Moment of Inertia for a cylinder: Difference between revisions
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::<math> KE = 480900 J </math> | ::<math> KE = 480900 J </math> | ||
*Calculate the kinetic energy of a cylindrical piston rotating about its central axis given that the rod has mass 100 kg, rotational velocity of 2 m/s, and radius 5m | |||
::<math> KE = \frac{1}{2}*I*ω^2 </math> where <math> I = \frac{1}{2}*M*R^2 </math> | |||
::<math> I = \frac{1}{2}*100*5^2 </math> | |||
::<math> I = 125 kg*m^2 </math> | |||
::<math> KE = \frac{1}{2}*125 *kg*m^2*(12 \frac{m}{s})^2 </math> | |||
[[File:Screen.png]] | [[File:Screen.png]] | ||
Revision as of 22:41, 9 April 2017
This page discusses the moment of inertia specifically in the case of a cylinder or rod.
Written by Jack Corelli Edited by: Sukanya Basu Spring 2017
A Brief Overview
The Moments of Inertia can be defined as the tendency bodies are resistant to angular motion.
The moment of inertia of an object relates the mass of the object, the distance between the center of mass and the shape of rotation. In a ring, or uniform loop, the center of mass is exactly at the center of the ring, and the moment of inertia can be found by approximating the exterior ring as a single line, akin to a circle. The moment of inertia is dependent on the axis of rotation. In terms of a cylinder, the moment of inertia can be different even if the shape, volume, and mass of the cylinder are the same, given that each cylinder has different axes of revolution.
Governing Equations
Cylinders
As seen in the image above, in its simplest form, the moment of inertia can be found for a simple, constant density and shape cylinder by the equation:
[math]\displaystyle{ I = \frac{1}{2}MR^2 }[/math]
where:
- I is the moment of inertia
- M is the mass of the object being rotated
- R is the radius of the rod
This describes the moment of inertia calculated when a rod is spun about its center axis as designated by the blue line.
In the picture above, when the axis of rotation is no longer the center of the cylinder, the equations for moment of inertia change distinctly. When both the radius of the cylinder and the length of the cylinder are significant, the following equation is used.
[math]\displaystyle{ I = \frac{1}{4}MR^2 + \frac{1}{12}ML^2 }[/math] where:
- I is the moment of inertia
- M is the mass of the object being rotated
- R is the radius of the rod
- L is the length of the rod
This describes the moment of inertia calculated when the rod is spun about an axis of revolution perpendicular to its length at the center of the cylinder.
Rods
As seen in the image above, when the axis of rotation is perpendicular to the length, but is touching at the middle of the rod, then the equation would be: [math]\displaystyle{ I = \frac{1}{12}ML^2 }[/math]
where:
- I is the moment of inertia
- M is the mass of the object being rotated
- L is the length of the rod
As seen in the image above, when the axis of rotation is perpendicular to the length, but is touching at one end of the rod, then the equation would be:
[math]\displaystyle{ I = \frac{1}{3}ML^2 }[/math]
where:
- I is the moment of inertia
- M is the mass of the object being rotated
- L is the length of the rod
Examples
- Calculate the kinetic energy of a rod rotating about its end given that the rod has mass 200 kg, rotational velocity of 12 m/s, and length 15m, and radius 0.5m:
- First, the equation that equals kinetic energy in rotational motion is [math]\displaystyle{ KE = \frac{1}{2}*I*ω^2 }[/math] where [math]\displaystyle{ I = \frac{1}{4}*M*R^2 + \frac{1}{3}*M*L^2 }[/math]
- Thus, finding I: [math]\displaystyle{ I = \frac{1}{4}*200*0.5^2 + \frac{1}{3}*200*10^2 }[/math]
- [math]\displaystyle{ I = 6679.166 kg*m^2 }[/math]
- Thus [math]\displaystyle{ KE = \frac{1}{2}*6679.166 *kg*m^2*(12 \frac{m}{s})^2 }[/math]
- [math]\displaystyle{ KE = 480900 J }[/math]
- Calculate the kinetic energy of a cylindrical piston rotating about its central axis given that the rod has mass 100 kg, rotational velocity of 2 m/s, and radius 5m
- [math]\displaystyle{ KE = \frac{1}{2}*I*ω^2 }[/math] where [math]\displaystyle{ I = \frac{1}{2}*M*R^2 }[/math]
- [math]\displaystyle{ I = \frac{1}{2}*100*5^2 }[/math]
- [math]\displaystyle{ I = 125 kg*m^2 }[/math]
- [math]\displaystyle{ KE = \frac{1}{2}*125 *kg*m^2*(12 \frac{m}{s})^2 }[/math]
Connectedness
- How is this topic connected to something that you are interested in?
Moments of inertia are important because they can be used to calculate kinetic energy of solid objects. These can be used in real life scenarios like wind turbines. The calculation of the moment of inertia for the blades can be used to find the amount of force need to still or to start the motion of the blades.
See also
You can find more information in the text book about moments of inertia for different sized objects.
External links
https://en.wikipedia.org/wiki/List_of_moments_of_inertia
http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html
https://www.quora.com/What-is-an-explanation-in-simple-words-of-the-moment-of-inertia
http://www.engineeringtoolbox.com/moment-inertia-torque-d_913.html