Point Charge
This page is all about the Electric Field due to a Point Charge.
Electric Field
A Work In Progress by Brandon Weiner: bweiner6 (talk)
A Mathematical Model of Electric Field due to Point Charge
The Electric Field of a Point Charge can be found by the formula:
[math]\displaystyle{ \vec E=\frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} \hat r,\text{where } \frac{1}{4 \pi \epsilon_0 } \text{is approximately } 9*10^{9} \text{, q is the charge of the particle, r is the magnitude of the distance} \text{ between the point charge and the observation point, and } }[/math] [math]\displaystyle{ \hat r \text { is the direction of the distance from} \text{the point charge to the observation point.} \text{This equation is also called Coulomb's Law. } }[/math]
A Computational Model
Here is a link to some code which shows the Electric Field due to an Proton at different points.
<html> <iframe src="https://trinket.io/embed/glowscript/cf036f65f7?start=result" width="100%" height="600" frameborder="0" marginwidth="0" marginheight="0" allowfullscreen></iframe> </html>
Examples
Be sure to show all steps in your solution and include diagrams whenever possible
Simple
Problem 1: There is a proton at <1,2,3>. Calculate the electric field at <2,-1,3>.
Step 1: Find [math]\displaystyle{ \hat r }[/math]
Find [math]\displaystyle{ \vec r_{obs} - \vec r_{proton} (\lt 2,-1,3\gt - \lt 1,2,3\gt = \lt 1,-3,0\gt ) }[/math]
Calculate the magnitude of r. ([math]\displaystyle{ \sqrt{1^2+(-3)^2+0^2}=\sqrt{10} }[/math]
From r, find the unit vector [math]\displaystyle{ \hat{r}. }[/math] [math]\displaystyle{ \lt \frac{1}{\sqrt{10}},\frac{-3}{\sqrt{10}},\frac{0}{\sqrt{10}}\gt }[/math]
Step 2: Find the magnitude of the Electric Field
[math]\displaystyle{ E= \frac{1}{4 \pi \epsilon_0 } \frac{q}{r^2} = \frac{1}{4 \pi \epsilon_0 } \frac{1.6 * 10^{-19}}{10} }[/math]
Step 3: Multiply the magnitude by [math]\displaystyle{ \hat{r} }[/math] to find the Electric Field
E= [math]\displaystyle{ \frac{1}{4 \pi \epsilon_0 } \frac{1.6 * 10^{-19}}{10}*\lt \frac{1}{\sqrt{10}},\frac{-3}{\sqrt{10}},\frac{0}{\sqrt{10}}\gt =\lt 4.554*10^{-11},-1.366*10^{-10},0\gt N/C }[/math]
Middling
Difficult
Connectedness
- How is this topic connected to something that you are interested in?
I am very interested in the idea of forces and how objects interact with each other. After you calculate the Electric Filed you can easily find the Electric Force on particle exerts on another.
- How is it connected to your major?
I am a CompE major and so Electric Fields have to do with my major because when you integrate them with respect to dL, and swap the sign, you get potential difference(voltage), which is very important in circuits. As ECE majors take circuits classes, this topic is relevant to me.
- Is there an interesting industrial application?
An interesting application is that electric fields of point charges can be used to find forces. Then you can predict the motion of various particles by the forces acting on them.
History
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.
See also
Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?
Electric Field More general ideas about electric fields
Electric Force One application of electric fields due to point charges deals with finding electric force
Further reading
Books, Articles or other print media on this topic
External links
Internet resources on this topic
Some more information : http://hyperphysics.phy-astr.gsu.edu/hbase/electric/epoint.html
References
Matter and Interactions Vol. II