Newton's Third Law of Motion

claimed by Karan Shah

Newton's Third Law Explained

Main Idea

Newton’s Third Law of Motion describes a push or pull that acts on an object as a result of its interaction with another object. According to this law for every action there is an equal and opposite re-action. This means that for every force there is a reaction force that is equal in size, but opposite in direction. Meaning that when an object 1 pushes another object 2 then object 1 gets pushed back with equal force but in the opposite direction.

If you push an object with 100N it will push back on you with equal but opposite force.

The third law of motion is also referred to as the action-reaction law because both objects are part of a single interaction and neither force can exist without the other. An important concept to remember about Newton's Third Law of Motion is that the two forces are of the same type. For example, when you throw a ball in the sky the Earth exerts a gravitational force on the ball and the ball also exerts a

The canon pushes the canon ball forward and the canon pushes the canon back with equal force.

gravitational force that is equal in magnitude and opposite in direction on the earth. Another example, that can sum up the concept of Newton's Third Law is when you walk. When you push down upon the ground and ground pushes with the same force upward. Similarly, the tires of a car push against the road while the road pushes back on the tires.

Mathematically Formula to describe Newton's Third Law

Examples

Here are some problems regarding Newton's Third Law.

Simple

Question

Simple Example

Car B is stopped at a red light. The brakes in Car A have failed and Car A is coming towards Car B at 60 kmh. Car B then runs into the back of Car A, What can be said about the force on Car A on Car B and the force on Car B on Car A?

Answer

B exerts the same amount of force on A as A exerts on B. 
Just the direction of both the forces will be in the opposite direction.

MIddle

Question

Blocks with masses of 1 kg, 2 kg, and 3 kg are lined up in a row on a frictionless table. All three are pushed forward by a 8 N force applied to the 1 kg block. (a) How much force does the 2 kg block exert on the 3 kg block? (b) How much force does the 2 kg block exert on the 1 kg block?

Answer

(a) Find the Acceleration of the Whole Object:

Total Mass: 6kg

8 = (6) a 

a = 8 / 6 = 1.33 m/s^2

Total Acceleration: 1.33 m/s^2 (Acceleration will be the same for all three blocks)

F(2 on 3) = m(3) * a  

3 * 1.33 = 3.999 N

(b) Total Acceleration: 1.33 m/s^2

Mass to push: 5 kg (Because we are also pushing the 3 kg block)

F(1 on 2) = 5 * 1.33

F(1 on 2) = 5.33 N

Difficult

Question

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Answer

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