Producing a Radiative Electric Field: Difference between revisions

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===Simple===
===Simple===
An electron at the origin is kicked in the +x direction. At an observation location (0, 1, 0), what is the direction of the radiative electric field?
===Middling===
===Middling===
===Difficult===
===Difficult===

Revision as of 15:49, 18 November 2015

This page explains the relationship between measured radiative electric field and the properties of charges in a system.

Calculating Radiative Electric Field

Maintained by Charles Kilpatrick --Ck (talk) 14:18, 18 November 2015 (EST)

A Mathematical Model

The radiative electric field can be generally modeled as [math]\displaystyle{ \vec{E}_{radiative} = \frac{1}{4 \pi \epsilon_0} \frac{-q \vec{a}_\perp}{c^2r} }[/math] where q is the charge of the accelerated particle, [math]\displaystyle{ \vec{a}_\perp }[/math] is the projected acceleration, c is the speed of light and r is the distance between the charge and the observation location.

A Computational Model

The following is a vPython model of Radiative Electric Field due to an instant of acceleration (a "kick") on a charged particle.

3d Radiation vPython Model

The acceleration vector, an initial kick in the -y direction, is represented by the yellow arrow in the center. The orange arrows seen in the model represent [math]\displaystyle{ \vec{E}_{radiative} }[/math] and the cyan arrows represent the corresponding [math]\displaystyle{ \vec{B}_{radiative} }[/math] at distance r from the particle.

Examples

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Simple

An electron at the origin is kicked in the +x direction. At an observation location (0, 1, 0), what is the direction of the radiative electric field?

Middling

Difficult

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