

  • Mobile charges are moving with constant drift velocity anywhere in the circuit.
  • No excess charges accumulate anywhere in the circuit.

Although mobile charges are moving in the circuit, the drift velocities of those charges do not vary with time at any location within the circuit. Thus, the current is constant throughout the circuit. However, since current is also a function of the cross-sectional area and charge density of the wire - as shown in the equations for conventional and electron current- a steady state circuit is more specifically described as one in which the current is constant in each section of a wire with uniform thickness and composition.

Mathematical Models

Current

In a steady state circuit, there are two types of current: conventional current ([math]\displaystyle{ I }[/math]) and electron (or electric) current ([math]\displaystyle{ i }[/math]). They can be derived using the following formulas:

[math]\displaystyle{ I= \left | q \right |nA\bar{v} }[/math]
[math]\displaystyle{ i= nA\bar{v} }[/math]

Where q = charge of mobile particles, n = charge density, A = cross-sectional area of wire, and v = drift speed.

Keep in mind that drift velocity [math]\displaystyle{ \bar{v}=\mu \left | E_{applied} \right | }[/math].

Node Rule

In the steady state, each section of wire (referred to as a "node") obeys the following properties in regard to conventional and electron current:
[math]\displaystyle{ I_{in} = I_{out} }[/math]
[math]\displaystyle{ i_{in} = i_{out} }[/math]

This property, known as the Node Rule, means that current is constant throughout a steady state circuit.

A Conceptual Understanding

Because mobile charges are moving (with constant drift speed) in the circuit, there must be an applied electric field inside the wire that causes the mobile charges to move. Since there is no excess charge inside the wire, the electric field must be produced from surface charges. And because this electric field is responsible for moving the mobile charges inside the wire, the direction of the electric field at each location in the circuit must be parallel to the wire.

Once a circuit is described as being in the steady state, there are three things we know to be true. It is true that:

  • There must be a nonzero electric field in the wire.
  • The electric field has uniform magnitude throughout the wire.
  • The electric field is parallel to the wire at every location along the wire.

The electric field and current inside the wire remain constant because the electric force ([math]\displaystyle{ F = qE }[/math]), which acts on the mobile charges and allows them to move through the circuit, is canceled out by the drag force produced by the moving charged particles. Therefore, the net force is zero and by extension, acceleration is also zero.

Steady State vs. Other States

When you assume that a circuit is in steady state, you are assuming that the circuit has been assembled and connected for a long time (such that the current is constant). However, there is a process that occurs- when the circuit is first assembled- before the circuit reaches steady state. While in this Non Steady State, circuits have different properties than those in the steady state. This is also true of circuits that have reached Static Equilibrium.

The following chart compares common properties of circuits across various states: at Static Equilibrium, at Steady State, and at Non Steady States.

Static Equilibrium Steady State Non Steady State
[math]\displaystyle{ \bar{v} }[/math] [math]\displaystyle{ = 0 }[/math] [math]\displaystyle{ \neq 0 }[/math] [math]\displaystyle{ \neq 0 }[/math]
[math]\displaystyle{ \frac{d\bar{v}}{dt} }[/math] [math]\displaystyle{ = 0 }[/math] [math]\displaystyle{ = 0 }[/math] [math]\displaystyle{ \neq 0 }[/math]
[math]\displaystyle{ \sum E_{inside} }[/math] [math]\displaystyle{ = 0 }[/math] [math]\displaystyle{ \neq 0 }[/math] [math]\displaystyle{ \neq 0 }[/math]

Examples

Simple

(Example taken from the OpenStax College Physics Textbook)

Problem

Calculate the drift velocity of electrons in a 12-gauge copper wire (which has a diameter of 2.053 mm) carrying a 20.0-A current, given that there is one free electron per copper atom. The density of copper is [math]\displaystyle{ 8.80\times 10^{3} kg/m^3 }[/math].

Solution

First, calculate the density of free electrons in copper. There is one free electron per copper atom. Therefore, is the same as the number of copper atoms per [math]\displaystyle{ m^3 }[/math]. We can now find [math]\displaystyle{ n }[/math] as follows:

[math]\displaystyle{ n= \frac{1e-}{atom}\times \frac{6.02\times10^{23}atoms}{mol}\times \frac{1 mol}{63.54 g} \times \frac{1000 g}{kg} \times \frac{8.80 \times 10^3 kg}{1 m} }[/math]


[math]\displaystyle{ n= 8.342\times 10^{28}e−/m^3 }[/math]


The cross-sectional area of the wire is [math]\displaystyle{ A= \pi r^2 = \pi(2.053\times10^{−3}m^2) = 23.310 \times 10^{–6}m^2 }[/math]


Rearranging [math]\displaystyle{ I= \left | q \right |nA\bar{v} }[/math] to isolate drift velocity gives you:
[math]\displaystyle{ \bar{v}= \frac{I}{n\left |q \right |A} }[/math]
[math]\displaystyle{ \bar{v}= \frac{20.0A}{(8.342\times10^{28}/m^3) (1.60\times10^{-19}C)(3.310\times10^{-6}m^2)} }[/math]
[math]\displaystyle{ \bar{v}= 4.53\times 10^{–4}m/s }[/math]

Difficult

Problem

A circuit is in the steady state with a blah blah blah

Connectedness

As a biomedical engineer, the idea of steady state circuits is surprisingly interesting to me because the process of reaching steady state in a circuit is much like the process of maintaining homeostasis in the human body.

In the field of biochemistry, steady state can be related to cells. In ionic steady state, cells maintain different internal and external concentrations of various ionic species with the cell. If the cells are not in steady state, this means there is equilibrium. With steady state, there is not an equilibrium establishes meaning both the inner and outer cell are never equal in concentration. There are continuous ions moving within and out of the cell.

See also

References

  1. Matter and Interactions Vol. II
  2. OpenStax College Physics
  3. http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html
  4. http://people.seas.harvard.edu/~jones/es154/pages/nicetut/book2/RC.html
  5. http://ocw.mit.edu/high-school/physics/exam-prep/electric-circuits/steady-state-direct-current-circuits-batteries-resistors/8_02_spring_2007_chap7dc_circuits.pdf
  6. Formula code created with Online LaTeX Equation Editor