Capacitor: Difference between revisions
| Line 20: | Line 20: | ||
<math>\ E=\frac{Q/A}{epilson_0}</math> One plate has charge <math>\ +Q</math> and other plate has charge <math>\ -Q</math>; each plate has area A; Direction is perpendicular to the plates. Assumption: separation between capacitor is very small compared to the area of a plate. | <math>\ E=\frac{Q/A}{epilson_0}</math> One plate has charge <math>\ +Q</math> and other plate has charge <math>\ -Q</math>; each plate has area A; Direction is perpendicular to the plates. Assumption: separation between capacitor is very small compared to the area of a plate. | ||
Fringe Field (just outside the plates near center of disk) | '''Fringe Field (just outside the plates near center of disk)''' | ||
Revision as of 23:44, 18 November 2015
Short Description of Topic
Claimed by Jiwon Yom
This page is all about the Electric Field due to a Point Charge.
Electric Field
Electric Field of two uniformly charged disks: A Capacitor
The Electric Field of a Capacitor can be found by the formula:
Electric field near the center of a two-plate capacitor
[math]\displaystyle{ \ E=\frac{Q/A}{epilson_0} }[/math] One plate has charge [math]\displaystyle{ \ +Q }[/math] and other plate has charge [math]\displaystyle{ \ -Q }[/math]; each plate has area A; Direction is perpendicular to the plates. Assumption: separation between capacitor is very small compared to the area of a plate.
Fringe Field (just outside the plates near center of disk)
[math]\displaystyle{ \ E_{fringe}=\frac{Q/A}{2epilson_0}\frac{s}{R} }[/math] [math]\displaystyle{ \ s }[/math] is the separation between plates; [math]\displaystyle{ \ R }[/math] is the radius of plate