Potential Energy of Macroscopic Springs

An Exploration of Spring Potential Energy: Lanier Freeman and other

The Key Concept

Other: Studying macroscopic springs pulls us out of the theoretical atomic realm and into the physical world of springs. The potential energy of a spring changes as the end of the coil varies in its relative distance from the location of its affixed base.

Me: More specifically, it [potential energy] relates to one half the product of the spring constant and the change in length squared.

Terms and Definitions

A mathematical evaluation

Potential Energy - the energy stored in a body or system that results inherently from its relative position to another object

• A change in potential energy occurs when there is a change in the separation distance between the two objects.
• Gravitational potential energy relates the vertical position of an object to the surface of the Earth.

[math]\displaystyle{ \Delta U\approx \Delta mgy }[/math]

Lanier begins here and continues thru computational section:

• With spring potential energy, we relate potential energy to one half the product of the spring constant and the square of equilibrium displacement, or this:

[math]\displaystyle{ \Delta U_{spring} = \frac{1}{2}k\Delta x^2 }[/math]

• derive this, consider the following from the work-energy theorem:

[math]\displaystyle{ \Delta U_{spring} = W }[/math]

• We then look at the definition of work and infer the following:

[math]\displaystyle{ W = F\Delta x }[/math]

[math]\displaystyle{ \Delta U_{spring} = f\Delta x }[/math]

Using the mean value theorem of integrals, we simplify the nonconstant force using the mean value theorem:

[math]\displaystyle{ F_{avg} = \frac{k}{\Delta x}\int_{x_1}^{x_2}x \;dx }[/math]

[math]\displaystyle{ F_{avg} = \frac{k}{\Delta x}\cdot \frac{\Delta x^2}{2} }[/math]

[math]\displaystyle{ F_{avg} = \frac{k\Delta x}{2} }[/math]

Finally, we arrive at the above formula for spring potential energy:

[math]\displaystyle{ \Delta U_{spring} = \frac{k\Delta x}{2}\cdot \Delta x }[/math]

[math]\displaystyle{ \Delta U_{spring} = \frac{1}{2}k\Delta x^2 }[/math]

Ta-dah!

Computational Evaluation

When we plot the change in potential energy of a spring as a function of equilibrium displacement in vPython, we arrive at a parabolic model like the one in this image:

Our independent variable is the displacement of the spring from its equilibrium position, and the dependent variable is the product of the displacement squared and [math]\displaystyle{ \frac{k}{2} }[/math].

Examples

All Lanier

Simple

If a spring has a spring constant of [math]\displaystyle{ 1000 \;N/m }[/math] and is stretched [math]\displaystyle{ 10 \;cm }[/math], what is its potential energy?

[math]\displaystyle{ U = \frac{1}{2}(1000)(0.1)^2 }[/math]

[math]\displaystyle{ U = 5\;J }[/math]

Moderate

If a spring has a spring constant of [math]\displaystyle{ 1000 \;N/m }[/math] and is stretched [math]\displaystyle{ 10 \;cm }[/math] by an unknown mass, find the unknown mass.

[math]\displaystyle{ F = k\Delta x }[/math]

[math]\displaystyle{ m = \frac{k\Delta x}{g} }[/math]

[math]\displaystyle{ m = \frac{(1000)(0.1)}{9.8} }[/math]

[math]\displaystyle{ m \approx 10.204\;kg }[/math]

Difficult

If the total potential energy of a system consisting of a mass suspended on a spring is [math]\displaystyle{ 100\;J }[/math], the mass is two metres off the ground, and the mass of the object is [math]\displaystyle{ 4.081\;kg }[/math], find the spring potential energy.

[math]\displaystyle{ \sum U = U_{g}+U_s }[/math]

[math]\displaystyle{ U_s = 100-mgh }[/math]

[math]\displaystyle{ U_s = 100-(4.081)(9.8)(2) }[/math]

[math]\displaystyle{ U_s = 20 J }[/math]

Connectedness

1. How is this topic connected to something that you are interested in?

This is the first law of thermodynamics where every energy related goes around with this law, where energy is neither made or destroyed. It is very interesting how energy is just there and is transformed into other energies such as chemical energy that the food in the student center has will transform into kinetic energy when playing tennis after school.

1. How is it connected to your major?

As my major is Chemical Engineering, thermodynamics has many materials in common because of calculating the energy balances toward a reaction. The first law of thermodynamics To work out thermodynamic problems you will need to isolate a certain portion of the universe, the system, from the remainder of the universe, the surroundings.

1. Is there an interesting industrial application?

There was an interesting industrial application where we can calculate the energy required by the machine to pump the fluid out.

Lanier's Answers

1. This topic is of much interest to me because of the applications of the mean value theorem of calculus to problems dealing with potential energy--both spring and gravitational. I think this type of problem underscores the amazing power of the MVT.

2. This topic relates to being a math major for obvious reasons; it presents a basic, practical application for advanced mathematics, something that isn't seen often in my experience.

3. A silly yet decent example of industrial applications of spring applications is the way many pens are constructed: A spring of specific dimensions requiring a spring constant within a certain range is necessary to make the button on a pen work.

History

Someone else:

• William Rankinet
  • The term potential energy was introduced e, although it has links to Greek philosopher Aristotle's concept of potentiality.
  • Scottish engineer and physicist
  • links to Greek philosopher Aristotle's concept of potentiality

Lanier:

• Robert Hooke
  • Came up with Hooke's Law, which is used to find the potential energy of springs.
  • Coined the term "cell" in biology

See also

Someone else: Potential Energy Ideal Spring Spring stretch.

Further reading

Broken link from someone else that I fixed Potential Energy

References

Someone else: [1] [2]

Lanier: [3]