Compression or Normal Force

From Physics Book
Revision as of 16:45, 16 April 2016 by Patrycjakot (talk | contribs) (I am correcting the equations and defining variables.)
Jump to navigation Jump to search

Claimed by Hemanth Koralla

FN represents the normal force

Compression of Normal Force

The compression or also commonly known as the normal force, [math]\displaystyle{ F_n\ }[/math], is a simple fundamental concept that must be understood before attempting any contact force problem. First, it is important to understand that the normal force is NOT a kind of fundamental force such as the electric or gravitational force. It is just a force used to describe the interaction between atoms. As hinted by the name, this force simply points in the perpendicular or "normal" direction to the surface(s) that it is in contact with. The magnitude of this normal force often equal to the weight of the object, however,

Understanding information about the normal force on an object can also help . The approximate force of friction is the static friction coefficient multiplied by this normal force.

Equations

The formula for calculating the normal force at an angle is:

[math]\displaystyle{ F_n = mg \cos(\theta) }[/math]
[math]\displaystyle{ F_n }[/math] is the normal force present in the system
[math]\displaystyle{ m }[/math] is the mass of the system
[math]\displaystyle{ g }[/math] is a constant value for the force due to gravity and is equivalent to 9.8 [math]\displaystyle{ m/s^2 }[/math]
[math]\displaystyle{ \theta }[/math] is the angle of the incline (

The normal force of an object (such as a block) on an inclined plane must be separated into parallel and perpendicular components. This results in two separate equations for the normal force on the object.

Perpendicular component of normal force:
[math]\displaystyle{ F_n = mgcos(\theta) }[/math]
[math]\displaystyle{ m }[/math] is the mass of the object
[math]\displaystyle{ g }[/math] is the force of gravity and is equivalent to [math]\displaystyle{ 9.8 m/s^2 }[/math]
[math]\displaystyle{ \theta }[/math] is the angle of the incline
Parallel component of normal force (with no friction present):
[math]\displaystyle{ F_n = mgsin(\theta) }[/math]
[math]\displaystyle{ m }[/math] is the mass of the object
[math]\displaystyle{ g }[/math] is the force of gravity and is equivalent to [math]\displaystyle{ 9.8 m/s^2 }[/math]
[math]\displaystyle{ \theta }[/math] is the angle of the incline

The formula for calculating the force of friction using this normal force when an object is on an inclined plane is:

[math]\displaystyle{ F_f (static) = \mu_k F_n }[/math]
[math]\displaystyle{ = \mu_k (mg \cos(\theta)) }[/math]

Examples

Time for a few examples:

Simple

Example 1

On the image to the left (Example 1), there is a 7 kilogram block resting on top a flat table. Find the normal force, [math]\displaystyle{ F_n\ }[/math], that is being exerted on the block. The force of gravity is 9.8 N/kg.




Answer

[math]\displaystyle{ F_n = mgcos(\theta)  }[/math]
In this example, theta will be 90 since the normal force is perpendicular to the surface that it is resting on, thus 90 degrees. 
Now we can plug into our formula: 
m = 7kg
g = 9.8 N/kg
theta = 90
Fn = (7 kg)(9.8 N/kg)cos(90)
 = 68.6 N

Middling

Example 2
Example 2

In Example 2 (the figure to the right), the 14 kg block is lying stationary on a plane that is inclined 48 degrees. Find the normal force perpendicular to the block on the incline. The force of gravity is 9.8 N/kg.



Answer

Because this problem asks for the normal force on an inclined plane, it is important to break up the normal force into components: Given:

m = 14 kg
g = 9.8 N/kg
theta = 48

Using trigonometry, it is seen that the cosine trig identity correlates to

Fn = mgcos(theta) 
Fn = (14 kg)(9.8 N/kg)cos(48)
 = 91.805 N

Connectedness

This force is pretty important to understand because it explains the fundamental reason for why gravity doesn't keep pulling us down and explains this not-so-apparent force that is acting on an object. It helps explain why we don't keep falling into the Earth. The application of the normal force can be seen in many industrial situations. It must be taken into account when creating any free body diagram or any construction.

History

Error creating thumbnail: sh: /usr/bin/convert: No such file or directory Error code: 127
Sir Issac Newton

The normal force a direct application of Newton's Third Law of Motion. As you probably know, Sir Issac Newton was famous scientist from England who roamed the Earth from 1643 to 1727. His work in math and physics set the stage for many of the principles and theories that we have today. His main work, the Philosophiae Naturalis Principia Mathematic, discussed the many of his theories about physics and stated his three laws of motion. You can find even more information about him under the Notable Scientists tab.

See also

External links

http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html

http://www.physicsclassroom.com/class/newtlaws/Lesson-2/Types-of-Forces

https://www.physics.uoguelph.ca/tutorials/fbd/FBD3.htm

References

Information: https://en.wikipedia.org/wiki/Normal_force

http://www.sparknotes.com/physics/dynamics/newtonapplications/section1.rhtml

http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/thereq.html


Images: https://en.wikipedia.org/wiki/Normal_force#/media/File:Friction_relative_to_normal_force_(diagram).png

http://www.fromoldbooks.org/Aubrey-HistoryOfEngland-Vol3/pages/vol3-401-Sir-Isaac-Newton/

http://www.sparknotes.com/physics/dynamics/newtonapplications/section1.rhtml